Problem 143
Question
If \(P(A \mid B)=0.3, P(B)=0.8,\) and \(P(A)=0.3,\) are the events \(B\) and the complement of \(A\) independent?
Step-by-Step Solution
Verified Answer
Yes, the events \(B\) and \(A^c\) are independent.
1Step 1: Understand the Complement Rule
The complement of event \(A\), denoted as \(A^c\), represents the event that \(A\) does not occur. Given that \(P(A) = 0.3\), the probability of \(A^c\) is \(P(A^c) = 1 - P(A) = 1 - 0.3 = 0.7\). We will use this in conjunction with \(P(B)\) to check for independence.
2Step 2: Recall Definition of Independence
Two events \(B\) and \(A^c\) are considered independent if \(P(B) \times P(A^c) = P(B \cap A^c)\). We need to verify this equality to determine if \(B\) and \(A^c\) are independent.
3Step 3: Use Bayes' Theorem for Probability of Intersection
We know \(P(A \,|\, B) = 0.3\). Using the formula for conditional probability, \[P(A \,|\, B) = \frac{P(A \cap B)}{P(B)}\]\, we find the probability of intersection: \[P(A \cap B) = P(A \,|\, B) \times P(B) = 0.3 \times 0.8 = 0.24.\] Hence, \[P(A^c \cap B) = P(B) - P(A \cap B) = 0.8 - 0.24 = 0.56.\]
4Step 4: Check for Independence of B and A^c
Using the values calculated in previous steps, check if \(P(B) \times P(A^c) = P(B \cap A^c)\).Substitute the values: \[0.8 \times 0.7 = 0.56.\]Since \(0.56 = 0.56\), the equality holds, indicating that the events \(B\) and \(A^c\) are independent.
Key Concepts
Complement RuleIndependent EventsConditional ProbabilityBayes' Theorem
Complement Rule
Understanding the concept of the complement is crucial in probability theory. The complement of an event, labeled as \(A^c\), denotes all outcomes that are not part of event \(A\). For example, if event \(A\) represents rolling a die and getting a 4, the complement \(A^c\) would be rolling anything other than a 4. This means that the probabilities of these two events add up to 1. Mathematically, it is expressed as:
- \(P(A^c) = 1 - P(A)\)
Independent Events
Two events, say \(A\) and \(B\), are independent if the occurrence of one does not affect the probability of the other occurring. In simpler terms, the probability of \(A\) happening is the same whether \(B\) happens or not. The formal definition states:
- \(P(A \cap B) = P(A) \times P(B)\)
Conditional Probability
Conditional probability refers to the probability of event \(A\) occurring given that \(B\) has already occurred. It is represented mathematically as \(P(A \mid B)\).The formula for conditional probability is:
- \(P(A \mid B) = \frac{P(A \cap B)}{P(B)}\)
- \(P(A \cap B) = P(A \mid B) \times P(B)\)
Bayes' Theorem
Bayes' Theorem is a fundamental result in probability theory. It describes the probability of an event based on prior knowledge of related events. Specifically, it allows us to update our beliefs in light of new evidence. The theorem is expressed as:
- \(P(A \mid B) = \frac{P(B \mid A) \times P(A)}{P(B)}\)
Other exercises in this chapter
Problem 141
A computer system uses passwords that contain exactly eight characters, and each character is one of the 26 lowercase letters \((a-z)\) or 26 uppercase letters
View solution Problem 142
If \(P(A \mid B)=0.4, P(B)=0.8,\) and \(P(A)=0.5,\) are the events \(A\) and \(B\) independent?
View solution Problem 144
If \(P(A)=0.2, P(B)=0.2,\) and \(A\) and \(B\) are mutually exclusive, are they independent?
View solution Problem 145
A batch of 500 containers of frozen orange juice contains 5 that are defective. Two are selected, at random, without replacement, from the batch. Let \(A\) and
View solution