Problem 14
Question
The equation of a conic section is given in a familiar form. Identify the type of graph (if any) that each equation has, without actually graphing. See the summary chart in this section. Do not use a calculator. $$\frac{x^{2}}{4}=1+\frac{y^{2}}{9}$$
Step-by-Step Solution
Verified Answer
The graph represents a hyperbola.
1Step 1: Recognize the Standard Form
The given equation is \( \frac{x^{2}}{4} = 1 + \frac{y^{2}}{9} \). Start by recognizing the form of this equation to see if it matches any standard conic sections forms.
2Step 2: Rearrange the Equation
Reorganize the given equation into a form more similar to the standard forms of conic sections. To do this, subtract \( \frac{y^{2}}{9} \) from both sides to get: \[ \frac{x^{2}}{4} - \frac{y^{2}}{9} = 1. \]
3Step 3: Identify the Standard Form
Now, the equation \( \frac{x^{2}}{4} - \frac{y^{2}}{9} = 1 \) resembles the standard form of a hyperbola. A hyperbola in standard form is written as \( \frac{x^{2}}{a^{2}} - \frac{y^{2}}{b^{2}} = 1 \) or \( \frac{y^{2}}{b^{2}} - \frac{x^{2}}{a^{2}} = 1 \).
4Step 4: Determine the Type of Conic Section
Since the equation \( \frac{x^{2}}{4} - \frac{y^{2}}{9} = 1 \) has both \( x^{2} \) and \( y^{2} \) terms with opposite signs, it represents a hyperbola where \( a^{2} = 4 \) and \( b^{2} = 9 \).
Key Concepts
HyperbolaStandard FormEquation Rearrangement
Hyperbola
A hyperbola is a type of conic section that is distinct from ellipses, circles, and parabolas. It occurs when the plane cuts through both nappes of the cone,
creating two symmetrical open curves. Hyperbolas have the unique property of having a center, two foci, two vertices, and two asymptotes.
Think of a hyperbola as a pair of mirrored arches. These curves open either horizontally or vertically around a center point depending on the arrangement of the variables in its standard form equation.
creating two symmetrical open curves. Hyperbolas have the unique property of having a center, two foci, two vertices, and two asymptotes.
Think of a hyperbola as a pair of mirrored arches. These curves open either horizontally or vertically around a center point depending on the arrangement of the variables in its standard form equation.
- A hyperbola's standard equation has two squared terms with opposite signs.
- Such uniqueness differentiates it from other conic sections.
Standard Form
The standard form of a hyperbola's equation helps identify and work with these curves effectively.
Standard forms are established equations used to recognize the type of curve without graphing it directly.
For hyperbolas, there are two variations:
Understanding the standard form is critical in graphing hyperbolas and identifying their properties without visual aids.
Standard forms are established equations used to recognize the type of curve without graphing it directly.
For hyperbolas, there are two variations:
- The equation can follow the form: \( \frac{x^{2}}{a^{2}} - \frac{y^{2}}{b^{2}} = 1 \), which describes a hyperbola opening left and right.
- Alternatively, it can be \( \frac{y^{2}}{b^{2}} - \frac{x^{2}}{a^{2}} = 1 \), indicating a hyperbola opening up and down.
Understanding the standard form is critical in graphing hyperbolas and identifying their properties without visual aids.
Equation Rearrangement
Equation rearrangement is an essential skill to match given equations with their standard forms for easier identification. It involves algebraic manipulation to align your given equation to look like classic representations of mathematical concepts.
This process is particularly crucial in conic sections where standard forms provide immediate insights into the graph's characteristics.
Let's break down how this works:
This process is particularly crucial in conic sections where standard forms provide immediate insights into the graph's characteristics.
Let's break down how this works:
- Given an equation like \( \frac{x^{2}}{4} = 1 + \frac{y^{2}}{9} \), rearrangement is necessary.
- Subtract \( \frac{y^{2}}{9} \) from both sides to reformat it as \( \frac{x^{2}}{4} - \frac{y^{2}}{9} = 1 \).
- Now, it follows the standard hyperbola form \( \frac{x^{2}}{a^{2}} - \frac{y^{2}}{b^{2}} = 1 \).
Other exercises in this chapter
Problem 13
Graph each ellipse by hand. Give the domain and range. Give the foci and identify the center. Do not use a calculator. $$9 x^{2}+6 y^{2}=54$$
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For each plane curve, use a graphing calculator to generate the curve over the interval for the parameter \(t\), in the window specified. Then, find a rectangul
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Graph each ellipse by hand. Give the domain and range. Give the foci and identify the center. Do not use a calculator. $$12 x^{2}+8 y^{2}=96$$
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Find the center-radius form for each circle satisfying the given conditions. $$\text { Center }\left(-\frac{1}{2},-\frac{1}{4}\right) ; \text { radius } \frac{1
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