Problem 15
Question
Complete each solution. Determine whether each statement is true or false. a. \(\sqrt{6} i=i \sqrt{6}\) b. \(\sqrt{8} i=\sqrt{8 i}\) c. \(\sqrt{-25}=-\sqrt{25}\) d. \(-i=i\)
Step-by-Step Solution
Verified Answer
a. True; b. False; c. False; d. False.
1Step 1: Analyze Statement (a)
Consider the equation \( \sqrt{6} i = i \sqrt{6} \). Both sides of the equation involve multiplying \( i \) with \( \sqrt{6} \). The commutative property of multiplication ensures that \( a \cdot b = b \cdot a \). Therefore, this statement is true as both sides are equivalent.
2Step 2: Analyze Statement (b)
Consider the equation \( \sqrt{8} i = \sqrt{8i} \). The left side represents the imaginary number \( \sqrt{8} \cdot i \). The right side suggests taking the square root of the product \( 8i \). According to the rules of square roots, \( \sqrt{ab} eq \sqrt{a} \cdot \sqrt{b} \) for negative \( b \). Hence, this statement is false.
3Step 3: Analyze Statement (c)
Consider the equation \( \sqrt{-25} = -\sqrt{25} \). The left side represents an imaginary number \( 5i \) because \( \sqrt{-25} = \sqrt{25} \cdot \sqrt{-1} = 5i \). The right side simplifies to \(-5\), a real number. Since \( 5i eq -5 \), this statement is false.
4Step 4: Analyze Statement (d)
Consider the equation \( -i = i \). \(-i\) and \(i\) are imaginary numbers with identical magnitudes but different signs. Since they represent different numbers in the complex plane, this equation is false.
Key Concepts
Imaginary UnitSquare RootsCommutative Property of Multiplication
Imaginary Unit
In mathematics, particularly within the realm of complex numbers, the imaginary unit is a fundamental concept. It's represented by the symbol \(i\) and defined by the property that \(i^2 = -1\). This means that \(i\) is the square root of \(-1\), a concept that cannot be understood through the context of real numbers. Here's why it's essential:
- It allows for the expression and manipulation of complex numbers, which take the form \(a + bi\), where \(a\) and \(b\) are real numbers.
- The imaginary unit helps in solving equations that do not have solutions within the real number system, such as \(x^2 + 1 = 0\).
- It is crucial in various fields like engineering, physics, and computer science, where complex numbers are frequently applied.
Square Roots
Square roots are central in understanding complex numbers and many algebraic principles. The square root of a number \(x\) is such that when squared, it results in \(x\). Written as \(\sqrt{x}\), it poses unique challenges when dealing with negative numbers.
- If \(x\) is positive, \(\sqrt{x}\) represents the positive root.
- For negative numbers, we cannot determine a real number root under the conventional system, hence the introduction of the imaginary unit \(i\). For example, \(\sqrt{-25} = \sqrt{25} \cdot \sqrt{-1} = 5i\).
- It's important to note that \(\sqrt{ab} = \sqrt{a} \cdot \sqrt{b}\) only holds true when both \(a\) and \(b\) are positive or zero.
Commutative Property of Multiplication
The commutative property of multiplication is a fundamental property of arithmetic, stating that the order in which two numbers are multiplied does not affect the product. In formal terms, this property asserts that for any two numbers \(a\) and \(b\), the equation \(a \cdot b = b \cdot a\) holds.
- This property applies to all real and complex numbers, allowing flexibilities in computation and algebraic manipulation.
- It simultaneously simplifies calculations and assures that rearranging terms won't affect the end result.
- In complex numbers, this concept remains valid, such as in \(\sqrt{6}i = i\sqrt{6}\), showcasing the versatility of the property.
Other exercises in this chapter
Problem 14
Solve \(8^{2}+4^{2}=c^{2}\) and assume \(c>0 .\) Approximate to two decimal places. (EQUATION CAN'T COPY)
View solution Problem 15
Multiply and simplify. All variables represent positive real numbers. $$ \sqrt{3} \sqrt{15} $$
View solution Problem 15
Fill in the blanks. $$ \sqrt{x^{2}}=\quad \text { and } \sqrt[3]{x^{3}}= $$
View solution Problem 15
The lengths of two sides of the right triangle \(A B C\) are given. Find the length of the missing side. \(a=6 \mathrm{ft}\) and \(b=8 \mathrm{ft}\) (RIGHT TRIA
View solution