Problem 14
Question
Use properties of logarithms to expand logarithmic expression as much as possible. Where possible, evaluate logarithmic expressions without using a calculator. \(\ln \left(\frac{e^{4}}{8}\right)\)
Step-by-Step Solution
Verified Answer
4 - \( \ln{8} \)
1Step 1: Applying Division Rule
Using the division rule \( \ln{a/b} = \ln{a} - \ln{b} \), expand the given expression as: \( \ln{e^{4}} - \ln{8} \)
2Step 2: Applying Power Rule
Using the power rule \( \ln{a^n} = n\ln{a} \), the first term simplifies to \( 4\ln{e} \). So the expression now becomes \( 4\ln{e} - \ln{8} \)
3Step 3: Evaluating Logarithmic Expressions
Since the base of \( \ln{e} \) is \( e \), it equals 1, simplifying the expression to 4 - \( \ln{8} \).
Key Concepts
Understanding the Division Rule of LogarithmsExploring the Power Rule of LogarithmsThe Tranquility of the Natural LogarithmSimplifying Logarithmic Expressions Efficiently
Understanding the Division Rule of Logarithms
The division rule of logarithms is a fundamental component when working with logarithmic expressions and can greatly help in simplifying complex expressions. The rule states that the logarithm of a division equals the difference of the logarithms. This can be written as:\[\ln\left(\frac{a}{b}\right) = \ln{a} - \ln{b}\]This means that if you have a logarithm involving a fraction or division, you can separate it into two logarithms by subtracting the logarithm of the denominator from the logarithm of the numerator. For instance, for the expression \( \ln\left(\frac{e^{4}}{8}\right) \), we apply this rule to get:
- \( \ln{e^{4}} - \ln{8} \)
Exploring the Power Rule of Logarithms
The power rule of logarithms is another powerful tool that often accompanies the division rule. It allows us to simplify logs that involve exponents by bringing the exponent outside as a multiplier. The rule is expressed as: \[\ln{a^n} = n \ln{a}\]This makes tackling logarithms with powers a breeze. In our example earlier, notice the term \( \ln{e^{4}} \). Applying the power rule gives us:
- \( 4\ln{e} \)
The Tranquility of the Natural Logarithm
The natural logarithm, denoted as \( \ln{x} \), holds a special place in mathematics, particularly because of its base, \( e \), which is approximately equal to 2.718. The natural logarithm has specific properties that simplify calculations substantially, one of which is simplifying \( \ln{e} \). Since it implies \( e \) to the power of itself (essentially \( e^1 \)), \( \ln{e} \) evaluates to 1. Consider the term we obtained from the power rule, \( 4\ln{e} \). Knowing that \( \ln{e} \) is 1 simplifies our expression further to:
- 4 - \( \ln{8} \)
Simplifying Logarithmic Expressions Efficiently
Simplifying complex logarithmic expressions is an essential skill in math, enabling the solving of equations and problems with confidence. Let's look back on the expression we simplified incrementally:
- Start: \( \ln\left(\frac{e^{4}}{8}\right) \)
- Apply division rule: \( \ln{e^{4}} - \ln{8} \)
- Apply power rule: \( 4\ln{e} - \ln{8} \)
- Simplify using \( \ln{e} = 1: 4 - \ln{8} \)
Other exercises in this chapter
Problem 14
Solve each exponential equation by expressing each side as a power of the same base and then equating exponents. $$5^{2-x}=\frac{1}{125}$$
View solution Problem 14
Graph each function by making a table of coordinates. If applicable, use a graphing utility to confirm your hand-drawn graph. $$g(x)=\left(\frac{4}{3}\right)^{x
View solution Problem 15
An artifact originally had 16 grams of carbon- 14 present. The decay model \(A=16 e^{-0.0001211}\) describes the amount of carbon-I4 present after t years. Use
View solution Problem 15
Solve each exponential equation by expressing each side as a power of the same base and then equating exponents. $$6^{\frac{x-3}{4}}=\sqrt{6}$$
View solution