Problem 15
Question
(a) Use the Intermediate Value Theorem to show that \(e^{x}=2-x\) has a solution in \((0,2) .\) (b) Find this solution to an accuracy of \(10^{-4}\) using the bisection search method, implemented as a spreadsheet.
Step-by-Step Solution
Verified Answer
There is a solution for the equation on the interval \((0,2)\). Using the bisection method, the approximate solution is \( x \approx 0.4428 \).
1Step 1: Define the Function
Let's define the function we are interested in:\[ f(x) = e^x - (2 - x) \]We need to find values \( x \) in the interval \( (0, 2) \) where this function equals zero.
2Step 2: Apply the Intermediate Value Theorem
First, calculate \( f(0) \) and \( f(2) \):\[ f(0) = e^0 - (2 - 0) = 1 - 2 = -1 \]\[ f(2) = e^2 - (2 - 2) = e^2 > 0 \]Since \( f(0) = -1 \) and \( f(2) > 0 \), by the Intermediate Value Theorem, there must be a root in the interval \( (0, 2) \) because the function changes sign.
3Step 3: Initial Setup for Bisection Method
For the bisection method, our initial interval is \( a = 0 \) and \( b = 2 \) with \( f(a) = -1 \) and \( f(b) > 0 \). This method will repeatedly halve the interval and select the subinterval in which the function changes sign.
4Step 4: Implement Bisection Method
1. Compute the midpoint: \( c = \frac{a + b}{2} \).2. Evaluate \( f(c) \). If \( f(c) = 0 \) or the interval \( b - a \) is sufficiently small (less than \( 10^{-4} \)), stop.3. Determine which subinterval has a sign change: - If \( f(c) \) has the same sign as \( f(a) \), set \( a = c \). - If \( f(c) \) has the same sign as \( f(b) \), set \( b = c \).4. Repeat the process until the interval is sufficiently small.
5Step 5: Spreadsheet Implementation
Create a spreadsheet with columns for \( a \), \( b \), \( c \), \( f(c) \), and the interval size \( b-a \). 1. In the first row, input \( a = 0 \), \( b = 2 \).2. Calculate \( c \) as \( \frac{a + b}{2} \) and \( f(c) \).3. Adjust \( a \) or \( b \) based on the sign of \( f(c) \) as described previously.4. Continue to fill out the spreadsheet until \( b-a < 10^{-4} \).
6Step 6: Verify the Solution
Upon completion of the spreadsheet, the value of \( c \) in the final row is the approximate root of the equation \( e^x = 2-x \) accurate to \( 10^{-4} \).
Key Concepts
Bisection MethodNumerical AnalysisRoot Finding
Bisection Method
The Bisection Method is a popular numerical technique used to find roots of continuous functions. It's based on the Intermediate Value Theorem, which guarantees that if a continuous function changes sign over an interval \(a, b\), then there is at least one root in that interval. The essence of the bisection method is to halve the interval repeatedly to zero in on a root.
Here is how it works:
The method is not only straightforward but also reliable, as it ensures convergence to a root within the specified tolerance level.
Here is how it works:
- Start with an initial interval \(a, b\) where the function changes sign.
- Calculate the midpoint \(c = \frac{a + b}{2}\).
- Evaluate the function at \(c\); if \(f(c) = 0\), you found a root.
- If not, check if the sign change occurs between \(a\) and \(c\) or \(c\) and \(b\).
- Set the new interval as the half that contains the sign change and repeat until the interval is sufficiently small, indicating proximity to a root.
The method is not only straightforward but also reliable, as it ensures convergence to a root within the specified tolerance level.
Numerical Analysis
Numerical Analysis is the field of mathematics and computer science that focuses on devising algorithms to obtain numerical solutions to mathematical problems. It is particularly useful in cases where exact solutions are impossible or impractical to determine, such as solving equations involving detailed functions like \(e^x = 2 - x\).
Key aspects to keep in mind about numerical analysis include:
In practical applications, like those tackled with spreadsheets or programming, these methods can be automated, lending great utility in scientific computations and real-world problem-solving tasks.
Key aspects to keep in mind about numerical analysis include:
- The precision of numerical methods, like the Bisection Method, which helps refine an estimate for a solution.
- Their stability, which refers to the method's sensitivity to small changes or errors in data.
- Their efficiency, which concerns how quickly and resourcefully a method reaches a solution.
In practical applications, like those tackled with spreadsheets or programming, these methods can be automated, lending great utility in scientific computations and real-world problem-solving tasks.
Root Finding
Root Finding is a type of problem in numerical analysis where we seek values of \(x\) such that a given function \(f(x)\) equals zero. This is crucial since many real-world problems can be reduced to equations that require solving for these critical points. Finding roots tells us about the behavior of functions in different contexts.
This process is vital for:
This process is vital for:
- Identifying points where a system transitions, like during zero crossing in signal processing or finding equilibrium points in applied physics.
- Solving mathematical equations that can't be rearranged to isolate \(x\) easily.
- Testing for conditions or constraints in optimization problems.
Other exercises in this chapter
Problem 15
Evaluate the trigonometric limits. $$ \lim _{x \rightarrow 0} \frac{\sin x(1-\cos x)}{x^{2}} $$
View solution Problem 15
Use the formal definition of limits to prove each statement. $$ \lim _{x \rightarrow 0} \frac{1}{x^{4}}=\infty. $$
View solution Problem 15
In Problems 15-24, find the values of \(x \in\) R for which the given functions are both defined and continuous. $$ f(x)=3 x^{4}-x^{2}+4 $$
View solution Problem 15
Evaluate the limits. $$ \lim _{x \rightarrow \infty} \frac{e^{x}}{e^{x}+2} $$
View solution