Problem 15
Question
A recent study of the hourly wages of maintenance crew members for major airlines showed that the mean hourly salary was \(\$ 20.50,\) with a standard deviation of \(\$ 3.50 .\) If we select a crew member at random, what is the probability the crew member earns: a. Between \(\$ 20.50\) and \(\$ 24.00\) per hour? b. More than \(\$ 24.00\) per hour? c. Less than \(\$ 19.00\) per hour?
Step-by-Step Solution
Verified Answer
a. 0.3413
b. 0.1587
c. 0.3336
1Step 1: Understand the Normal Distribution
Since the hourly wages of a maintenance crew member are normally distributed, we can use the properties of the normal distribution to find probabilities. The mean is given as \( \mu = 20.50 \) and the standard deviation as \( \sigma = 3.50 \).
2Step 2: Calculate Z-scores
For any salary \( x \), the Z-score is calculated using the formula: \[ Z = \frac{x - \mu}{\sigma} \]- For \( x = 24.00 \): \( Z = \frac{24.00 - 20.50}{3.50} = 1.00 \)- For \( x = 20.50 \): \( Z = \frac{20.50 - 20.50}{3.50} = 0.00 \)- For \( x = 19.00 \): \( Z = \frac{19.00 - 20.50}{3.50} = -0.43 \)
3Step 3: Use Z-table for Probability Calculations
- Probability for between \\(20.50 and \\)24.00: \[ P(0.00 < Z < 1.00) = P(Z < 1.00) - P(Z < 0.00) \] From Z-tables: \( P(Z < 1.00) = 0.8413 \) and \( P(Z < 0.00) = 0.5000 \). So, the probability is \( 0.8413 - 0.5000 = 0.3413 \).- Probability for more than \\(24.00: \[ P(Z > 1.00) = 1 - P(Z < 1.00) \] \( P(Z > 1.00) = 1 - 0.8413 = 0.1587 \).- Probability for less than \\)19.00: \[ P(Z < -0.43) \] From Z-tables: \( P(Z < -0.43) = 0.3336 \).
Key Concepts
Z-scoreProbability CalculationsStandard Deviation
Z-score
The Z-score is a statistical measurement that describes a value's position relative to the mean of a group of values. In simpler terms, it tells you how many standard deviations the original value is away from the average. To calculate the Z-score, you can use the formula: \[ Z = \frac{x - \mu}{\sigma} \]
- \( x \) is the value you are analyzing.
- \( \mu \) is the mean of the data.
- \( \sigma \) is the standard deviation.
Probability Calculations
When dealing with normal distribution, probability calculations help us understand how likely it is for a random value to fall within a certain range or beyond a specific point.
Steps for Calculating Probability
1. **Calculate the Z-score**: This is a necessary step as it converts the variable into a standard normal variable. 2. **Use the Z-table**: The Z-table provides the probability that a standard normal variable is less than the given Z-score. For instance, from the Z-table: - Probability for \( Z < 1.00 \) is 0.8413. - Probability for \( Z < -0.43 \) is 0.3336.Interpreting the Results
- **Between Two Values**: To find the probability of earning between \\(20.50 and \\)24.00, you subtract the smaller Z-score probability from the larger one: \[ P(0.00 < Z < 1.00) = 0.8413 - 0.5000 = 0.3413 \] - **Above a Value**: For a salary more than \\(24.00, calculate: \[ P(Z > 1.00) = 1 - 0.8413 = 0.1587 \]- **Below a Value**: For less than \\)19.00, you use the Z-score directly from the Z-table: \[ P(Z < -0.43) = 0.3336 \] Probability calculations using the Z-score and the Z-table transform real-world data into insights, helping us predict outcomes based on the data's normal distribution.Standard Deviation
Standard deviation is a measure that indicates how much variation or dispersion there is from the mean in a set of data. A smaller standard deviation means that the data points are generally close to the mean, while a larger one indicates more spread out data.In our exercise, the standard deviation is \\(3.50, which is used to measure how salaries of crew members deviate from the average salary of \\)20.50. Here’s why it’s important:
- It provides a scale to quantify the volatility or risk in a dataset.
- By knowing the standard deviation, we can understand what to expect when randomly picking a data point.
Other exercises in this chapter
Problem 13
A normal population has a mean of 20.0 and a standard deviation of \(4.0 .\) a. Compute the \(z\) value associated with 25.0 . b. What proportion of the populat
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A normal population has a mean of 12.2 and a standard deviation of \(2.5 .\) a. Compute the \(z\) value associated with 14.3 . b. What proportion of the populat
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The mean of a normal distribution is 400 pounds. The standard deviation is 10 pounds. a. What is the area between 415 pounds and the mean of 400 pounds? b. What
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A normal distribution has a mean of 50 and a standard deviation of 4 a. Compute the probability of a value between 44.0 and 55.0 . b. Compute the probability of
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