Problem 15
Question
\(15-18\) Explain how the graph of \(g\) is obtained from the graph of \(f .\) $$ \begin{array}{l}{\text { (a) } f(x)=x^{2}, \quad g(x)=(x+2)^{2}} \\ {\text { (b) } f(x)=x^{2}, \quad g(x)=x^{2}+2}\end{array} $$
Step-by-Step Solution
Verified Answer
For (a), shift 2 units left; for (b), shift 2 units up.
1Step 1: Understand the Base Function
The base function for both parts (a) and (b) is \( f(x) = x^2 \), which is a parabola opening upwards with its vertex at the origin (0,0).
2Step 2: Analyze Part (a) Transformation
In part (a), we have \( g(x) = (x+2)^2 \). This indicates a horizontal shift. The \( +2 \) inside the parenthesis means the graph of \( f(x) = x^2 \) is shifted 2 units to the left. Thus, the vertex of the parabola moves from (0,0) to (-2,0).
3Step 3: Analyze Part (b) Transformation
In part (b), we have \( g(x) = x^2 + 2 \). This represents a vertical shift. The \( +2 \) at the end indicates the graph of \( f(x) = x^2 \) is shifted 2 units upwards. Therefore, the vertex of the parabola moves from (0,0) to (0,2).
Key Concepts
Horizontal ShiftVertical ShiftVertex of Parabola
Horizontal Shift
When transforming the graph of a parabola, a horizontal shift involves moving the graph left or right along the x-axis. This transformation is influenced by changes inside the function's parentheses.
To understand horizontal shifts, consider an example like part (a) of the exercise: from the base function \( f(x) = x^2 \) to \( g(x) = (x + 2)^2 \).
The addition of \(+2\) to \(x\) results in the entire graph moving in the opposite direction to what we might initially assume. In this case, it shifts 2 units to the **left**.
Consequently, the vertex of the original function at the point \((0,0)\) is relocated to \((-2,0)\). This movement alters the x-coordinates of all points on the graph while keeping the y-coordinates unchanged.
To understand horizontal shifts, consider an example like part (a) of the exercise: from the base function \( f(x) = x^2 \) to \( g(x) = (x + 2)^2 \).
The addition of \(+2\) to \(x\) results in the entire graph moving in the opposite direction to what we might initially assume. In this case, it shifts 2 units to the **left**.
Consequently, the vertex of the original function at the point \((0,0)\) is relocated to \((-2,0)\). This movement alters the x-coordinates of all points on the graph while keeping the y-coordinates unchanged.
- The rule is: if the function includes \( (x + a) \), shift the graph left by \(a\) units.
- If the function includes \( (x - a) \), shift the graph right by \(a\) units.
Vertical Shift
A vertical shift involves moving the graph of a function up or down along the y-axis. This occurs when a constant is added or subtracted from the entire function.
For instance, in part (b) of the exercise, the transformation of the function from \( f(x) = x^2 \) to \( g(x) = x^2 + 2 \) reflects a vertical shift.
The \(+2\) added to the function signifies a movement of the whole graph 2 units **upwards**.
This alteration changes the y-coordinate of each point on the graph while maintaining the x-coordinate, effectively raising the parabola without transforming its shape or width.
For instance, in part (b) of the exercise, the transformation of the function from \( f(x) = x^2 \) to \( g(x) = x^2 + 2 \) reflects a vertical shift.
The \(+2\) added to the function signifies a movement of the whole graph 2 units **upwards**.
This alteration changes the y-coordinate of each point on the graph while maintaining the x-coordinate, effectively raising the parabola without transforming its shape or width.
- Adding a positive constant moves the graph upwards by that many units.
- Subtracting a constant moves the graph downwards by that many units.
Vertex of Parabola
The vertex of a parabola is a pivotal point where it either reaches its highest or lowest point, depending on the orientation. Understanding movements and transformations that affect the vertex is essential.
For the base function \( f(x) = x^2 \), the vertex is at the origin \( (0,0) \).
This vertex shifts due to transformations applied to the function.
- In a horizontal shift, as seen in part (a) with \( g(x) = (x + 2)^2 \), the vertex moves horizontally to \( (-2,0) \).
- In a vertical shift, illustrated in part (b) with \( g(x) = x^2 + 2 \), the vertex moves vertically to \( (0,2) \).
- In both horizontal and vertical transformations, \( h \) is obtained by solving \( x + a = 0 \), leading to \( h = -a \) for horizontal shifts.
- The value of \( k \) comes directly from added constants to the function, defining the new y-coordinate.
Recognizing how these transformations influence the vertex helps accurately graph and understand parabolas.
For the base function \( f(x) = x^2 \), the vertex is at the origin \( (0,0) \).
This vertex shifts due to transformations applied to the function.
Impact of Horizontal and Vertical Shifts
Horizontal and vertical shifts are transformations that relocate the vertex:- In a horizontal shift, as seen in part (a) with \( g(x) = (x + 2)^2 \), the vertex moves horizontally to \( (-2,0) \).
- In a vertical shift, illustrated in part (b) with \( g(x) = x^2 + 2 \), the vertex moves vertically to \( (0,2) \).
Determining the Vertex
Use the formula \( (h,k) \), where \( h \) and \( k \) result from the shifts:- In both horizontal and vertical transformations, \( h \) is obtained by solving \( x + a = 0 \), leading to \( h = -a \) for horizontal shifts.
- The value of \( k \) comes directly from added constants to the function, defining the new y-coordinate.
Recognizing how these transformations influence the vertex helps accurately graph and understand parabolas.
Other exercises in this chapter
Problem 15
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A function is given. Determine the average rate of change of the function between the given values of the variable. $$ f(x)=3 x^{2} ; \quad x=2, x=2+h $$
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Sketch the graph of the function by first making a table of values. \(g(x)=x^{3}-8\)
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\(9-18\) m function \(f\) is given. (a) Use a graphing calculator to draw the graph of \(f .(b)\) Find the domain and range of \(f\) from the graph. $$ f(x)=\sq
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