Problem 142
Question
Can a real number be both rational and irrational? Explain your answer.
Step-by-Step Solution
Verified Answer
No, a real number cannot be both rational and irrational. These two sets of numbers are mutually exclusive, meaning a number can be either rational or irrational, but not both.
1Step 1: Definitions Review
A rational number can be defined as a number that can be expressed as the quotient or fraction \( p/q \) of two integers, with the denominator \( q \) not equal to zero. Since the set of rational numbers includes the integers, the rational numbers are countable. On the other hand, an irrational number cannot be expressed as a ratio. That's why it is called irrational. It cannot be expressed as a fraction, and it's decimal goes on forever without repeating. For example, \(\pi\) is an irrational number.
2Step 2: Reflection on the Question
With the above understanding, it's clear that the defining properties of rational and irrational numbers are mutually exclusive. A rational number, by definition, has a finite or repeating decimal expansion. An irrational number, by definition, has a non-repeating decimal expansion. There is no overlap in these two sets, meaning a number can either be rational (finite or repeating decimal expansion) or irrational (non-repeating decimal expansion), but not both.
Other exercises in this chapter
Problem 142
Find all integers b so that the trinomial can be factored. $$x^{2}+b x+15$$
View solution Problem 142
Exercises \(142-144\) will help you prepare for the material covered in the next section. $$\text { Multiply: }\left(2 x^{3} y^{2}\right)\left(5 x^{4} y^{7}\rig
View solution Problem 143
Exercises \(142-144\) will help you prepare for the material covered in the next section. Use the distributive property to multiply: $$2 x^{4}\left(8 x^{4}+3 x\
View solution Problem 143
If you are given two real numbers, explain how to determine which is the lesser.
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