Problem 15

Question

Calculate. (If you run out of ideas, use the examples as models.) $$\int \sin 2 x \cos 3 x d x$$.

Step-by-Step Solution

Verified
Answer
The short answer is: \(\int \sin(2x)\cos(3x) dx = -\frac{1}{10}\cos(5x)+\frac{1}{2}\cos(x)+C\)
1Step 1: Apply Double-Angle Formula
We will apply the product-to-sum formulas for sine and cosine to simplify the function: \(\sin(2x)\cos(3x) = \frac{1}{2}(\sin(5x) - \sin(x))\) Step 2: Integrate Individual Trigonometric Functions
2Step 2: Integrate Individual Trigonometric Functions
Now, we need to integrate these individual sine functions with respect to \(x\): \(\int (\frac{1}{2}\sin(5x) - \frac{1}{2}\sin(x)) dx\) Step 3: Apply Fundamental Integration Rules
3Step 3: Apply Fundamental Integration Rules
We will apply the Fundamental Integration Rule \(\int \sin(ax)dx = -\frac{1}{a}\cos(ax)+C\): \(-\frac{1}{10}\cos(5x)+\frac{1}{2}\cos(x)+C\) Step 4: Write Final Answer
4Step 4: Write Final Answer
The indefinite integral is: \(-\frac{1}{10}\cos(5x)+\frac{1}{2}\cos(x)+C\)

Key Concepts

Trigonometric IntegralsProduct-to-Sum FormulasFundamental Integration Rules
Trigonometric Integrals
Trigonometric integrals are when you integrate functions that involve trigonometric expressions like sine, cosine, tangent, and others. These can sometimes seem intimidating because they often involve several steps and require knowledge of various trigonometric identities. However, understanding the basics of these integrals makes the process much easier.

With trigonometric integrals, certain strategies are often applied to simplify the expression before integrating:
  • Using identities such as double-angle or half-angle formulas.
  • Breaking down products or other complex operations into simpler forms.
In our specific problem, the integral of \( \int \sin 2x \cos 3x \ dx \) involves a product of sine and cosine functions. Knowing the right identity to use helps turn this into an easier problem.
Product-to-Sum Formulas
The product-to-sum formulas are handy for converting products of sines and cosines into sums that are easier to work with, especially when integrating. These identities allow us to transform expressions into forms that are more straightforward to integrate.

For example, one useful formula is:
  • \( \sin(A)\cos(B) = \frac{1}{2} (\sin(A+B) + \sin(A-B)) \)
Applying the product-to-sum formula simplifies the integration process. In our problem, \( \sin(2x)\cos(3x) \) is converted using:
  • \( \sin(2x)\cos(3x) = \frac{1}{2}(\sin(5x) - \sin(x)) \)
  • This step is crucial as it breaks down the product into separate functions that we can then integrate individually.
    Fundamental Integration Rules
    The fundamental integration rules are the basic building blocks for calculus, allowing us to find antiderivatives of functions. When handling trigonometric integrals, applying these rules becomes crucial.
    • The rule for integrating sine functions, \( \int \sin(ax) \, dx = -\frac{1}{a}\cos(ax) + C \), is one of the fundamental rules used here.
    Once the trigonometric product becomes a sum (thanks to the product-to-sum formula), each term like \( \sin(5x) \) and \( \sin(x) \) can be integrated separately using these rules.

    In the example, after substitution, the integration applies:
    • \( \int \sin(5x) \, dx = -\frac{1}{5}\cos(5x) + C \)
    • \( \int \sin(x) \, dx = -\cos(x) + C \)
    Combining these gives the final integral result: \(-\frac{1}{10}\cos(5x)\) and \(+\frac{1}{2}\cos(x) + C\).

    Understanding these rules allows you to tackle trigonometric integrals confidently and is essential for learning more complex integration techniques.