Problem 14
Question
Suppose that \(\int_{0}^{1} f(x) d x=2, \int_{1}^{2} f(x) d x=3, \int_{0}^{1} g(x) d x=-1\), and \(\int_{0}^{2} g(x) d x=4\). Use properties of definite integrals (linearity, interval additivity, and so on) to calculate each of the integrals in Problems 9-16. $$ \int_{1}^{1}[3 f(x)+2 g(x)] d x $$
Step-by-Step Solution
Verified Answer
The integral is 0 due to the zero-length interval property.
1Step 1: Understand the Integral Limits
The integral given is \[ \int_{1}^{1}[3 f(x) + 2 g(x)] dx.\] At first glance, notice that the upper and lower limits of the integral are the same (both are 1). This setup is crucial for solving the problem, because there is a fundamental property of definite integrals which we need to apply.
2Step 2: Apply the Zero-Length Interval Property
Recall the property that if the upper and lower limits of a definite integral are the same, then the value of the integral is 0. Formally stated, for any function \( h(x) \) and any point \( a \), \[\int_{a}^{a} h(x) \, dx = 0.\] Therefore, applying this property directly to our problem: \[\int_{1}^{1}[3 f(x) + 2 g(x)] dx = 0.\] No matter what's inside the brackets, the evaluation is 0 because the bounds are the same.
Key Concepts
Linearity of IntegrationProperties of Definite IntegralsZero-Length Interval Property
Linearity of Integration
Linearity of integration is a fundamental property of definite integrals, which states that the integral of a sum of functions is the sum of their integrals. This property also allows us to factor out constants from the integral sign. In mathematical terms, this means:
By taking each part of the combination separately, we can easily handle complex integrals. It is a very handy tool for mathematicians and is fundamental in calculus.
Understanding linearity is essential because it allows integration to maintain its "additive" nature, keeping calculations straightforward, especially when paired with other integration properties.
- For any two functions, say \( f(x) \) and \( g(x) \), and constants \( a \) and \( b \), the integral of their linear combination is given by:
By taking each part of the combination separately, we can easily handle complex integrals. It is a very handy tool for mathematicians and is fundamental in calculus.
Understanding linearity is essential because it allows integration to maintain its "additive" nature, keeping calculations straightforward, especially when paired with other integration properties.
Properties of Definite Integrals
Definite integrals come with a bundle of useful properties that make computations easier and are valuable when solving real-world problems. Here are some key properties:
- Linearity: As mentioned, it allows for the splitting of the integral of a sum into the sum of integrals, as well as factorization of constants.
- Interval Additivity: This states that if a function is integrated over two adjacent intervals, the result is the sum of the integrals over each interval:
- Symmetry: If a function is symmetric about the y-axis, the integral over a symmetric interval centered on the origin may simplify.
Zero-Length Interval Property
The zero-length interval property of definite integrals is a fascinating and very intuitive concept. It states that if the upper and lower limits of an integral are the same, the integral evaluates to zero:
In practical applications, this property allows us to instantly recognize and solve integrals without needing to perform any detailed calculations when the limits match. It's a key example of how sometimes the absence of movement (along an interval) results in zero, highlighting a fundamental aspect of calculus as it connects to the physical world.
- Symbolically, for any function \( h(x) \) and any point \( a \):
In practical applications, this property allows us to instantly recognize and solve integrals without needing to perform any detailed calculations when the limits match. It's a key example of how sometimes the absence of movement (along an interval) results in zero, highlighting a fundamental aspect of calculus as it connects to the physical world.
Other exercises in this chapter
Problem 14
\(G(v)=\frac{\sin v \cos v}{\sqrt{1+\cos ^{2} v}}, \quad[0, \pi / 2]\)
View solution Problem 14
In Problems \(11-14\), determine an \(n\) so that the Trapezoidal Rule will approximate the integral with an error \(E_{n}\) satisfying \(\left|E_{n}\right| \le
View solution Problem 15
Suppose that \(\sum_{i=1}^{10} a_{i}=40\) and \(\sum_{i=1}^{10} b_{i}=50\). Calculate each of the following. $$ \sum_{i=1}^{10}\left(a_{i}+b_{i}\right) $$
View solution Problem 15
In Problems 15-34, use the method of substitution to find each of the following indefinite integrals. \(\int \sqrt{3 x+2} d x\)
View solution