Problem 141
Question
Determine whether the statement is true or false. Justify your answer. $$\sin \theta=-\sqrt{1-\cos ^{2} \theta} \text { for } 90^{\circ} < \theta < 180^{\circ}$$
Step-by-Step Solution
Verified Answer
The statement is false.
1Step 1: Recognize the quadrant
First, notice that the range \(90^{\circ} < \theta < 180^{\circ}\) is found in the 2nd quadrant, where \(\sin\theta >0\) and \(\cos\theta <0\).
2Step 2: Understand the sign of the function
In this quadrant, the sine function returns positive values because the y-coordinate on the unit circle is positive in this quadrant. Thus, for any \(\theta\) in this quadrant, \(\sin\theta\) cannot be negative.
3Step 3: Evaluate the given equation
The given equation implies \(\sin\theta\) should be negative in this quadrant, which is impossible. So the equation \(\sin \theta=-\sqrt{1-\cos ^{2} \theta}\) is not true for \(90^{\circ} < \theta < 180^{\circ}\).
Key Concepts
Unit CircleSine FunctionCosine FunctionQuadrants in Trigonometry
Unit Circle
The unit circle is a powerful tool in trigonometry. It helps to define the sine and cosine functions in a simple way. Imagine a circle with a radius of one unit centered at the origin of a coordinate plane. As you move around the circle, the coordinates of the points are expressed as \((x, y)\).
- The x-coordinate corresponds to the cosine of the angle \(\theta\).
- The y-coordinate is the sine of the angle \(\theta\).
Sine Function
The sine function defines a relationship between an angle and the vertical component of a point on the unit circle. In simpler terms, it tells you how far up or down the point on the unit circle is.
In the provided exercise, the angle \(\theta\) lies between \(90^{\circ}\) and \(180^{\circ}\). Here, the sine function is positive, because the y-coordinate is above the x-axis.
The sine function can be expressed in terms of other trigonometric functions, using the identity: \(\sin^2\theta + \cos^2\theta = 1\). This means:
In the provided exercise, the angle \(\theta\) lies between \(90^{\circ}\) and \(180^{\circ}\). Here, the sine function is positive, because the y-coordinate is above the x-axis.
The sine function can be expressed in terms of other trigonometric functions, using the identity: \(\sin^2\theta + \cos^2\theta = 1\). This means:
- \(\sin\theta = \sqrt{1 - \cos^2\theta}\)
Cosine Function
The cosine function is closely related to the sine function and portrays how far left or right a point on the unit circle is, or in other words, its horizontal component.
Like with the sine function, the exercise involves analyzing the cosine of an angle in the second quadrant, where the cosine is negative. This is because in this region of the unit circle, the x-coordinate is on the left side of the y-axis and thus negative.
To elaborate further, using the Pythagorean identity:
Like with the sine function, the exercise involves analyzing the cosine of an angle in the second quadrant, where the cosine is negative. This is because in this region of the unit circle, the x-coordinate is on the left side of the y-axis and thus negative.
To elaborate further, using the Pythagorean identity:
- \(\cos\theta = -\sqrt{1 - \sin^2\theta}\), when \(\theta\) is between \(90^{\circ}\) and \(180^{\circ}\).
Quadrants in Trigonometry
Understanding the quadrants of the coordinate plane is essential in trigonometry because they tell us the signs of trigonometric functions in each section.
The coordinate plane is divided into four quadrants:
The coordinate plane is divided into four quadrants:
- First Quadrant: Both sine and cosine are positive.
- Second Quadrant: Sine is positive, cosine is negative.
- Third Quadrant: Both sine and cosine are negative.
- Fourth Quadrant: Sine is negative, cosine is positive.
Other exercises in this chapter
Problem 139
Determine whether the statement is true or false. Justify your answer. $$\sin \theta
View solution Problem 140
Determine whether the statement is true or false. Justify your answer. $$\sin \theta
View solution Problem 142
Determine whether the statement is true or false. Justify your answer. $$\cos \theta=-\sqrt{1-\sin ^{2} \theta} \text { for } 90^{\circ}
View solution Problem 143
(a) Use a graphing utility to complete the table. $$\begin{array}{|l|l|l|l|l|l|} \hline \theta & 0^{\circ} & 20^{\circ} & 40^{\circ} & 60^{\circ} & 80^{\circ} \
View solution