Problem 15
Question
A ray of light is incident on a plane surface separating two sheets of glass with refractive indexes 1.70 and 1.58 . The angle of incidence is \(62.0^{\circ},\) and the ray originates in the glass with \(n=1.70 .\) Compute the angle of refraction.
Step-by-Step Solution
Verified Answer
The angle of refraction is approximately \(71.82^{\circ}\).
1Step 1: Understand Snell's Law
Snell's Law relates the angle of incidence and angle of refraction for a wave impinging on an interface between two media with different refractive indices, using the formula: \( n_1 \sin(\theta_1) = n_2 \sin(\theta_2) \). Here, \( n_1 = 1.70 \) and \( n_2 = 1.58 \), and \( \theta_1 = 62.0^{\circ} \). We need to find \( \theta_2 \).
2Step 2: Apply Snell's Law
Insert the given values into Snell's Law: \( 1.70 \sin(62.0^{\circ}) = 1.58 \sin(\theta_2) \). This equation will allow us to solve for \( \theta_2 \).
3Step 3: Solve for \( \sin(\theta_2) \)
Calculate \( \sin(62.0^{\circ}) \) using a calculator to find \( 0.88295 \). Then substitute back into the equation: \( 1.70 \, \times \, 0.88295 = 1.58 \sin(\theta_2) \). Simplify to find \( \sin(\theta_2) = \frac{1.70 \, \times \, 0.88295}{1.58} \approx 0.949 \).
4Step 4: Calculate \( \theta_2 \)
Now, use the inverse sine function to find \( \theta_2 \): \( \theta_2 = \arcsin(0.949) \). Using a calculator, find that \( \theta_2 \approx 71.82^{\circ} \).
5Step 5: Double-Check Calculation
Finally, re-check the insertion of values and computation to ensure accuracy, reaffirming that the angle of refraction \( \theta_2 \) is approximately \( 71.82^{\circ} \).
Key Concepts
Snell's LawRefractive IndexAngle of Refraction
Snell's Law
Snell's Law is a fundamental principle in the study of light and optics. It describes how light bends, or refracts, when it passes from one medium to another. This law is named after the Dutch mathematician, Willebrord Snellius. Snell's Law is represented by the equation:\[ n_1 \sin(\theta_1) = n_2 \sin(\theta_2) \]Here:
- \(n_1\) is the refractive index of the first medium.
- \(\theta_1\) is the angle of incidence, the angle between the incoming ray and the normal to the interface.
- \(n_2\) is the refractive index of the second medium.
- \(\theta_2\) is the angle of refraction, the angle between the refracted ray and the normal.
Refractive Index
The refractive index of a material indicates how much the speed of light is reduced inside it compared to the speed in a vacuum. It is a dimensionless number typically greater than 1. Light travels slower in materials with higher refractive indices.
- A vacuum has a refractive index of exactly 1.
- In air, the refractive index is slightly more than 1, approximately \(1.0003\).
- Glass has a higher refractive index, often ranging between 1.5 to 1.7, depending on its composition.
Angle of Refraction
The angle of refraction is the angle between the refracted light ray and the normal to the surface at the point of refraction. It is crucial in determining how much a light ray bends when passing through mediums with different refractive indices.
- When light enters a denser medium (higher refractive index), it bends towards the normal, resulting in a smaller angle of refraction compared to the angle of incidence.
- However, when light exits a denser medium into a less dense one, the angle of refraction will be larger than the angle of incidence, causing the light to bend away from the normal.
Other exercises in this chapter
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