Problem 14
Question
These exercises use the population growth model. The count in a culture of bacteria was 400 after 2 hours and \(25,600\) after 6 hours. (a) What is the relative rate of growth of the bacteria population? Express your answer as a percentage. (b) What was the initial size of the culture? (c) Find a function that models the number of bacteria \(n(t)\) after \(t\) hours. (d) Find the number of bacteria after 4.5 hours. (e) When will the number of bacteria be \(50,000 ?\)
Step-by-Step Solution
Verified Answer
(a) 103.972% growth rate
(b) Initial size 100
(c) Model: \(n(t) = 100e^{1.03972t}\)
(d) 10746.7 bacteria after 4.5 hours
(e) 5.975 hours for 50,000 bacteria
1Step 1: Understand the Exponential Growth Formula
The formula for exponential growth is given by:\[ n(t) = n_0 e^{rt} \]where \( n(t) \) is the population at time \( t \), \( n_0 \) is the initial population size, \( r \) is the growth rate, and \( t \) is time.
2Step 2: Relate Two Population Values to Find Growth Rate
We know the population at two different times: \( n(2) = 400 \) and \( n(6) = 25600 \). Using the formula,\[ 25600 = 400 e^{4r} \]Solve for \( r \):\( e^{4r} = \frac{25600}{400} = 64 \),\( 4r = \ln 64 \),\( r = \frac{\ln 64}{4} \).
3Step 3: Calculate the Growth Rate
Compute \( r \):\[ r = \frac{\ln 64}{4} = \frac{4.15888}{4} = 1.03972 \]Express \( r \) as a percentage: \( r \approx 103.972\% \).
4Step 4: Determine Initial Population
Using the exponential growth formula with known \( n(2) = 400 \),\[ 400 = n_0 e^{2r} \]Using \( r \approx 1.03972 \),\[ 400 = n_0 \times e^{2 \times 1.03972} \]Calculate \( n_0 \):\[ n_0 = \frac{400}{e^{2.07944}} = 100 \].
5Step 5: Formulate the Exponential Model
Using the values \( n_0 = 100 \) and \( r = 1.03972 \):\[ n(t) = 100 e^{1.03972t} \].
6Step 6: Calculate Population After 4.5 Hours
Using the model \( n(t) = 100 e^{1.03972t} \) with \( t = 4.5 \):\[ n(4.5) = 100 e^{1.03972 \times 4.5} \]\[ n(4.5) = 100 \times e^{4.67874} \approx 100 \times 107.467 \approx 10746.7 \].
7Step 7: Determine Time for Population to Reach 50,000
Set the model equal to 50000:\[ 50000 = 100 e^{1.03972t} \]Solve for \( t \):\[ 500 = e^{1.03972t} \],\[ t = \frac{\ln 500}{1.03972} \approx \frac{6.21461}{1.03972} \approx 5.975 \] hours.
Key Concepts
Population Growth ModelBacteria PopulationGrowth RateExponential Function
Population Growth Model
The population growth model plays a significant role in understanding how populations increase over time. In many scenarios, especially in biology and ecology, populations such as bacteria grow in a way that can be described mathematically.
The basic formula for such growth is the exponential growth equation. This model assumes that the population growth rate is proportional to the current population.
This mathematical representation helps in predicting future population sizes and is critical in fields such as microbiology, where understanding the behavior of bacteria over time is vital.
The basic formula for such growth is the exponential growth equation. This model assumes that the population growth rate is proportional to the current population.
- The model is expressed as: \[ n(t) = n_0 e^{rt} \]
- Where \( n(t) \) is the population at time \( t \)
- \( n_0 \) is the initial population size
- \( r \) is a constant representing the growth rate
- \( e \) is the base of the natural logarithm, approximately equal to 2.71828
This mathematical representation helps in predicting future population sizes and is critical in fields such as microbiology, where understanding the behavior of bacteria over time is vital.
Bacteria Population
A bacteria population is a perfect example of exponential growth in nature. Bacteria reproduce by binary fission, which means one bacterium splits into two, leading to rapid population increase under favorable conditions.
In the context of the given exercise, we consider a culture of bacteria where the initial and changes in population over time can be precisely calculated using the exponential growth model. Here’s a breakdown:
Such calculations are essential for understanding microbial cultures in laboratory settings, ensuring proper handling and experimentation.
In the context of the given exercise, we consider a culture of bacteria where the initial and changes in population over time can be precisely calculated using the exponential growth model. Here’s a breakdown:
- Given: After 2 hours, the population is 400, and after 6 hours, it becomes 25,600.
- To determine the initial size and behavior over time, use the exponential function model.
- This aids in knowing how many bacterial cells were present initially and predicting population changes over other time periods.
Such calculations are essential for understanding microbial cultures in laboratory settings, ensuring proper handling and experimentation.
Growth Rate
In understanding exponential growth, the growth rate, denoted by \( r \), is crucial. It reflects how quickly the population increases. Often expressed as a percentage, it tells you the rate of increase per unit time.
In our bacterial population problem:
In our bacterial population problem:
- The growth rate \( r \) is computed based on given population values at different times.
- You can calculate it by rearranging the exponential growth equation and solving for \( r \).
- Here, \( r \) was determined using the known populations \( n(2) = 400 \) and \( n(6) = 25600 \).
- The resultant growth rate was found to be approximately 103.972%.
Exponential Function
The exponential function is a mathematical function that models situations where growth or decay occurs at a constant rate. In the context of the population growth model, it is used to describe how quantities like populations change over time exponentially.
Applying this function, you can determine both the past and future states of populations in various scenarios, making it an indispensable tool in fields ranging from biology to economics.
- The basic form of an exponential function is \( f(t) = a e^{bt} \), where \( a \) is the initial amount and \( b \) is a constant that determines the rate of growth or decay.
- In our example, \( n(t) = 100 e^{1.03972t} \), this exponential function accurately describes the bacteria population over time.
- It allows predicting how population sizes will change at any point.
Applying this function, you can determine both the past and future states of populations in various scenarios, making it an indispensable tool in fields ranging from biology to economics.
Other exercises in this chapter
Problem 14
Express the equation in logarithmic form. (a) \(10^{3}=1000\) (b) \(81^{1 / 2}=9\)
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Find the solution of the exponential equation, rounded to four decimal places. $$2^{3 x}=34$$
View solution Problem 14
Sketch the graph of the function by making a table of values. Use a calculator if necessary. $$h(x)=2\left(\frac{1}{4}\right)^{x}$$
View solution Problem 14
Evaluate the expression. $$\log _{3} 100-\log _{3} 18-\log _{3} 50$$
View solution