Problem 14
Question
Which of the following is the electron deficient molecule? (a) \(\mathrm{C}_{2} \mathrm{H}_{6}\) (b) \(\mathrm{B}_{2} \mathrm{H}_{6}\) (c) \(\mathrm{SiH}_{4}\) (d) \(\mathrm{PH}_{3}\)
Step-by-Step Solution
Verified Answer
The electron-deficient molecule is ext{B}_{2} ext{H}_{6}.
1Step 1: Understanding Electron Deficiency
An electron-deficient molecule is one that does not have enough electrons to form the standard two-electron bonds expected from their known chemical structure. Usually, these are compounds of elements that tend to follow the octet rule but cannot complete their octet in standard conditions.
2Step 2: Examine Each Molecule for Electron Deficiency
We need to look at the electron configurations of the given molecules to identify the electron-deficient one. Let's review them one by one:
- extbf{(a) } ext{In } ext{C}_{2} ext{H}_{6} ext{(ethane), carbon forms four bonds, each carbon is happy with a full octet.}
- extbf{(b) } ext{In } ext{B}_{2} ext{H}_{6} ext{(diborane), boron usually has 3 valence electrons. Traditionally, it would seek 5 additional electrons to satisfy the octet rule, however, in B}_{2} ext{H}_{6}, it forms three bonds and is left electron-deficient as it cannot complete its octet.}
- extbf{(c) } ext{In } ext{SiH}_{4} ext{(silane), silicon forms four single bonds, thus satisfying its octet.}
- extbf{(d) } ext{In } ext{PH}_{3} ext{(phosphine), phosphorus forms three bonds and holds a lone pair, completing its octet.}
3Step 3: Identify Electron Deficient Molecule
Based on the above analysis, diborane ( ext{B}_{2} ext{H}_{6}) is electron-deficient as each boron atom forms only three bonds and has only six electrons in its valence shell, thus lacking a full octet.
Key Concepts
Octet RuleDiborane StructureElectron ConfigurationValence Electrons
Octet Rule
The octet rule is a fundamental principle in chemistry. It states that atoms tend to form bonds until they are surrounded by eight valence electrons, achieving a stable electron configuration similar to noble gases.
This rule explains many chemical bonding tendencies in molecules.
For example, in carbon, with four valence electrons, it needs four more to complete its octet. Hence, it forms four covalent bonds, like in methane \(\mathrm{CH}_{4}\).
This rule explains many chemical bonding tendencies in molecules.
For example, in carbon, with four valence electrons, it needs four more to complete its octet. Hence, it forms four covalent bonds, like in methane \(\mathrm{CH}_{4}\).
- Limitations: The rule generally applies to main-group elements. However, some molecules, like certain transitioned metals or those involving elements like hydrogen, boron, and aluminum, do not comply fully.
- Systems and Exceptions: For small molecules like \(\mathrm{B}_{2}\mathrm{H}_{6}\) (diborane), octet completion is unachievable due to the inherent lack of electrons, leading to electron deficiency.
Diborane Structure
Diborane \(\mathrm{B}_{2}\mathrm{H}_{6}\) is a fascinating example of an electron-deficient compound due to its unique bonding approach. In this molecule, we see the formation of unusual 'three-center two-electron' bonds or 'bridge bonds.'
These are necessary to hold the atoms together despite lacking enough electrons to form ordinary covalent bonds.
These are necessary to hold the atoms together despite lacking enough electrons to form ordinary covalent bonds.
- Diborane consists of two boron atoms each forming 4 hydride bonds: 2 regular hydrogen bonds and 2 bridge bonds.
- In these bonds, a pair of electrons is shared between three atoms instead of the usual two, a clear deviation from traditional octet rule bonding.
Electron Configuration
Electron configuration describes the distribution of electrons in an atom's orbitals. This organization helps predict an atom's bonding behavior and chemical properties.
For elements like boron in diborane, the electron configuration can be illustrated as \(1s^2 2s^2 2p^1\).
For elements like boron in diborane, the electron configuration can be illustrated as \(1s^2 2s^2 2p^1\).
- In a boron atom, only three electrons are in the valence shell, making it electron-deficient for octet completion.
- This scarcity of electrons is pivotal in determining boron's bonding pattern in molecules it forms.
Valence Electrons
Valence electrons are the outermost electrons that play a key role in forming chemical bonds.
Their number usually determines an atom's ability to follow the octet rule in bonding processes.
Their number usually determines an atom's ability to follow the octet rule in bonding processes.
- For most elements, achieving a stable electron configuration involves gaining, losing, or sharing valence electrons.
- Boron, for example, has three valence electrons, insufficient for full octet formation.
Other exercises in this chapter
Problem 12
Among the following pairs, the one in which the two species are not isostructural is (a) \(\mathrm{SiF}_{4}\) and \(\mathrm{SF}_{4}\) (b) \(\mathrm{IO}_{3}^{-}\
View solution Problem 13
In an octahedral structure, the pair of \(\mathrm{d}\) orbitals involved in \(\mathrm{d}^{2} \mathrm{sp}^{3}\) hybridization is (a) \(\mathrm{d}_{x^{2}-y^{2}},
View solution Problem 15
Which of the following molecules has trigonal planar geometry? (a) \(\mathrm{BF}_{3}\) (b) \(\mathrm{NH}_{3}\) (c) \(\mathrm{PCl}_{3}\) (d) \(\mathrm{IF}_{3}\)
View solution Problem 16
Which of the following would have a permanent dipole moment? (a) \(\mathrm{SiF}_{4}\) (b) \(\mathrm{SF}_{4}\) (c) \(\mathrm{XeF}_{4}\) (d) \(\mathrm{BF}_{3}\)
View solution