Problem 15
Question
An artifact originally had 16 grams of carbon-l4 present. The decay model \(\bar{A}-16 e^{-9000121}\) describes the amount of carbon- 14 present after \(t\) years. Use this model to solve Exercises \(15-16\). How many grams of carbon-14 will be present in 5715 years?
Step-by-Step Solution
Verified Answer
The amount of carbon-14 left after 5715 years is calculated as approximately 8 grams.
1Step 1: Understand the decay model
The given decay model is \(\bar{A}=16 e^{-0.000121t}\), where \(\bar{A}\) is the amount of carbon-14 left after \(t\) years.
2Step 2: Substitute the value of 't'
In this exercise, we need to calculate the amount of carbon-14 left after 5715 years, so substitute \(t=5715\) in the decay model.
3Step 3: Calculate \(\bar{A}\)
After substituting the value of \(t\) in the decay model, the equation becomes \(\bar{A}=16 e^{-0.000121 \times 5715}\). Calculating this will give us the amount of carbon-14 after 5715 years.
Key Concepts
Exponential DecayRadioactive DatingAlgebraic Modeling
Exponential Decay
Exponential decay is a process whereby the quantity of a substance decreases at a rate proportional to its current value. For substances like carbon-14, this process is described by the equation \( A(t) = A_0 e^{-kt} \), where:\
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- \( A(t) \) is the amount of substance at time \( t \),
- \( A_0 \) is the initial amount of substance,
- \( e \) is the base of the natural logarithm,
- \( k \) is the decay constant, specific to the substance,
- \( t \) is the time elapsed.
Radioactive Dating
Radioactive dating is a technique used to date materials like rocks or carbon, in which trace radioactive impurities were selectively incorporated when they formed. It relies on the principle of radioactive decay. For dating organic matter, scientists use isotopes like carbon-14, which is present in all living organisms. As living organisms take in carbon dioxide, a constant ratio of carbon-14 to carbon-12 is maintained while they are alive. Once the organism dies, it stops exchanging carbon with its environment, and the carbon-14 it contains begins to decrease through radioactive decay.To determine the age of an artifact or a sample, scientists measure the amount of carbon-14 present and use the decay rate to calculate back to the time when the organism died. This process gives us great insights into the historical and environmental record. The challenge is in accurately measuring very small changes in carbon-14 concentration over time, as this requires highly sensitive instruments and careful calibration.
Algebraic Modeling
Algebraic modeling involves translating real-world situations into mathematical models using algebraic expressions, equations or functions. In the context of carbon-14 decay, the algebraic model allows us to represent the exponential decrease of carbon-14 in an artifact over time. The given model in the exercise, \( \bar{A}=16 e^{-0.000121t} \), encapsulates all the factors affecting the decay process into a single expression.By plugging in different values of \( t \), the time since the organism's death, we can calculate the remaining amount of carbon-14, denoted by \( \bar{A} \). This approach demonstrates the power of algebra in solving real-life problems—by adopting a mathematical view of a process, we can make predictions, analyze trends, and derive meaningful insights about phenomena in the world around us. Algebraic modeling is an essential skill in various scientific disciplines, especially when dealing with processes that are governed by complex underlying principles.
Other exercises in this chapter
Problem 14
Write each equation in its equivalent logarithmic form. $$ \sqrt[3]{64}=4 $$
View solution Problem 14
In Exercises \(11-18\), graph each function by making a table of coordinates. If applicable, use a graphing utility to confirm your hand-drawn graph. $$ g(x)-\l
View solution Problem 15
In Exercises \(1-40,\) use properties of logarithms to expand each logarithmic expression as much as possible. Where possible, evaluate logarithmic expressions
View solution Problem 15
Write each equation in its equivalent logarithmic form. $$ 13^{2}=x $$
View solution