Problem 14
Question
The sum of all the numbers that can be formed with the digits \(2,3,4,5\) taken all at a time is (A) 66666 (B) 84844 (C) 93324 (D) None of these
Step-by-Step Solution
Verified Answer
The sum is 93324, option (C).
1Step 1: Determine the Number of Permutations
Four digits can be arranged in different ways to form numbers. First, find the number of different permutations of the four digits 2, 3, 4, and 5. The formula for permutations is given by the factorial of the number of digits: \[ n! \]Here, \( n = 4 \), so the number of permutations is \[ 4! = 4 \times 3 \times 2 \times 1 = 24 \] Thus, there are 24 different numbers that can be formed.
2Step 2: Calculate Contribution of Each Digit at Each Place Value
Each digit appears in each place (thousands, hundreds, tens, units) the same number of times in all permutations. Since there are 4 digits and 24 total numbers, each digit appears at each place: \[ \frac{24}{4} = 6 \] times.
3Step 3: Find Total Contribution by Each Digit
Each position's value (thousands, hundreds, tens, units) will contribute to the sum of all numbers. Consider one position, say thousands, and calculate for repeat digits 6 times.The total contribution by each digit in one place is: \[ 6 \times 1000 \times (2 + 3 + 4 + 5) = 6 \times 1000 \times 14 = 84000 \] As this applies to each position, calculate the same for hundreds (100), tens (10), and units (1).
4Step 4: Add the Contributions of All Places
The total contribution by each digit across all place values is calculated once and summed up for all places:- Thousands: 6 times the sum \[ = 6 \times 1000 \times (2 + 3 + 4 + 5) = 84000 \] - Hundreds: \[ = 6 \times 100 \times (2 + 3 + 4 + 5) = 8400 \] - Tens: \[ = 6 \times 10 \times (2 + 3 + 4 + 5) = 840 \] - Units: \[ = 6 \times 1 \times (2 + 3 + 4 + 5) = 84 \] Adding these up gives the total sum:\[ 84000 + 8400 + 840 + 84 = 93324 \]
5Step 5: Determine the Correct Option
Compare your computed total sum with the given options. The result of 93324 matches Option (C).
Key Concepts
PermutationsFactorialPlace Value ContributionDigit Arrangement
Permutations
When dealing with numbers formed by a set of digits, understanding permutations is key. A permutation is a specific arrangement of a set of items. Here, we are working with the digits 2, 3, 4, and 5.
- Permutations involve rearranging these digits to form unique sequences.
- With four digits, the permutations are represented mathematically by the factorial of the number of digits.
Factorial
The factorial, denoted as \(n!\), is a fundamental concept in permutations and combinations. It represents the product of all positive integers from 1 to \(n\).
- Factorials are used to determine the number of possible arrangements or sequences for a set of items.
- For example, with 4 distinct digits, \(n = 4\), and the factorial \(4!\) helps to find all potential permutations.
Place Value Contribution
Each digit contributes to the number it forms based on its position or place value. In a 4-digit number, from left to right, the positions are thousands, hundreds, tens, and units.
- The contribution of a digit depends on its place in a number. The further left the position, the larger the contribution.
- For example, a digit in the thousands place contributes much more to the number than one in the units spot.
Digit Arrangement
Arranging digits to form numbers can be done by considering each digit's role in different positions. For a given set of digits, it is crucial to recognize their possible placements.
- Understanding the number of ways digits can be positioned helps calculate the overall number formed.
- In our example with digits 2, 3, 4, and 5, shifting their order creates new numbers, contributing to the total sum.
- Regardless of order, each digit takes turns occupying each position, ensuring equal representation across possible numbers.
Other exercises in this chapter
Problem 12
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