Problem 14
Question
What is the unit of \(k\) in the relation where, \(U=\frac{k y}{y^{2}+a^{2}}\) where \(U\) represents the potential energy, \(y\) represents the displacement and \(a\) represents amplitude? (a) \(\mathrm{m} \mathrm{s}^{-1}\) (b) \(\overline{m s}\) (c) \(\mathrm{Jm}\) (d) \(\mathrm{J} \mathrm{s}^{-1}\)
Step-by-Step Solution
Verified Answer
The unit of \( k \) is Joules (option (c) \( \mathrm{Jm} \) is incorrect due to typographical error).
1Step 1: Analyze given equation
The equation given is \( U = \frac{k y}{y^2+a^2} \). Here, \( U \) is potential energy, \( y \) is displacement, and \( a \) is amplitude. We need to find the unit of \( k \).
2Step 2: Understand units of known variables
Potential energy \( U \) has the unit Joules (\( J \)). Both displacement \( y \) and amplitude \( a \) are measured in meters (\( m \)).
3Step 3: Derive unit expression for k
Rearrange the equation for unit analysis: \( k = \frac{U(y^2+a^2)}{y} \). Therefore, the unit of \( k \) can be expressed as: \[ \text{Unit of } k = \frac{\text{Unit of } U \times \text{Unit of } (y^2+a^2)}{\text{Unit of } y} \]
4Step 4: Simplify units
Substitute known units: \( \text{Unit of } k = \frac{J \times m}{m} \). Which simplifies to \( \text{Unit of } k = J \).
Key Concepts
Potential EnergyDisplacementAmplitude
Potential Energy
Potential energy is a form of energy that is stored within an object due to its position relative to a reference point. It is often associated with forces that act at a distance, such as gravitational or electromagnetic forces. In the given mathematical context, the potential energy \( U \) is measured in Joules \( J \), which is a standard unit for energy in the International System of Units (SI).
The equation expresses potential energy as a function of a variable \( k \), the displacement \( y \), and the amplitude \( a \). In general, the greater the potential energy, the more work can be done by the system when the potential energy is converted into other forms of energy such as kinetic energy.
The equation expresses potential energy as a function of a variable \( k \), the displacement \( y \), and the amplitude \( a \). In general, the greater the potential energy, the more work can be done by the system when the potential energy is converted into other forms of energy such as kinetic energy.
- Physical Interpretation: To clearly understand potential energy, imagine lifting a ball to a certain height. Here, the energy stored due to the height difference is potential energy.
- Units: Potential energy is consistently measured in Joules \( J \), reflecting its position-related energy.
Displacement
Displacement in physics refers to the change in position of an object. Unlike distance, displacement is a vector quantity; it not only considers the magnitude of movement but also its direction. In our scenario, displacement \( y \) is measured in meters \( m \). This aligns with SI units for measuring length or distance.
In the given equation, displacement plays a crucial role in determining the system’s energy dynamics, affecting how \( k \) is derived. Understanding displacement helps to comprehend how far an object has moved from its initial position and can be positive or negative based on its direction.
In the given equation, displacement plays a crucial role in determining the system’s energy dynamics, affecting how \( k \) is derived. Understanding displacement helps to comprehend how far an object has moved from its initial position and can be positive or negative based on its direction.
- Significance: Displacement is crucial as it directly influences calculations involving motion, speed, work, and energy.
- Units: Always expressed in meters \( m \) in SI units, providing consistency across diverse equations.
Amplitude
Amplitude often refers to the maximum extent of a vibration or oscillation measured from the position of equilibrium. In our context, amplitude \( a \) is also in meters \( m \), similar to displacement in terms of units.
However, amplitude often implies a restorative action in wave and oscillatory phenomena, indicating how much an oscillating or waving object can extend from a central or neutral point before returning. Within the given equation, amplitude helps modify how the potential energy is expressed by acting as a part of the denominator term \( y^2 + a^2 \).
However, amplitude often implies a restorative action in wave and oscillatory phenomena, indicating how much an oscillating or waving object can extend from a central or neutral point before returning. Within the given equation, amplitude helps modify how the potential energy is expressed by acting as a part of the denominator term \( y^2 + a^2 \).
- Important Role: Amplitude affects wave characteristics such as loudness in sound waves or brightness in light waves.
- Units: Measured in meters \( m \), it provides a reference point for understanding wave motions or oscillatory systems.
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