Problem 14
Question
What is the Lewis symbol for each of the following atoms or ions? (a) \(\mathrm{K},\) (b) As, (c) \(\mathrm{Sn}^{2+},(\mathbf{d}) \mathrm{N}^{3-}\) .
Step-by-Step Solution
Verified Answer
The Lewis symbols for the given atoms and ions are:
(a) \(\text{K}\bullet\) , (b) \[\begin{array}{c}\cdot \text{As} \cdot \\ | \end{array}\], (c) \(\bullet \text{Sn}^{2+} \bullet\), and (d) \[\begin{array}{c}\cdot \text{N}^{3-} \cdot \\ | \end{array}\].
1Step 1: Determine valence electrons for each atom/ion
(a) Potassium (K) - As it belongs to the first group in the periodic table, it has only 1 valence electron.
(b) Arsenic (As) - Being a member of Group 15 in the periodic table, it has 5 valence electrons.
(c) Tin(II) ion (Sn²⁺) - Tin, as a Group 14 element, has 4 valence electrons. However, due to the 2+ charge, which means it loses 2 electrons, that leaves it with 2 valence electrons.
(d) Nitride ion (N³⁻) - Nitrogen, as a Group 15 element, has 5 valence electrons. Since the ion has a 3- charge, it gains 3 electrons, thus giving it a total of 8 valence electrons.
2Step 2: Represent elements and ions with their symbols and valence electrons
(a) Potassium (K) - \[\text{K}\bullet\]
(b) Arsenic (As) - \[\begin{array}{c}\cdot \text{As} \cdot \\ | \end{array}\]
(c) Tin(II) ion (Sn²⁺) - \[\bullet \text{Sn}^{2+} \bullet\]
(d) Nitride ion (N³⁻) - \[\begin{array}{c}\cdot \text{N}^{3-} \cdot \\ | \end{array}\]
The Lewis symbols for the given atoms and ions are:
(a) K• , (b) ∙As∙| , (c) •Sn²⁺• , and (d) ∙N³⁻∙| .
Key Concepts
Valence ElectronsElectron ConfigurationPeriodic Table Groups
Valence Electrons
Valence electrons are the outermost electrons in an atom, which are crucial in determining how atoms interact with one another. These electrons play a significant role in chemical bonds, as they are the ones involved in gaining, losing, or sharing to form compounds.
The tin(II) ion (Sn²⁺) originally has four valence electrons, but due to its 2+ charge, it loses two. Thus, it has two valence electrons left. Nitride ion (N³⁻) gains three electrons, bringing its valence count to eight.
Understanding valence electrons enables us to visualize the interaction possibilities and predict chemical reactions.
- Valence electrons dictate how an element behaves chemically.
- They are located in the atom's highest energy level or shell.
- The number of valence electrons in an atom is often represented in Lewis symbols.
The tin(II) ion (Sn²⁺) originally has four valence electrons, but due to its 2+ charge, it loses two. Thus, it has two valence electrons left. Nitride ion (N³⁻) gains three electrons, bringing its valence count to eight.
Understanding valence electrons enables us to visualize the interaction possibilities and predict chemical reactions.
Electron Configuration
The electron configuration of an atom describes how its electrons are distributed in different atomic orbitals. This configuration helps us understand the atom's characteristics and chemical behavior.
This electron arrangement explains why some atoms are more likely to form certain types of bonds.
- Electrons are arranged into shells and subshells (s, p, d, f) based on their energy levels.
- Each shell follows a specific order based on increasing energy levels, usually noted as 1s, 2s, 2p, 3s, and so on.
- The number of valence electrons stems from the electron configuration, impacting how Lewis symbols are drawn.
This electron arrangement explains why some atoms are more likely to form certain types of bonds.
Periodic Table Groups
The periodic table is organized into vertical columns known as groups or families, each possessing specific chemical properties determined by their electron configuration. These groups are essential for predicting chemical behavior and properties, including the number of valence electrons.
- Elements in the same group have the same number of valence electrons.
- This similarity leads to comparable chemical properties among group elements.
- Groups are numbered from 1 to 18, sometimes using old notations like IA, IIA, etc.
Other exercises in this chapter
Problem 12
(a) Write the electron configuration for the element titanium, Ti. How many valence electrons does this atom possess? (b) Hafnium, Hf, is also found in group 4
View solution Problem 13
Write the Lewis symbol for atoms of each of the following elements: (a) Al, (b) Br, (c) Ar, (d) Sr.
View solution Problem 15
(a) Using Lewis symbols, diagram the reaction between magnesium and oxygen atoms to give the ionic substance MgO. (b) How many electrons are transferred? (c) Wh
View solution Problem 16
(a) Use Lewis symbols to represent the reaction that occurs between Ca and F atoms. (b) What is the chemical formula of the most likely product? (c) How many el
View solution