Problem 14
Question
Suppose \(f: I \rightarrow \mathbb{R}\) is differentiable at \(c \in I .\) Prove there exist numbers a and \(b\) with the property that for every \(\varepsilon>0,\) there is a \(\delta>0,\) such that \(|a+b(x-c)-f(x)| \leq \varepsilon|x-c|,\) whenever \(x \in I\) and \(|x-c|<\delta .\) In other words, show that there exists a function \(g: I \rightarrow \mathbb{R}\) such that \(\lim _{x \rightarrow c} g(x)=0\) and \(|a+b(x-c)-f(x)| \leq|x-c| g(x)\).
Step-by-Step Solution
Verified Answer
Set \(a = f(c)\), \(b = f'(c)\); \(|a+b(x-c)-f(x)| \leq |x-c|g(x)\), with \(g(x) \to 0\) as \(x \to c\).
1Step 1: Understand the problem
We are given that the function \(f\) is differentiable at \(c\) and need to show the existence of numbers \(a\) and \(b\) such that \(|a + b(x-c) - f(x)| \leq \varepsilon|x-c|\) holds for any given \(\varepsilon > 0\). We'll prove this by constructing \(a\) and \(b\), showing how \(f\) can be approximated in terms of a linear function plus a term that vanishes as \(x\) approaches \(c\).
2Step 2: Use the definition of differentiability
From differentiability, we know \(\lim_{x \to c} \frac{f(x) - f(c)}{x-c} = f'(c)\), where \(f'(c)\) is the derivative at point \(c\). This suggests that locally around \(c\), \(f(x)\) behaves like \(f(c) + f'(c)(x-c)\). This linear approximation is crucial to construct the numbers \(a\) and \(b\).
3Step 3: Set the numbers a and b
Let \(a = f(c)\) and \(b = f'(c)\). These values ensure that the linear approximation aligns with the definition of differentiability; thus, we need to show \(|f(c) + f'(c)(x-c) - f(x)| \leq \varepsilon |x-c|\).
4Step 4: Simplify the difference
Calculate the expression \(|a + b(x-c) - f(x)|\) which simplifies to \(|f(c) + f'(c)(x-c) - f(x)|\). This can be rewritten using our understanding from the differentiability condition as the limit operation \(|f'(c)(x-c) - (f(x)-f(c))| \leq \varepsilon |x-c|\).
5Step 5: Introduce a function g(x)
Since \(|f(x) - f(c) - f'(c)(x-c)|\) can be expressed in terms of an error function that quantitatively behaves as \(\lim_{x \to c} \frac{|f(x) - f(c) - f'(c)(x-c)|}{|x-c|} = 0\), we can define \(g(x) = \frac{|f(x) - f(c) - f'(c)(x-c)|}{|x-c|}\). The condition \(\lim_{x \rightarrow c} g(x) = 0\) holds.
6Step 6: Conclude the solution using g(x)
We have \(|f(x) - f(c) - f'(c)(x-c)| = |x-c| g(x)\) with \(\lim_{x \to c} g(x) = 0\). This confirms that \(|a + b(x-c) - f(x)| \leq |x-c| g(x)\) for \(a = f(c)\) and \(b = f'(c)\), satisfying the required condition as \(|x-c| g(x)\) vanishes near \(c\).
Key Concepts
Linear approximationDerivativeLimitError function
Linear approximation
Linear approximation is a way to approximate any function by using a linear function or a straight line. It's particularly useful to understand how a function behaves near a point. Suppose you have a function, and you're curious about its behavior around a certain point. By using linear approximation, you can create a simple linear model.
- A linear approximation is essentially finding a line tangent to the function at that point.
- Mathematically, it's expressed as a line equation: \( L(x) = f(c) + f'(c)(x-c) \).
- This tells us that near the point \(c\), \(f(x)\) is approximately \( f(c) + f'(c)(x-c) \).
Derivative
The derivative of a function at a particular point gives you the slope of the tangent line at that point. This is central to understanding how functions behave as the input values change.
- The derivative is written as \(f'(c)\) and represents the rate of change of the function at \(c\).
- For differentiable functions, this slope tells us the function’s sensitivity to changes in input.
- It's computed as \( \lim_{x \to c} \frac{f(x) - f(c)}{x-c} \).
Limit
Limits provide a way to understand the behavior of functions as inputs get close to a specific value. They help us make sense of values approach — even if the function itself doesn't reach that value.
- Formally, the limit as \(x\) approaches \(c\) is written as \( \lim_{x \rightarrow c} f(x)\).
- They're a core part of defining a derivative.
- If \( \lim_{x \rightarrow c} g(x) = 0 \), it means the function approaches zero as \(x\) gets closer to \(c\).
Error function
In calculus, when approximating a function using a linear approximation, an error term arises. This is called the error function and it measures the difference between the actual function and the linear approximation.
- The error function captures how much the linear approximation deviates from the actual function.
- It is expressed as \( |f(x) - f(c) - f'(c)(x-c)| \).
- By dividing this error by \( |x-c| \), we define a new function \( g(x) = \frac{|f(x) - f(c) - f'(c)(x-c)|}{|x-c|} \).
Other exercises in this chapter
Problem 12
Suppose \(f: I \rightarrow \mathbb{R}, g: I \rightarrow \mathbb{R},\) and \(h: I \rightarrow \mathbb{R},\) are functions. Suppose \(c \in I\) is such that \(f(c
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Prove the following simple version of \(L\) 'Hôpital's rule. Suppose \(f:(a, b) \rightarrow \mathbb{R}\) and \(g:(a, b) \rightarrow \mathbb{R}\) are differentia
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Suppose \(a, b \in \mathbb{R}\) and \(f: \mathbb{R} \rightarrow \mathbb{R}\) is differentiable, \(f^{\prime}(x)=a\) for all \(x\), and \(f(0)=b\). Find \(f\) an
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