Problem 147
Question
Verify that each equation is an identity. \(\frac{\tan \theta \cot \theta}{\csc \theta}=\sin \theta\)
Step-by-Step Solution
Verified Answer
The equation is an identity because both sides simplify to \( \sin \theta \).
1Step 1: Simplify the Left Side
We start with the left side of the equation: \[ \frac{\tan \theta \cot \theta}{\csc \theta}. \]First, use the trigonometric identities: \( \tan \theta = \frac{\sin \theta}{\cos \theta} \) and \( \cot \theta = \frac{\cos \theta}{\sin \theta} \).So, \( \tan \theta \cot \theta = \frac{\sin \theta}{\cos \theta} \cdot \frac{\cos \theta}{\sin \theta} = 1 \). Thus, we have: \[ \frac{1}{\csc \theta}. \]
2Step 2: Convert Cosecant
Now, convert \( \csc \theta \) using the identity \( \csc \theta = \frac{1}{\sin \theta} \). So, the expression becomes:\[ \frac{1}{\frac{1}{\sin \theta}} = \sin \theta. \]
3Step 3: Verify Equality
The right side of the original equation is already \( \sin \theta \). Both sides of the equation simplify to \( \sin \theta \), confirming that the equation is an identity.
Key Concepts
Simplifying Trigonometric ExpressionsVerification of IdentitiesBasic Trigonometric Functions
Simplifying Trigonometric Expressions
Trigonometric expressions often appear complex at first glance. To simplify them, we frequently use trigonometric identities—essentially, relationships connecting the basic trigonometric functions such as sine, cosine, and tangent. Consider our problem where the expression starts as \( \frac{\tan \theta \cot \theta}{\csc \theta} \). To simplify this, we break down each function using identities:
- \( \tan \theta = \frac{\sin \theta}{\cos \theta} \)
- \( \cot \theta = \frac{\cos \theta}{\sin \theta} \)
Verification of Identities
Verifying trig identities involves proving that both sides of an equation are equal through logical steps. Here, we began with the expression \( \frac{\tan \theta \cot \theta}{\csc \theta} \) and simplified it to \( \sin \theta \). In the process:
- Simplify the expression using identities like \( \csc \theta = \frac{1}{\sin \theta} \).
- Result becomes \( \sin \theta \), which matches the equation's right side.
Basic Trigonometric Functions
Trigonometric functions form the backbone of trigonometry and relate the angles of triangles to side ratios. Here is a brief rundown of some of the basic functions:
- Sine (sin): Ratio of the opposite side to the hypotenuse in a right triangle.
- Cosine (cos): Ratio of the adjacent side to the hypotenuse.
- Tangent (tan): Ratio of the sine to the cosine, or opposite over adjacent sides, \( \tan \theta = \frac{\sin \theta}{\cos \theta} \).
- Cotangent (cot): Reciprocal of tangent, or adjacent over opposite, \( \cot \theta = \frac{\cos \theta}{\sin \theta} \).
- Cosecant (csc): Reciprocal of sine, \( \csc \theta = \frac{1}{\sin \theta} \).
Other exercises in this chapter
Problem 146
Simplify each expression by writing it in terms of sines and cosines, then simplify. The final answer does not have to be in terms of sine and cosine only. \(\f
View solution Problem 147
For the following exercises, verify that each equation is an identity. $$\frac{\tan \theta \cot \theta}{\csc \theta}=\sin \theta$$
View solution Problem 148
For the following exercises, verify that each equation is an identity. $$\frac{\sec ^{2} \theta}{\tan \theta}=\sec \theta \csc \theta$$
View solution Problem 148
Verify that each equation is an identity. \(\frac{\sec ^{2} \theta}{\tan \theta}=\sec \theta \csc \theta\)
View solution