Problem 143
Question
If you are given two real numbers, explain how to determine which is the lesser.
Step-by-Step Solution
Verified Answer
To determine the lesser of two numbers, compare them. If \(x < y\), then \(x\) is less. If \(y < x\), then \(y\) is less. If \(x = y\), the numbers are equal, and neither is less.
1Step 1: Identify the Numbers
The first task is to identify the two real numbers that are to be compared. Let's denote these numbers as \(x\) and \(y\). They can have any real value.
2Step 2: Compare the Numbers
The next step is to compare the two numbers. If \(x < y\), then \(x\) is the lesser number. If \(y < x\), then \(y\) is the lesser number. If \(x = y\), both numbers are equal, and neither is lesser.
3Step 3: Provide the Answer
Use the result from step 2 to provide the answer, stating which number is the lesser of the two, or if they are equal.
Other exercises in this chapter
Problem 143
Use the distributive property to multiply: $$2 x^{4}\left(8 x^{4}+3 x\right)$$
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Determine whether each statement is true or false. If the statement is false, make the necessary change(s) to produce a true statement. $$\left(4 \times 10^{3}\
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Factor the numerator and the denominator. Then simplify by dividing out the common factor in the numerator and the denominator. $$\frac{x^{2}+6 x+5}{x^{2}-25}$$
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Simplify and express the answer in descending powers of \(x\) : $$2 x\left(x^{2}+4 x+5\right)+3\left(x^{2}+4 x+5\right)$$
View solution