Problem 15
Question
An artifact originally had 16 grams of carbon- 14 present. The decay model \(A=16 e^{-0.000121 t}\) describes the amount of carbon- 14 present after \(t\) years. Use this model to solve Exercises \(15-16\) How many grams of carbon- 14 will be present in 5715 years?
Step-by-Step Solution
Verified Answer
The amount of carbon-14 that will be present in 5715 years is the solution of \(A = 16 e^{-0.000121 * 5715}\).
1Step 1: Understand the Decay Model
The decay model tells us about the amount of carbon-14 remaining after a period of time. In the given model, \(A=16 e^{-0.000121 t}\), where \(A\) is the amount of carbon-14 present after \(t\) years, \(16\) is the initial amount of carbon-14, the term \(e^{-0.000121 t}\) represents the exponential decay (with \(e\) being the base of natural logarithms), and the rate of decay is provided by the coefficient of \(t\) in the power of \(e\), which is \(-0.000121\).
2Step 2: Substitution
Substitute the value of \(t\) as \(5715\) into the decay model to find out the amount of carbon-14 after \(5715\) years. So, \(A = 16 e^{-0.000121 * 5715}\).
3Step 3: Perform the Calculation
Calculate the amount of carbon-14 remaining by solving the equation \(A = 16 e^{-0.000121 * 5715}\).
4Step 4: Interpret the Result
The solution gives the amount of carbon-14 that will be present in 5715 years.
Key Concepts
Exponential DecayNatural LogarithmsRadioactive Dating
Exponential Decay
Exponential decay is a process in which a quantity decreases at a rate proportional to its current value. In the context of carbon-14, this means that the amount of carbon-14 in a sample decreases by a fixed percentage each year. The decay model formula is generally given as
A = A_0e^{-kt}, where:Ais the amount of substance remaining after timet,A_0is the initial quantity of the substance,kis the decay constant specific to the substance, andeis Euler's number, the base of natural logarithms.
A=16e^{-0.000121t} to calculate how much carbon-14 remains after t years. For instance, after 5715 years, the amount of carbon-14 decreases exponentially based on this model.Natural Logarithms
Natural logarithms are mathematical functions that are inverses of exponential functions with base
For example, if we have an equation of the form
e, where e approximately equals 2.71828. It is denoted as ln(x), with x being the argument of the function. Natural logarithms are particularly useful when dealing with exponential growth or decay since they can help isolate the exponent in exponential equations. For example, if we have an equation of the form
A = A_0e^{-kt}, taking the natural logarithm of both sides can help us solve for t if we know the values of A, A_0, and k. The equation would become ln(A) = ln(A_0) - kt, which can be rearranged to find the time t when a certain amount of a substance will remain. In essence, natural logarithms provide a transformative tool to work with and understand exponential relationships in various scientific fields, including radioactive decay and financial growth models.Radioactive Dating
Radioactive dating is a technique used to date materials such as rocks or carbon, in which trace radioactive impurities were selectively incorporated when they formed. Carbon-14 dating, a form of radioactive dating, is used to estimate the age of carbon-bearing materials up to about 60,000 years old. The method is based on the principle of exponential decay of carbon-14, which has a known half-life of about 5730 years.
By measuring the amount of carbon-14 remaining in a sample and comparing it to the initial amount believed to be present at the time of death of the organism, scientists can calculate the time elapsed since the organism's death. The formula
By measuring the amount of carbon-14 remaining in a sample and comparing it to the initial amount believed to be present at the time of death of the organism, scientists can calculate the time elapsed since the organism's death. The formula
A=A_0e^{-0.000121t} is central to this process as it directly connects the remaining amount of carbon-14 (A) in the artifact with the time (t) since its last synthesis or death. Simplistically, if you found that an artifact contained half the amount of carbon-14 it started with, you could infer that it is approximately 5730 years old, the half-life of carbon-14. This is an invaluable tool in fields such as archaeology and geology for dating ancient organic remains.Other exercises in this chapter
Problem 14
Solve each exponential equation by expressing each side as a power of the same base and then equating exponents. $$ 5^{2-x}=\frac{1}{125} $$
View solution Problem 14
graph each function by making a table of coordinates. If applicable, use a graphing utility to confirm your hand-drawn graph. $$ g(x)=\left(\frac{4}{3}\right)^{
View solution Problem 15
Use properties of logarithms to expand each logarithmic expression as much as possible. Where possible, evaluate logarithmic expressions without using a calcula
View solution Problem 15
Solve each exponential equation by expressing each side as a power of the same base and then equating exponents. $$ 6^{\frac{x-3}{4}}=\sqrt{6} $$
View solution