Problem 143
Question
What mass of iron(III) chloride contains \(2.35 \times 10^{23}\) chloride ions?
Step-by-Step Solution
Verified Answer
The mass of iron(III) chloride needed is approximately 21.1 grams.
1Step 1: Determine Moles of Chloride Ions
We start by using Avogadro's number which is \[6.022 \times 10^{23}\] ions/mol. Divide the given number of chloride ions by Avogadro's number to find the moles of chloride ions:\[\text{moles of chloride ions} = \frac{2.35 \times 10^{23}}{6.022 \times 10^{23}} \approx 0.39 \text{ moles}.\]
2Step 2: Calculate Moles of Iron(III) Chloride
Iron(III) chloride, \(\text{FeCl}_3\), contains 3 chloride ions per formula unit. To find the moles of \(\text{FeCl}_3\), divide the moles of chloride ions by 3:\[\text{moles of FeCl}_3 = \frac{0.39}{3} \approx 0.13 \text{ moles}.\]
3Step 3: Calculate Mass of Iron(III) Chloride
Next, we need the molar mass of \(\text{FeCl}_3\). The atomic masses are: Fe = 55.85 u and Cl = 35.45 u. Thus:\[\text{Molar mass of FeCl}_3 = 55.85 + 3 \times 35.45 = 162.2 \text{ g/mol}.\]Now, multiply the moles of \(\text{FeCl}_3\) by its molar mass to find the mass in grams:\[\text{mass of FeCl}_3 = 0.13 \times 162.2 \approx 21.1 \text{ grams}.\]
Key Concepts
The Mole ConceptAvogadro's NumberMolar MassChemical Calculations
The Mole Concept
The mole is a fundamental concept in chemistry that represents a specific number of entities, whether these are atoms, molecules, or ions. Think of it as a way of counting by weighing. Just like a dozen represents 12 items, a mole represents a much larger number: Avogadro's number. One mole of any substance contains exactly the same number of entities, which is hugely beneficial for solving problems in chemistry where we often deal with incredibly small particles like ions and atoms. By using the mole concept, chemists can convert between the mass of a substance and the number of atoms or molecules it contains. In our exercise, when we know the number of chloride ions, the mole concept allows us to find out how many moles those ions translate into.
Avogadro's Number
Avogadro's number is a key part of the stoichiometric landscape. It is defined as exactly
6.022 × 10^{23}
entities per mole. This large number is used because atoms and molecules are extremely small, and we often deal with them in vast quantities. Avogadro’s number allows chemists to translate between microscopic-scale amounts into macroscopic-scale quantities that we can measure and understand, such as moles. In the problem at hand, Avogadro's number helps us convert a large number of chloride ions (
2.35 × 10^{23}
) into a more manageable quantity of moles. This makes subsequent calculations much more straightforward.
Molar Mass
Molar mass is the bridge between moles and grams. It is defined as the mass of one mole of a given substance—measured in grams per mole (g/mol). Every element's atomic mass, which you can find on the periodic table, contributes to the molar mass of a compound. For example,
FeCl_3
is composed of iron (Fe) and chlorine (Cl). The molar mass of
FeCl_3
is calculated by adding the atomic masses of one iron atom and three chlorine atoms, resulting in
162.2
g/mol. Once we know how many moles of
FeCl_3
we have from the earlier steps, we can easily convert this to a mass using its molar mass.
Chemical Calculations
Chemical calculations often involve conversions between different units. Here, we seamlessly moved from ions to moles, then from moles to mass. This is a typical sequence in stoichiometry, often requiring steps involving Avogadro’s number and molar mass. Here's a simplified breakdown of the calculation process used in our exercise:
- Determine moles from the number of entities using Avogadro's number.
- Account for the composition of the compound—in our case, three chloride ions per FeCl_3 unit.
- Use the molar mass to convert from moles to grams.
Other exercises in this chapter
Problem 137
What is the mass of a mole of electrons if one electron has a mass of \(9.11 \times 10^{-28} \mathrm{g} ?\)
View solution Problem 142
Determine the number of molecules of ethanol \(\left(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH}\right)\) in 47.0 \(\mathrm{g}\).
View solution Problem 146
Calculate the moles of aluminum ions present in 250.0 \(\mathrm{g}\) of aluminum oxide \(\left(\mathrm{Al}_{2} \mathrm{O}_{3}\right) .\)
View solution Problem 149
Calculate the number of sodium ions present in 25.0 \(\mathrm{g}\) of sodium chloride.
View solution