Problem 14
Question
Verify the identity. \(\frac{\sin ^{2} 2 \alpha}{\sin ^{2} \alpha}=4-4 \sin ^{2} \alpha\)
Step-by-Step Solution
Verified Answer
The identity is verified as both sides equal \(4 \cos^{2} \alpha\).
1Step 1: Simplify the Left Side
We begin with simplifying the left side of the equation \( \frac{\sin^{2} 2\alpha}{\sin^{2} \alpha} \). The formula for \( \sin 2\alpha \) is \( 2 \sin \alpha \cos \alpha \). Therefore, \( \sin^{2} 2\alpha = (2 \sin \alpha \cos \alpha)^2 = 4 \sin^{2} \alpha \cos^{2} \alpha \). Thus, the left side becomes \( \frac{4 \sin^{2} \alpha \cos^{2} \alpha}{\sin^{2} \alpha} \).
2Step 2: Simplify the Fraction
Cancel \( \sin^{2} \alpha \) from the numerator and the denominator of \( \frac{4 \sin^{2} \alpha \cos^{2} \alpha}{\sin^{2} \alpha} \). This simplifies to \( 4 \cos^{2} \alpha \). Therefore, the left side simplifies to \( 4 \cos^{2} \alpha \).
3Step 3: Express Right Side in Terms of Cosine
The identity on the right side \( 4 - 4 \sin^{2} \alpha \) can be rewritten using the Pythagorean identity \( \sin^{2} \alpha + \cos^{2} \alpha = 1 \). So, \( 4(1 - \sin^{2} \alpha) = 4 \cos^{2} \alpha \).
4Step 4: Equate the Simplified Expressions
Both sides now simplify to \( 4 \cos^{2} \alpha \). Therefore, the identity is verified as both sides are equal.
Key Concepts
Double Angle FormulasPythagorean IdentityTrigonometric Simplification
Double Angle Formulas
When dealing with trigonometric expressions, the double angle formulas can be incredibly useful tools. They provide a way to express trigonometric functions of double angles in terms of single-angle functions. For example, the double angle formula for sine is \( \sin 2\alpha = 2 \sin \alpha \cos \alpha \). This formula allows us to simplify expressions involving double angles by breaking them down into simpler parts. In the exercise, we used \( \sin^2 2\alpha \) and expanded it using the double angle formula, which transformed \( \sin^2 2\alpha \) into \((2 \sin \alpha \cos \alpha)^2 = 4 \sin^2 \alpha \cos^2 \alpha \). Understanding and applying these formulas enable us to break down complex trigonometric identities into more manageable forms.
Pythagorean Identity
The Pythagorean identity is one of the cornerstone relationships in trigonometry. It states that for any angle \( \alpha \), \( \sin^2 \alpha + \cos^2 \alpha = 1 \).This identity is not only fundamental but highly useful for simplifying expressions, especially when you need to rewrite one trigonometric function in terms of another. In the given exercise, to simplify the right side of the identity, we used \( \cos^2 \alpha = 1 - \sin^2 \alpha \) by rearranging the Pythagorean identity. This allowed us to rewrite \( 4 - 4 \sin^2 \alpha \) as \( 4 \cos^2 \alpha \).The Pythagorean identity is extremely versatile in various situations involving trigonometric expressions and equations, making it an essential tool for any student studying trigonometry.
Trigonometric Simplification
Trigonometric simplification involves expressing a complex trigonometric expression in a simpler or more convenient form. This process often utilizes identities such as double angle formulas and Pythagorean identities.In the provided exercise, we started by simplifying a fraction involving \( \sin^2 2\alpha \) on the left side. By using appropriate identities, we reduced the expression step by step to reach a more straightforward form. Key strategies include:
- Identifying applicable formulas or identities.
- Cancelling out common terms in fractions.
- Rewriting parts of an expression using known identities.
Other exercises in this chapter
Problem 14
Verify the Identity. $$\cos ^{4} 2 \theta+\sin ^{2} 2 \theta=\cos ^{2} 2 \theta+\sin ^{4} 2 \theta$$
View solution Problem 14
Exer. \(11-16\) : Express as a trigonometric function of one angle. $$\sin 57^{\circ} \cos 4^{\circ}+\cos 57^{\circ} \sin 4^{\circ}$$
View solution Problem 14
Find all solutions of the equation. $$\cos \frac{1}{4} x=-\frac{\sqrt{2}}{2}$$
View solution Problem 15
Find the exact value of the expression whenever It is defined. (a) \(\cot \left(\sin ^{-1} \frac{2}{3}\right)\) (b) \(\sec \left[\tan ^{-1}\left(-\frac{3}{5}\ri
View solution