Problem 15
Question
A radioisotope decays from \(55.9 \mathrm{~g}\) to \(6.99 \mathrm{~g}\) over a period of \(72.5\) hours. What is the half-life of the isotope?
Step-by-Step Solution
Verified Answer
The half-life of the isotope is approximately 24.1 hours.
1Step 1: Understanding Decay Formula
The formula for exponential decay is given by \( N(t) = N_0 e^{-kt} \), where \( N(t) \) is the remaining quantity of the substance at time \( t \), \( N_0 \) is the initial quantity, \( k \) is the decay constant, and \( t \) is time.
2Step 2: Set Up the Known Values
From the problem, we know that the initial quantity \( N_0 = 55.9 \) g and the remaining quantity \( N(t) = 6.99 \) g after \( t = 72.5 \) hours.
3Step 3: Solve for the Decay Constant
Using the decay formula \( N(t) = N_0 e^{-kt} \), substitute the known values: \( 6.99 = 55.9 e^{-72.5k} \). First, solve for \( e^{-72.5k} \) by dividing both sides by 55.9, resulting in \( \frac{6.99}{55.9} = e^{-72.5k} \).
4Step 4: Calculate the Decay Constant
Find \( e^{-72.5k} \) by calculating \( \frac{6.99}{55.9} \approx 0.125 \). Now, take the natural logarithm of both sides: \( \ln(0.125) = -72.5k \). Solving for \( k \), we get \( k \approx \frac{\ln(0.125)}{-72.5} \).
5Step 5: Find the Natural Logarithm
Calculate \( \ln(0.125) \approx -2.079 \). Thus, \( k \approx \frac{-2.079}{-72.5} \approx 0.0287 \).
6Step 6: Calculate the Half-Life
The half-life \( T_{1/2} \) is the time at which half of the initial amount remains, given by \( T_{1/2} = \frac{\ln(2)}{k} \). Since \( k \approx 0.0287 \), calculate \( T_{1/2} \approx \frac{0.693}{0.0287} \approx 24.1 \) hours.
Key Concepts
Radioactive DecayDecay ConstantExponential DecayNatural Logarithm
Radioactive Decay
Radioactive decay is a fundamental concept in nuclear physics and helps us understand why certain isotopes release energy over time. This process happens when the unstable nucleus of a radioisotope loses energy by emitting radiation. It's important to know that decay is random for individual nuclei, but predictable across a large number of them.
- Unlike chemical processes, radioactive decay is not affected by external conditions like temperature or pressure.
- The decay continues until a stable, non-radioactive isotope forms.
- This natural process can be used in carbon dating, medical imaging, and power generation.
Decay Constant
The decay constant, represented as \( k \), is a crucial parameter that informs us about the rate of radioactive decay of a substance. It's a measure of how quickly or slowly a substance undergoes radioactive decay. Specifically, it defines the probability of a single, unstable nucleus decaying per unit time.
Here's how it works in the decay formula:
Here's how it works in the decay formula:
- The smaller the decay constant, the slower the isotope decays, meaning a longer half-life.
- The larger the decay constant, the faster the decay, resulting in a shorter half-life.
- The decay constant is inherent to each isotope and can be calculated using the natural logarithm in the exponential decay formula.
Exponential Decay
Exponential decay describes how the amount of a radioactive substance decreases over time. This process can be visualized using the exponential decay formula \( N(t) = N_0 e^{-kt} \). Here, \( N(t) \) is the amount remaining at time \( t \), \( N_0 \) is the initial amount, and \( k \) is the decay constant.
Main characteristics of exponential decay include:
Main characteristics of exponential decay include:
- It leads to a rapid decrease initially, which gradually slows down.
- The rate of decay is proportional to the quantity remaining; the more substance present, the faster it depletes.
- In a graph of this function, you will see a downward curve approaching zero.
Natural Logarithm
The natural logarithm, denoted as \( \ln \), is a mathematical function essential in the study of exponential processes like radioactive decay. It helps to 'undo' the exponential part of exponential growth or decay equations, making it easier to solve for unknowns.
- It is based on the number \( e \), which is approximately 2.71828.
- In radioactive decay calculations, the natural logarithm helps us find the decay constant when we know the initial and remaining amounts of a substance.
- For half-life calculations, \( \ln(2) \approx 0.693 \) is often used.
Other exercises in this chapter
Problem 12
The half-life of protactinium- 234 is \(6.69\) hours. If a \(0.812 \mathrm{mg}\) sample of Pa- 239 decays for \(40.14\) hours, what mass of the isotope remains?
View solution Problem 13
\(2.86 \mathrm{~g}\) of a certain radioisotope decays to \(0.358 \mathrm{~g}\) over a period of \(22.8\) minutes. What is the half-life of the radioisotope?
View solution Problem 16
A sample of a radioisotope with a half-life of \(9.0\) hours has an activity of \(25.4 \mathrm{mCi}\) after 36 hours. What was the original activity of the samp
View solution Problem 17
What volume of a radioisotope should be given if a patient needs \(125 \mathrm{mCi}\) of a solution which contains \(45 \mathrm{mCi}\) in \(5.0 \mathrm{~mL}\) ?
View solution