Problem 145
Question
Use the \(\mathrm{NH}_{3}\) molecule as an example to explain the difference between molecular geometry and electron-group geometry.
Step-by-Step Solution
Verified Answer
The electron-group geometry of ammonia (\(NH_{3}\)) is tetrahedral as it accounts for all electron domains (three single bonds and one lone pair of electrons). However, the molecular geometry is trigonal pyramidal which includes only the positions of the nitrogen and hydrogen atoms and excludes non-bonding electrons.
1Step 1: Representation of ammonia molecule
Start by representing the ammonia molecule as \(NH_{3}\). This consists of one Nitrogen (N) atom and three Hydrogen (H) atoms. Nitrogen in the middle forms three single bonds with three hydrogen atoms. Nitrogen also has one lone pair of electrons remaining.
2Step 2: Defining Electron-group geometry
For identifying the electron-group geometry, all electron domains (bonding and non-bonding) should be considered. In the ammonia molecule, there are 4 electron domains: 3 from the bond with Hydrogen atoms and 1 from the lone pair of electrons. According to VSEPR theory, this describes a tetrahedral electron-group geometry.
3Step 3: Defining Molecular geometry
When we look at the molecular geometry, we only consider the atoms themselves, not the non-bonding electron pairs. In the case of ammonia, when ignoring the lone pair, the shape formed by the nitrogen and hydrogen atoms is a trigonal pyramidal not tetrahedral.
4Step 4: Comparison between Electron-group and molecular geometries
With the information above, it's clear that the electron-group geometry (tetrahedral) involves all electron domains including bonding and non-bonding. However, the molecular geometry (trigonal pyramidal) only accounts for the positioning of atoms, excluding non-bonding electrons. So the main difference is whether or not non-bonding electrons are factored into the geometry.
Key Concepts
Electron-group GeometryVSEPR TheoryLone Pair Electrons
Electron-group Geometry
When we talk about electron-group geometry, we're considering all of the regions around a central atom where electrons are most likely to be found. This includes not only the bonds formed with other atoms but also any lone pairs of electrons. For example, in the ammonia molecule \(\text{NH}_3\), nitrogen is the central atom. Here, nitrogen is bonded to three hydrogen atoms, and there's also one lone pair of electrons. Thus, there are four electron groups.
According to the Valence Shell Electron Pair Repulsion (VSEPR) theory, these electron groups arrange themselves as far apart as possible to minimize repulsion. For ammonia, this results in a tetrahedral electron-group geometry. Even though only three hydrogen atoms are visible to an observer, the lone pair also takes up space and influences the geometry in which electron groups are positioned around the central nitrogen atom.
According to the Valence Shell Electron Pair Repulsion (VSEPR) theory, these electron groups arrange themselves as far apart as possible to minimize repulsion. For ammonia, this results in a tetrahedral electron-group geometry. Even though only three hydrogen atoms are visible to an observer, the lone pair also takes up space and influences the geometry in which electron groups are positioned around the central nitrogen atom.
VSEPR Theory
VSEPR Theory, or Valence Shell Electron Pair Repulsion Theory, is pivotal in predicting the shapes of molecules. It essentially boils down to the idea that electron pairs around a central atom will arrange themselves as far apart as possible. This minimizes repulsions between electron pairs. Thus, it helps predict the 3D arrangement of atoms in a molecule.
Each pair of valence electrons, whether bonding or non-bonding, holds the same importance in shaping the molecule. For instance, in our ammonia \(\text{NH}_3\) example, the VSEPR theory suggests a shape that minimizes the repulsion between the four electron domains around the nitrogen atom. Though there are only three visible ***bonding pairs*** (each connecting Nitrogen to Hydrogen), it's crucial not to overlook the lone pair, which plays a key role in determining the final geometry. This is why understanding VSEPR is essential for grasping not just where the bonds are, but how the overall shape of a molecule comes to be.
Each pair of valence electrons, whether bonding or non-bonding, holds the same importance in shaping the molecule. For instance, in our ammonia \(\text{NH}_3\) example, the VSEPR theory suggests a shape that minimizes the repulsion between the four electron domains around the nitrogen atom. Though there are only three visible ***bonding pairs*** (each connecting Nitrogen to Hydrogen), it's crucial not to overlook the lone pair, which plays a key role in determining the final geometry. This is why understanding VSEPR is essential for grasping not just where the bonds are, but how the overall shape of a molecule comes to be.
Lone Pair Electrons
Lone pair electrons are often the invisible shapers of molecular structure. These are valence electrons that are not involved in forming chemical bonds but still occupy space around an atom. In \(\text{NH}_3\), the lone pair on nitrogen can be thought of as the unseen participant that greatly influences the molecule's shape.
While the lone pairs are not "seen" in the molecular geometry (as they are not directly connected to any other atoms), they certainly affect the angles between the bonds that are visible. In the ammonia molecule, the lone pair exerts a repulsive force that pushes the hydrogen atoms closer together, resulting in a trigonal pyramidal shape, rather than a perfect tetrahedron.
While the lone pairs are not "seen" in the molecular geometry (as they are not directly connected to any other atoms), they certainly affect the angles between the bonds that are visible. In the ammonia molecule, the lone pair exerts a repulsive force that pushes the hydrogen atoms closer together, resulting in a trigonal pyramidal shape, rather than a perfect tetrahedron.
- Lone pairs take up more space than bonding pairs.
- They exert stronger repulsions on adjacent bonds.
- In \(\text{NH}_3\), the lone pair is responsible for its signature bent away position.
Other exercises in this chapter
Problem 142
Without referring to tables or figures in the text other than the periodic table, indicate which of the following atoms, \(\mathrm{Bi}, \mathrm{S}, \mathrm{Ba},
View solution Problem 144
What is the VSEPR theory? On what physical basis is the VSEPR theory founded?
View solution Problem 146
If you have four electron pairs around a central atom, under what circumstances can you have a pyramidal molecule? Similarly, how can you have a bent molecule?
View solution Problem 147
Draw three resonance structures for the sulfine molecule, \(\mathrm{H}_{2} \mathrm{CSO}\). Do not consider ring structures.
View solution