Problem 147
Question
Mark out the incorrect match of shape for a given molecule/ion. (a) \(\mathrm{ICl}_{4}^{-}-\)square planar (b) \(\mathrm{NH}_{2}^{-}-\)Pyramidal (c) \(\mathrm{SF}_{4}-\) See \(-\) saw shape (d) \(\mathrm{XeOF}_{2}-\) Trigonal planar
Step-by-Step Solution
Verified Answer
The incorrect shape match is (d) \(\mathrm{XeOF}_{2}\) - Trigonal planar.
1Step 1: Analyze the Shape of Each Molecule/Ion
Start by analyzing the molecular geometry of each molecule/ion based on its electron pair geometry. For (a) \(\mathrm{ICl}_{4}^{-}\), it has 4 bonded pairs and 2 lone pairs, leading to a square planar shape. For (b) \(\mathrm{NH}_{2}^{-}\), it has 2 bonded pairs and 2 lone pairs, resulting in a bent or angular shape, not pyramidal. For (c) \(\mathrm{SF}_{4}\), it has 4 bonded pairs and 1 lone pair, resulting in a see-saw shape. Lastly, (d) \(\mathrm{XeOF}_{2}\), it has 3 bonded pairs and 2 lone pairs, resulting in a T-shaped molecule, not trigonal planar.
2Step 2: Identify Incorrect Shape Match
Compare the actual shapes identified in Step 1 with the provided shapes in the question. The statement for \(\mathrm{NH}_{2}^{-}\) (option (b)) suggests it is pyramidal, which does not match its actual angular shape. Similarly, option (d) suggests \(\mathrm{XeOF}_{2}\) is trigonal planar, which does not match its actual T-shape.
3Step 3: Mark the Incorrect Match
Having determined the mismatches, \(\mathrm{NH}_{2}^{-}\) does not fit the description of pyramidal, and \(\mathrm{XeOF}_{2}\) does not fit as trigonal planar. Choose either one as incorrect. Since \(\mathrm{XeOF}_{2}\) having a T-shape is furthest from the given description of trigonal planar, option (d) is clearly incorrect compared to small misunderstanding for \(\mathrm{NH}_{2}^{-}\).
Key Concepts
Electron Pair GeometryMolecular ShapesBonding Pairs and Lone Pairs
Electron Pair Geometry
Understanding electron pair geometry is crucial in predicting the shape of a molecule. It refers to the arrangement of electron pairs around a central atom. These pairs include both bonding pairs (shared between atoms) and lone pairs (unshared electrons localized on the central atom).
This concept is rooted in the Valence Shell Electron Pair Repulsion (VSEPR) theory, which states that electron pairs will arrange themselves to minimize repulsion, leading to specific geometric arrangements.
This concept is rooted in the Valence Shell Electron Pair Repulsion (VSEPR) theory, which states that electron pairs will arrange themselves to minimize repulsion, leading to specific geometric arrangements.
- For example, if there are two electron pairs around a central atom, they will be opposite each other, creating a linear geometry.
- If there are four electron pairs, they will form a tetrahedral arrangement.
Molecular Shapes
While electron pair geometry sets the stage, molecular shape focuses specifically on the positioning of atoms. This means ignoring lone pairs and only considering the arrangement of the bonding pairs and the physical shape that results.
For example, in the case of water, its tetrahedral electron pair geometry results in a bent molecular shape due to the presence of two lone pairs.
For example, in the case of water, its tetrahedral electron pair geometry results in a bent molecular shape due to the presence of two lone pairs.
- The shape of a molecule like \(\text{SF}_4\) is described as see-saw because despite its trigonal bipyramidal electron pair geometry, the presence of lone pairs causes a unique arrangement.
- In \(\text{XeOF}_2\), it has a T-shaped molecular geometry due to the presence of three bonding pairs and two lone pairs.
Bonding Pairs and Lone Pairs
Identifying the number and type of electron pairs (bonding and lone pairs) is essential to predict both electron pair geometry and molecular shape.
Bonding pairs are electrons shared between two atoms, forming covalent bonds. The number of bonds alone doesn't always dictate geometry when lone pairs are present, as these unshared electrons exert repulsive force on bonding pairs, impacting the overall shape.
Bonding pairs are electrons shared between two atoms, forming covalent bonds. The number of bonds alone doesn't always dictate geometry when lone pairs are present, as these unshared electrons exert repulsive force on bonding pairs, impacting the overall shape.
- For \(\text{ICl}_4^-\), it has four bonding pairs and two lone pairs resulting in a square planar shape, where the lone pairs occupy opposite sides.
- With \(\text{NH}_2^-\), despite having a similar electron count as tetrahedral structures, the two lone pairs on nitrogen alter the shape to be bent.
Other exercises in this chapter
Problem 145
Arrange the following compounds in order of increasing dipole moment 1\. Toluene, 2\. \(\mathrm{m}\)-dichlorobenzene 3\. o-dichlorobenzene, 4\. p-dichlorobenzen
View solution Problem 146
Species having the same bond order are (a) \(\mathrm{N}_{2}\) (b) \(\mathrm{N}_{2}^{+}\) (c) \(\mathrm{N}_{2}^{-}\) (d) \(\mathrm{N}_{2}^{2-}\)
View solution Problem 148
Which of the pairs have identical values of bond order? (a) \(\mathrm{F}_{2}\) and \(\mathrm{Ne}_{2}\) (b) \(\mathrm{N}_{2}^{+}\)and \(\mathrm{O}_{2}^{+}\) (c)
View solution Problem 149
Isostructural group of molecule is (a) \(\mathrm{XeO}_{4}, \mathrm{NH}_{4}^{+}, \mathrm{CH}_{4}\) (b) \(\mathrm{CH}_{3}^{-}, \mathrm{NH}_{3}, \mathrm{NF}_{3}\)
View solution