Problem 15
Question
\(5-22=\) Solve the equation. $$ 4-|3 x+6|=1 $$
Step-by-Step Solution
Verified Answer
The solutions are \(x = -1\) and \(x = -3\).
1Step 1: Simplify the Equation
Start by isolating the absolute value on one side of the equation. Subtract 3 from both sides of the equation:\[4 - |3x + 6| = 1 \Rightarrow |3x + 6| = 3.\]
2Step 2: Consider Positive and Negative Scenarios
Recall that the absolute value equation \(|a| = b\) implies two scenarios: \(a = b\) and \(a = -b\). Therefore:\[3x + 6 = 3 \quad \text{or} \quad 3x + 6 = -3.\]
3Step 3: Solve for x in the Positive Scenario
Consider the positive scenario \(3x + 6 = 3\). Subtract 6 from both sides:\[3x = 3 - 6 \3x = -3.\]Divide by 3 to solve for \(x\):\[x = -1.\]
4Step 4: Solve for x in the Negative Scenario
Now consider the negative scenario \(3x + 6 = -3\). Subtract 6 from both sides:\[3x = -3 - 6 \3x = -9.\]Divide by 3 to solve for \(x\):\[x = -3.\]
5Step 5: Verify the Solutions
Substitute each solution back into the original equation to verify:- For \(x = -1\): \(|3(-1) + 6| = |3| = 3\), satisfies \(4 - 3 = 1\).- For \(x = -3\): \(|3(-3) + 6| = |-3| = 3\), satisfies \(4 - 3 = 1\).Both solutions are verified.
Key Concepts
Solving EquationsPositive and Negative ScenariosVerifying SolutionsAlgebraic Manipulation
Solving Equations
To solve absolute value equations, we first need to isolate the absolute value expression on one side of the equation. This means modifying the equation so that the terms involving the absolute value are by themselves on one side. We can achieve this by using simple arithmetic operations: addition or subtraction.
- For example, in the given equation \(4 - |3x + 6| = 1\), we start by moving terms around to isolate the absolute value: \(|3x + 6| = 3\).
- Once isolated, we can proceed by considering different scenarios that absolute values can represent, namely the positive and negative cases of the expression inside the absolute value.
Positive and Negative Scenarios
In absolute value equations, you will often encounter two scenarios to consider for the solution. This arises because the absolute value of a number could make the inner expression either positive or negative. If you have an equation of the form \(|a| = b\), there are two possible equations you must solve:
- \(a = b\), representing the situation where the expression inside is unaffected by absolute value.
- \(a = -b\), accounting for the fact that a negative expression inside the absolute value becomes positive.
- \(3x + 6 = 3\)
- \(3x + 6 = -3\)
Verifying Solutions
After deriving potential solutions from your absolute value equation, it is critical to verify them. Verification ensures your solutions satisfy the original equation, considering any transformations applied during solving. Here's how you verify:
- Substitute each potential solution back into the original equation.
- Check if both sides of the original equation remain equal when this substitution is made.
- For \(x = -1\): Substitution gives \(|-3 + 6| = 3\), leading to \(1\).
- For \(x = -3\): Substitution results in \(||-9 + 6|| = 3\), also yielding \(1\).
Algebraic Manipulation
Mastering algebraic manipulation is key to solving equations efficiently and accurately. This skill involves employing operations such as addition, subtraction, multiplication, and division to transform and simplify equations. In the context of absolute value equations, follow these steps:
- Simplify both sides of the equation wherever possible.
- Effectively isolate the absolute value expression before considering positive and negative scenarios, as shown in \(4 - |3x + 6| = 1\), leading to \(|3x + 6| = 3\).
- Carefully handle each equation derived from the absolute scenarios using arithmetic operations.
Other exercises in this chapter
Problem 14
The given equation is either linear or equivalent to a linear equation. Solve the equation. \(5 x-3=4\)
View solution Problem 15
Evaluate the expression and write the result in the form a bi. $$ (2-5 i)+(3+4 i) $$
View solution Problem 15
Solve the linear inequality. Express the solution using interval notation and graph the solution set. $$ 7-x \geq 5 $$
View solution Problem 15
Solve the equation by factoring. $$ x^{2}=5(x+100) $$
View solution