Problem 147
Question
Determine whether each statement makes sense or does not make sense, and explain your reasoning. I can check inequalities by substituting 0 for the variable: When 0 belongs to the solution set, I should obtain a true statement, and when 0 does not belong to the solution set, I should obtain a false statement.
Step-by-Step Solution
Verified Answer
The statement does not make sense because simply substituting 0 for the variable in an inequality is not sufficient to check all possible solutions of the inequality.
1Step 1: Analyze the Statement
The provided statement is about evaluating inequalities by substituting 0 for the variable. Essentially, it is suggesting that if an inequality holds true when the variable is replaced with 0, then 0 is part of the solution set. Conversely, if the inequality does not hold true, then 0 is not part of the solution set.
2Step 2: Evaluate the Logic
The logic in this statement is partly correct but not always. While it's true that if a number satisfies an inequality, it is part of the solution set, substituting only 0 for the variable to evaluate the inequality is not comprehensive enough. An inequality might hold true for non-zero numbers, negative numbers, fractions, etc. Thus, simply testing 0 is not sufficient to determine the entire solution set of an inequality.
3Step 3: Final Conclusion
So, although testing 0 in an inequality might provide some insight about the solution set, the method is overly simplified and excludes many possible solutions. Therefore, the statement does not make sense because it is misleading by implying you can determine the whole solution set from just testing the variable 0.
Key Concepts
Evaluating InequalitiesSolution SetSubstitution Method
Evaluating Inequalities
Evaluating inequalities in algebra is akin to solving puzzles. Each inequality is a statement that expresses a relationship between expressions, using symbols such as < (less than), \textgreater (greater than), \textless= (less than or equal to), and \textgreater= (greater than or equal to). The process of evaluating these inequalities involves finding all the possible values for the variable that make the inequality true.
When evaluating, we replace the variable with a number to see if we obtain a true statement. For instance, if we have the inequality \(x + 3 > 5\), substituting \(x\) with 2 would give us \(5 > 5\), which is not true. If we substitute \(x\) with 3, then \(6 > 5\), which is true. Therefore, \(x = 3\) is part of the solution set, but \(x = 2\) is not. However, we must remember that trying just a single value, such as zero, may not always reveal the full solution set, as different values can affect the inequality's truth differently.
When evaluating, we replace the variable with a number to see if we obtain a true statement. For instance, if we have the inequality \(x + 3 > 5\), substituting \(x\) with 2 would give us \(5 > 5\), which is not true. If we substitute \(x\) with 3, then \(6 > 5\), which is true. Therefore, \(x = 3\) is part of the solution set, but \(x = 2\) is not. However, we must remember that trying just a single value, such as zero, may not always reveal the full solution set, as different values can affect the inequality's truth differently.
Tips for Evaluating Inequalities
- Test multiple values for variables, including positive, negative, and fractions.
- Consider drawing a number line to visualize which values make the inequality true.
- Be mindful of 'strict' inequalities (e.g., < and >) and 'non-strict' inequalities (e.g., \textless= and \textgreater=) as they affect the solution set differently.
Solution Set
The solution set of an inequality encompasses all the values that satisfy the inequality. It answers the question: 'What are all the possible values for my variable that make this inequality true?'
Using our previous example \(x + 3 > 5\), we can determine that the solution set consists of all values greater than 2, since x=2 would make the equation equal, and we are looking for values that make it strictly greater. This means that values such as 2.5, 3, 100 are all part of the solution set.
Using our previous example \(x + 3 > 5\), we can determine that the solution set consists of all values greater than 2, since x=2 would make the equation equal, and we are looking for values that make it strictly greater. This means that values such as 2.5, 3, 100 are all part of the solution set.
Features of a Solution Set
- A solution set may be a range of numbers, a single number, or even no numbers at all (in the case of a contradiction).
- It can be represented on a number line, in set-builder notation, or in interval notation.
- Determining the solution set often requires testing a range of values and understanding the behavior of the inequality.
Substitution Method
The substitution method is a pivotal tool in algebra, especially valuable when solving systems of equations. However, it can also be applied to inequalities. The main idea is to replace a variable with a value or another expression to simplify the problem and make it more manageable.
The process of using substitution to evaluate inequalities can quickly determine whether a particular value is a part of the solution set. But there's one caveat: using the substitution method alone is not foolproof for finding all the solutions to an inequality, since inequalities may have many solutions or intervals of solutions.
The process of using substitution to evaluate inequalities can quickly determine whether a particular value is a part of the solution set. But there's one caveat: using the substitution method alone is not foolproof for finding all the solutions to an inequality, since inequalities may have many solutions or intervals of solutions.
When to Apply the Substitution Method
- Use substitution to verify if specific values are within the solution set.
- Apply it to check your work or to simplify expressions when dealing with multiple inequalities or equations.
- Keep in mind that a complete solution often requires combining substitution with other methods such as graphing or interval testing.
Other exercises in this chapter
Problem 146
Determine whether each statement makes sense or does not make sense, and explain your reasoning. I prefer interval notation over set-builder notation because it
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Each side of a square is lengthened by 3 inches. The area of this new, larger square is 64 square inches. Find the length of a side of the original square.
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Each side of a square is lengthened by 2 inches. The area of this new, larger square is 36 square inches. Find the length of a side of the original square.
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Determine whether each statement makes sense or does not make sense, and explain your reasoning. In an inequality such as \(5 x+4
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