Problem 148

Question

Photosynthesis uses 660 -nm light to convert \(\mathrm{CO}_{2}\) and \(\mathrm{H}_{2} \mathrm{O}\) into glucose and \(\mathrm{O}_{2}\). Calculate the frequency of this light.

Step-by-Step Solution

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Answer
The frequency of the 660-nm light used in photosynthesis is approximately \(4.55 \times 10^{14}\,\mathrm{Hz}\).
1Step 1: Convert the Wavelength to Meters
The given wavelength of light is in nanometers, and we need to convert it into meters to be compatible with the speed of light in meters per second. To do so, use the following conversion factor: \(1\,\mathrm{m} = 10^9\,\mathrm{nm}\). So, the wavelength in meters can be calculated as: \(\lambda_\mathrm{meters} = \cfrac{660\,\mathrm{nm}}{10^9\,\mathrm{nm/m}}\).
2Step 2: Calculate the Frequency of Light
Now that we have the wavelength in meters, we can apply the formula mentioned above to determine the frequency of the light used in photosynthesis. \(f = \cfrac{c}{\lambda_\mathrm{meters}}\), Substitute the values: \(f = \cfrac{3.0 \times 10^8\,\mathrm{m/s}}{660\,\mathrm{nm} \times 10^{-9}\,\mathrm{m/nm}}\).
3Step 3: Calculate the Final Value
Perform the calculations to obtain the frequency of light: \(f = \cfrac{3.0 \times 10^8}{660 \times 10^{-9}}\), \(f = \cfrac{3.0 \times 10^8}{6.6 \times 10^{-7}}\), \(f = 4.55 \times 10^{14}\,\mathrm{Hz}\). The frequency of the 660-nm light used in photosynthesis is approximately \(4.55 \times 10^{14}\,\mathrm{Hz}\).

Key Concepts

Wavelength and Frequency CalculationLight Energy in Biological ProcessesConversion of Units in Scientific Calculations
Wavelength and Frequency Calculation
In photosynthesis, light energy plays a crucial role, specifically the energy from 660-nm light. Understanding how to calculate the frequency of light is vital for various scientific analyses. Let's explore how we can do this.

The relationship between wavelength and frequency is expressed by the formula:
  • \( f = \cfrac{c}{\lambda} \)
where:
  • \( f \) is the frequency
  • \( c \) is the speed of light, approximately \( 3.0 \times 10^8 \,\mathrm{m/s} \)
  • \( \lambda \) is the wavelength in meters
To perform this calculation, converting the wavelength from nanometers to meters is necessary, using the conversion factor:
  • \( 1\,\mathrm{m} = 10^9\,\mathrm{nm} \)
With this conversion, substituting the values into the frequency formula yields the frequency from the given wavelength. Calculations result in a frequency of approximately \(4.55 \times 10^{14}\,\mathrm{Hz}\).

This frequency is significant in photosynthesis as it aligns with the energy requirements of the process.
Light Energy in Biological Processes
Photosynthesis is a fundamental biological process where plants convert light energy into chemical energy. This process relies heavily on light that falls within a specific range of wavelengths.

For plants, light in the range around 660 nm contributes to the energy required to transform water and carbon dioxide into glucose. The energy from light facilitates this transformation by exciting electrons, enabling various chemical reactions within the chlorophyll, which acts as a catalyst for energy capture.

This knowledge is not only crucial for understanding plant biology but also provides insights into optimizing agricultural practices. By ensuring adequate exposure to specific wavelengths of light, it can enhance plant growth and photosynthetic efficiency.
Conversion of Units in Scientific Calculations
Conversions are pivotal in scientific computations, especially when working with dimensions like length, mass, or time. Understanding how to convert units ensures accurate calculations and meaningful results.

In our wavelength and frequency calculation, converting the wavelength from nanometers to meters was crucial. Scientific equations, such as the speed of light equation, typically operate in the International System of Units (SI), where the meter is the standard unit for length.

To convert from nanometers to meters, remember that:
  • \(1\,\mathrm{m} = 10^9\,\mathrm{nm} \)
This conversion allows seamless integration into formulas using SI units. Correctly applying conversions maintains consistency and precision in solving scientific questions. It is a fundamental skill that extends beyond physics into many areas of science and engineering.