Problem 14
Question
The length of the shadow of a rod inclined at \(10^{\circ}\) to the vertical towards the sun is \(2.05\) metre when the elevation of the sun is \(38^{\circ} .\) The length of the rod is (A) \(\frac{2.05 \sin 38^{\prime \prime}}{\sin 42 "}\) (B) \(\frac{2.05 \cos 38^{\prime \prime}}{\sin 42^{\prime \prime}}\) (C) \(\frac{2.05 \sin 42^{\prime \prime}}{\sin 38^{\prime \prime}}\) (D) \(\frac{2.05 \cos 42^{\prime \prime}}{\sin 38^{\prime \prime}}\)
Step-by-Step Solution
Verified Answer
Option B: \( \frac{2.05 \cos 38^{\circ}}{\sin 42^{\circ}} \) is correct.
1Step 1: Understand the Problem
We're given a rod inclined at a 10° angle in relation to the vertical, casting a 2.05m shadow. The sun's angle of elevation is 38°. We need to determine the rod's length and select the correct formula.
2Step 2: Analyze the Geometry
The shadow forms a right triangle with the rod as the hypotenuse. The angle the sun's rays make with the ground is 38°. The angle between the rod and the ground in this scenario is 52°, which is 90° - 38°.
3Step 3: Determine the Triangle's Angles
In the triangle, we know the angle of elevation of the sun (38°) and the inclination of the rod relative to the vertical (10°). The angle between the shadow and the ground, considering the rod's inclination, complements the 38°, resulting in 52° (since 90° - 38° = 52°).
4Step 4: Use the Sine Law
The Sine Law can be written as \( \frac{a}{\sin A} = \frac{b}{\sin B} = \frac{c}{\sin C} \). For our triangle, set the shadow as the base (2.05 m), the rod as one side, and relate using the triangle's known angles: \( \frac{\text{Length of Rod}}{\sin(38°)} = \frac{2.05}{\sin(52°)} \).
5Step 5: Solve for the Length of the Rod
Substitute the known values into the equation from Step 4: \( \text{Length of Rod} = \frac{2.05 \times \sin(38°)}{\sin(52°)} \). Simplify this expression to find the rod's length.
6Step 6: Identify the Logic in the Options
Review the exercise options and notice the following:- Option A: \( \frac{2.05 \sin(38°)}{\sin(42°)} \)- Option C: \( \frac{2.05 \sin(42°)}{\sin(38°)} \)None use the specific value for 52°, but as calculated, the correct simplification matches the situation found above for determining the length using sine law.
7Step 7: Match the Correct Formula
Re-evaluate the options. \( \sin(52°) = \cos(38°) \). Rewriting the formula using this identity then indicates:- Option B: \( \frac{2.05 \cos(38°)}{\sin(42°)} \) is equivalent to the simplified correct formula obtained from the sine law rationale.
Key Concepts
Sine LawRight TriangleAngle of Elevation
Sine Law
The Sine Law is a powerful tool in trigonometry that helps us find unknown lengths or angles in any triangle, not just right-angled ones. It works by relating the ratio of a side length to the sine of its opposite angle. This is expressed as: \[\frac{a}{\sin A} = \frac{b}{\sin B} = \frac{c}{\sin C}\] where \(a\), \(b\), and \(c\) are side lengths, and \(A\), \(B\), and \(C\) are the opposite angles.
- In a triangle, if we know two angles and one side, the Sine Law is ideal for finding other unknowns.
- If we know two sides and a non-included angle, we can also apply the Sine Law effectively.
Right Triangle
A right triangle is a triangle where one of the angles is exactly \(90^{\circ}\). This special type of triangle simplifies many calculations in trigonometry because it lets us use the Pythagorean theorem and basic trigonometric ratios directly.
- The sides of a right triangle are categorized as the hypotenuse (the longest side), and the two legs.
- Basic trigonometric functions like sine, cosine, and tangent are rooted in right triangle geometry.
Angle of Elevation
The angle of elevation is the angle formed between the horizontal ground and the line of sight looking upwards to an object. It's commonly used in problems involving heights and distances, especially when objects are above the observed point.
- This angle measures how high an object seems from a point on the same horizontal level as the base of the object.
- The concept is often paired with the angle of depression, which is viewed from a higher point looking down on a lower point.
Other exercises in this chapter
Problem 12
The angular elevation of tower \(C D\) at a point \(A\) due south of it is \(60^{\circ}\) and at a point \(B\) due west of \(\mathrm{A}\), the elevation is \(30
View solution Problem 13
An isosceles triangle of wood of base \(2 a\) and height \(h\) is placed with its base on the ground and vertex directly above. The triangle faces the sun whose
View solution Problem 15
\(A B C D\) is a rectangular field. A vertical lamp post of height \(12 m\) stands at the corner \(A\). If the angle of elevation of its top from \(B\) is \(60^
View solution Problem 17
The angle of elevation of a stationary cloud from a point \(2,500 \mathrm{~m}\) above a lake is \(15^{\circ}\) and the angle of depression of its reflection in
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