Problem 15
Question
A town has a population of 1000 people at time \(t=0\) In each of the following cases, write a formula for the population, \(P,\) of the town as a function of year \(t\) (a) The population increases by 50 people a year. (b) The population increases by \(5 \%\) a year.
Step-by-Step Solution
Verified Answer
(a) \(P(t) = 1000 + 50t\); (b) \(P(t) = 1000(1.05)^t\).
1Step 1: Identifying Population Growth Type for Case (a)
In this case, the population increases by a fixed number of people every year. This is a case of arithmetic or linear growth. The constant increase is 50 people per year.
2Step 2: Formulating the Linear Growth Equation
For linear growth, the population at any year can be expressed as \(P(t) = P_0 + rt\), where \(P_0\) is the initial population, \(r\) is the rate of increase, and \(t\) is the time in years. Here, \(P_0 = 1000\) and \(r = 50\). Thus, the formula becomes \(P(t) = 1000 + 50t\).
3Step 3: Identifying Population Growth Type for Case (b)
In this case, the population increases by a percentage each year. This is exponential growth because the population grows by a certain percentage of the current population each year.
4Step 4: Formulating the Exponential Growth Equation
For exponential growth, the population formula is \(P(t) = P_0(1+r)^t\), where \(P_0\) is the initial population, \(r\) is the rate of increase expressed as a decimal, and \(t\) is the time in years. Here, \(P_0 = 1000\) and \(r = 0.05\) (which is 5% expressed as a decimal). Thus, the formula becomes \(P(t) = 1000(1.05)^t\).
Key Concepts
Arithmetic GrowthExponential GrowthMathematical Modeling
Arithmetic Growth
Arithmetic growth, also known as linear growth, occurs when a population increases by a fixed number each year. Imagine the population of a town growing by exactly 50 people every year. This straight-line growth is easy to predict, as each year's population depends directly on the previous year's population. For arithmetic growth, we use a simple equation to represent the population over time: \[ P(t) = P_0 + rt \]Where:
- \( P(t) \) is the population at year \( t \)
- \( P_0 \) is the initial population
- \( r \) is the constant increase per year
Exponential Growth
Exponential growth is different from arithmetic growth because the population increases by a fixed percentage, not a fixed number. This creates a curve of growth that accelerates over time. Let's consider a town's population growing by 5% each year. This means that each year's growth builds on the previous year's total, creating a multiplier effect. The formula for exponential growth is: \[ P(t) = P_0(1 + r)^t \]Where:
- \( P(t) \) is the population at year \( t \)
- \( P_0 \) is the initial population
- \( r \) is the growth rate as a decimal
Mathematical Modeling
Mathematical modeling plays a critical role in understanding population growth. A model uses mathematical equations to simulate real-world scenarios. By representing population growth mathematically, we can predict future population sizes and make informed decisions or plans based on these predictions.
In the population growth scenario:
- Arithmetic models provide a straightforward prediction when increases are fixed.
- Exponential models offer a complex, yet realistic perspective when growth rates compound.
- Use arithmetic models if each year's growth is a set number.
- Use exponential models if the growth is a consistent percentage of the current population.
Other exercises in this chapter
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Solve for \(x\) using logs. $$2 e^{3 x}=4 e^{5 x}$$
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Simplify the quantities using \(m(z)=z^{2}\). $$m(z+h)-m(z)$$
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