Problem 15
Question
\(15-24\) . Evaluate each expression. $$ \begin{array}{llll}{\text { (a) } \sqrt{16}} & {\text { (b) } \sqrt[4]{16}} & {\text { (c) } \sqrt[4]{\frac{1}{16}}}\end{array} $$
Step-by-Step Solution
Verified Answer
(a) 4, (b) 2, (c) \( \frac{1}{2} \)
1Step 1: Evaluate \( \sqrt{16} \)
To solve \( \sqrt{16} \), we need to find a number that when multiplied by itself gives 16. The number \( 4 \times 4 = 16 \), so \( \sqrt{16} = 4 \).
2Step 2: Evaluate \( \sqrt[4]{16} \)
To solve \( \sqrt[4]{16} \), we need to find a number that when multiplied by itself four times gives 16. The number \( 2 \times 2 \times 2 \times 2 = 16 \), so \( \sqrt[4]{16} = 2 \).
3Step 3: Evaluate \( \sqrt[4]{\frac{1}{16}} \)
To solve \( \sqrt[4]{\frac{1}{16}} \), we need to find the fourth root of \( \frac{1}{16} \). This is equivalent to \( \left(\sqrt[4]{1}\right) / \left(\sqrt[4]{16}\right) \). From the previous step, we know \( \sqrt[4]{16} = 2 \), and \( \sqrt[4]{1} = 1 \) because any root of 1 is 1. So, \( \sqrt[4]{\frac{1}{16}} = \frac{1}{2} \).
Key Concepts
Square RootFourth RootSimplifying Radicals
Square Root
A square root is essentially the inverse operation of squaring a number. To find the square root of a given number, you're looking for a value that, when multiplied by itself, produces the original number. Consider the square root symbol \( \sqrt{} \) as the guide to discovering that number.
A helpful way to think of square roots is to view them as a pair of identical factors. For instance, when evaluating \( \sqrt{16} \), you're looking for a number that when squared equals 16. The answer here is 4, since \( 4 \times 4 = 16 \).
A helpful way to think of square roots is to view them as a pair of identical factors. For instance, when evaluating \( \sqrt{16} \), you're looking for a number that when squared equals 16. The answer here is 4, since \( 4 \times 4 = 16 \).
- If the number is a perfect square, like 16, the result is a whole number.
- Not all numbers are perfect squares. For non-perfect squares, the result will be an irrational number, like \( \sqrt{2} \).
Fourth Root
The fourth root extends the concept of square roots further. Instead of finding a number that, squared, results in the original, for fourth roots, you look for a number that raised to the power of four gives the original number.
Using the fourth root, represented by \( \sqrt[4]{} \), let's evaluate \( \sqrt[4]{16} \). In this case, you're searching for a number that, when multiplied by itself four times, equals 16. The answer is 2 because \( 2 \times 2 \times 2 \times 2 = 16 \).
Using the fourth root, represented by \( \sqrt[4]{} \), let's evaluate \( \sqrt[4]{16} \). In this case, you're searching for a number that, when multiplied by itself four times, equals 16. The answer is 2 because \( 2 \times 2 \times 2 \times 2 = 16 \).
- The fourth root of 1, as in \( \sqrt[4]{1} \), is 1. Any root of 1 will always be 1.
- Finding fourth roots is useful in algebra when dealing with powers and polynomial equations.
Simplifying Radicals
Simplifying radicals involves reducing them to their simplest form. This means breaking them down into more manageable numbers, where possible.
To simplify involves repetitively breaking down a radical until no further simplification is possible. Consider \( \sqrt[4]{\frac{1}{16}} \). Here, it's equivalent to \( \frac{\sqrt[4]{1}}{\sqrt[4]{16}} \). We already know that the fourth root of 16 is 2, and the fourth root of 1 is 1. So, \( \sqrt[4]{\frac{1}{16}} = \frac{1}{2} \).
Simplifying radicals helps:
To simplify involves repetitively breaking down a radical until no further simplification is possible. Consider \( \sqrt[4]{\frac{1}{16}} \). Here, it's equivalent to \( \frac{\sqrt[4]{1}}{\sqrt[4]{16}} \). We already know that the fourth root of 16 is 2, and the fourth root of 1 is 1. So, \( \sqrt[4]{\frac{1}{16}} = \frac{1}{2} \).
Simplifying radicals helps:
- Make equations easier to solve.
- Provide clearer insights into problems involving roots and exponents.
Other exercises in this chapter
Problem 15
Simplify the rational expression. $$ \frac{12 x}{6 x^{2}} $$
View solution Problem 15
\(13-20\) . Factor the trinomial. $$ x^{2}+2 x-15 $$
View solution Problem 15
Determine whether the expression is a polynomial. If it is, state its degree. \(\frac{1}{3} x^{3}+\sqrt{5} x-\frac{1}{4}\)
View solution Problem 15
\(7-28\) Evaluate each expression. $$ \left(\frac{1}{3}\right)^{4}(-3)^{2} $$
View solution