Problem 15
Question
Compute the Taylor series for the principal logarithm \(f(z)=\log z\) expanded about the center \(z_{0}=-1+i\).
Step-by-Step Solution
Verified Answer
The Taylor series is \(\log(-1+i) + \frac{-1-i}{2}(z + 1 - i) + \frac{1}{4}(z + 1 - i)^2 + \ldots\)
1Step 1: Identify the Function and Center
We're asked to find the Taylor series for the complex function \(f(z) = \log z\) centered at \(z_{0} = -1 + i\). A Taylor series expansion of a function \(f(z)\) about a center \(z_0\) is given by \(\sum_{n=0}^{\infty} \frac{f^{(n)}(z_0)}{n!} (z - z_0)^n\).
2Step 2: Calculate the Principal Logarithm at Center
The principal logarithm of a complex number \(z = x + yi\) is given by \(\log z = \log |z| + i\arg z\), where \(\arg z\) is the argument in the range \((-\pi, \pi]\). For \(z_0 = -1 + i\), \(|z_0| = \sqrt{2}\) and \(\arg z_0 = \frac{3\pi}{4}\). Thus, \(\log(-1+i) = \log \sqrt{2} + i\frac{3\pi}{4}\).
3Step 3: Find the Derivatives of \(f(z)\)
The first derivative of \(f(z) = \log z\) is \(f'(z) = \frac{1}{z}\). Higher-order derivatives are derivatives of \(\frac{1}{z}\): \(f''(z) = -\frac{1}{z^2}\), \(f'''(z) = \frac{2}{z^3}\), etc. The \(n\)-th derivative is \((-1)^{n-1}(n-1)!/z^n\).
4Step 4: Evaluate the Derivatives at \(z_0\)
Evaluate the derivatives at \(z_0 = -1 + i\):- \(f'(z_0) = \frac{1}{-1+i} = \frac{-1-i}{2}\),- \(f''(z_0) = -\frac{1}{(-1+i)^2} = \frac{i}{2}\),- \(f'''(z_0) = \frac{2}{(-1+i)^3} = \frac{-1+3i}{4}\), etc.
5Step 5: Construct the Taylor Series
Substitute the derivatives evaluated at \(z_0\) into the Taylor series formula:\[f(z) = \log(-1+i) + \sum_{n=1}^{\infty} \frac{(-1)^{n-1}(n-1)!}{n!} \left(\frac{1}{(-1+i)^n}\right) (z - (-1+i))^n\]Simplifying, using partial calculations for each coefficient, gives the expansion.
6Step 6: Final Expression
The Taylor series can now be expressed as:\[\log(-1+i) + \left(\frac{-1-i}{2}\right)(z + 1 - i) + \frac{1}{4}(z + 1 - i)^2 + \ldots\]
Key Concepts
Complex LogarithmComplex AnalysisDerivatives of Complex Functions
Complex Logarithm
The complex logarithm function is a fascinating extension of its real counterpart into the realm of complex numbers. When dealing with complex numbers, the logarithm is not as straightforward as its real version due to the multi-valued nature of the complex exponential function. For a complex number written in polar form, \(z = re^{i\theta}\), the principal logarithm is defined as \(\log z = \log |z| + i\arg z\). This expression consists of two parts:
- The magnitude of \(z\), represented by \(\log |z|\), which determines the distance from the origin in the complex plane.
- The angle or argument \(\arg z\), which specifies the direction from the positive real axis, confined to the interval \((-\pi, \pi]\).
Complex Analysis
Complex analysis is a branch of mathematics exploring functions of complex numbers. Differentiating functions in this domain involves understanding how the function behaves in the complex plane—a two-dimensional space incorporating both real and imaginary parts of complex numbers.
The Taylor series is a key tool in complex analysis. It provides a way to express complex functions as an infinite sum of terms calculated from the function's derivatives at a specific point, known as the center of the series. For example, if we expand \(f(z) = \log z\) about \(z_0 = -1+i\), we construct the series:
The Taylor series is a key tool in complex analysis. It provides a way to express complex functions as an infinite sum of terms calculated from the function's derivatives at a specific point, known as the center of the series. For example, if we expand \(f(z) = \log z\) about \(z_0 = -1+i\), we construct the series:
- Begin with \(f(z_0)\), the logarithm at the center.
- Add terms comprising successive derivatives of \(f(z)\), evaluated at \(z_0\), multiplied by corresponding powers of \((z - z_0)\).
Derivatives of Complex Functions
Derivatives in complex analysis extend the concept of differentiation from real numbers to complex functions. These derivatives provide critical insight into how complex functions change as their input varies. For a complex function \(f(z) = \log z\), the derivatives are derived as follows:
- The first derivative, \(f'(z) = \frac{1}{z}\), describes the rate of change of the logarithmic function at any point \(z\).
- Higher derivatives are systematic expansions based on the differentiation of \(f'(z)\). The second derivative, for example, becomes \(f''(z) = -\frac{1}{z^2}\), and follows a calculated pattern involving increments of exponent reversal for each higher order.
- The general \(n\)-th derivative formula, \((-1)^{n-1}(n-1)!/z^n\), determines all higher derivatives, providing an efficient means to calculate and construct the Taylor series.
Other exercises in this chapter
Problem 12
How are the definitions of singularity in complex analysis and asymptote in calculus different? How are they similar?
View solution Problem 13
Use the Maclaurin series for \(\sin z\) and then long division to get the Laurent series for \(\csc z\) with \(\alpha=0\).
View solution Problem 17
Let \(f\) be defined in a domain that contains the origin. The function \(f\) is said to be even if \(f(-z)=f(z)\), and it is called odd if \(f(-z)=-f(z)\). (a)
View solution Problem 18
The Z-transform. Let \(\left\\{a_{n}\right\\}\) be a sequence of complex numbers satisfying the growth condition \(\left|a_{n}\right| \leq M R^{n}\) for \(n=0,1
View solution