Problem 141
Question
How do the whole numbers differ from the natural numbers?
Step-by-Step Solution
Verified Answer
The main difference between whole numbers and natural numbers is that whole numbers include all non-negative integers including 0, while natural numbers include all positive integers starting from 1. Thus, whole numbers encompass natural numbers and the number 0.
1Step 1: Definition of Whole Numbers
Whole numbers are a set of numbers that includes all positive integers starting from 0. This set is often symbolized as W = {0, 1, 2, 3, 4, 5, ...}. The dots (...) denote that the numbers continue indefinitely in the positive direction.
2Step 2: Definition of Natural Numbers
The natural numbers, on the other hand, are a set of numbers that includes all positive integers starting from 1. This set is often symbolized as N = {1, 2, 3, 4, 5, ...}. Like whole numbers, the series continues indefinitely, but it starts from 1 instead of 0.
3Step 3: Difference between Whole Numbers and Natural Numbers
The primary difference between whole numbers and natural numbers is the inclusion of 0. In the set of whole numbers, 0 is included, thereby reflecting all non-negative integers. The set of natural numbers, however, starts from 1, so it includes only positive integers. Therefore, the whole numbers include the natural numbers and the number 0.
Other exercises in this chapter
Problem 141
a. A mathematics professor recently purchased a birthday cake for her son with the inscription $$\text { Happy }\left(2^{\frac{5}{2}} \cdot 2^{\frac{3}{4}} \div
View solution Problem 141
Factor completely. $$ (x-5)^{-\frac{1}{2}}(x+5)^{-\frac{1}{2}}-(x+5)^{\frac{1}{2}}(x-5)^{-\frac{3}{2}} $$
View solution Problem 142
Exercises \(142-144\) will help you prepare for the material covered in the next section. Multiply: \(\quad\left(2 x^{3} y^{2}\right)\left(5 x^{4} y^{7}\right)\
View solution Problem 142
Find all integers b so that the trinomial can be factored. $$ x^{2}+b x+15 $$
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