Problem 14
Question
Solve each quadratic equation using the method that seems most appropriate to you. $$3 x^{2}-2 x+8=0$$
Step-by-Step Solution
Verified Answer
The roots are \( x = \frac{1 \pm i\sqrt{23}}{3} \).
1Step 1: Identify the Form and Set Up the Equation
The given quadratic equation is in the standard form \( ax^2 + bx + c = 0 \) where \( a = 3 \), \( b = -2 \), and \( c = 8 \). We'll first check if it can be easily factored, but since it includes complex numbers, we'll choose to use the quadratic formula.
2Step 2: Recall the Quadratic Formula
The quadratic formula is \( x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \). We will use this formula to find the roots of the quadratic equation.
3Step 3: Calculate the Discriminant
Calculate the discriminant \( b^2 - 4ac \). Substitute the values: \( (-2)^2 - 4 \cdot 3 \cdot 8 = 4 - 96 = -92 \). The discriminant is negative, indicating that the solutions are complex numbers.
4Step 4: Substitute into the Quadratic Formula
Substitute \( a = 3 \), \( b = -2 \), and \( c = 8 \) into the quadratic formula: \[ x = \frac{-(-2) \pm \sqrt{-92}}{2 \cdot 3} = \frac{2 \pm \sqrt{-92}}{6} \].
5Step 5: Simplify the Expression
Since the discriminant \( -92 \) is negative, write \( \sqrt{-92} = i \cdot \sqrt{92} \), where \( i \) is the imaginary unit. Simplify to get \( x = \frac{2 \pm i \cdot \sqrt{92}}{6} \). Further simplify \( \sqrt{92} \): \( \sqrt{92} = \sqrt{4 \cdot 23} = 2 \cdot \sqrt{23} \). Substitute back: \[ x = \frac{2 \pm 2i\sqrt{23}}{6} = \frac{1 \pm i\sqrt{23}}{3} \].
Key Concepts
Quadratic FormulaComplex NumbersDiscriminantStandard Form of Quadratic Equation
Quadratic Formula
The quadratic formula is a powerful tool for solving quadratic equations, which are equations of the form \( ax^2 + bx + c = 0 \). It allows us to find the roots of these equations, even when they can't be factored easily. The quadratic formula itself is given by:
- \( x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \)
Complex Numbers
Complex numbers are an extension of real numbers and are especially useful in solving equations like quadratics with negative discriminants. A complex number is expressed in the form \( a + bi \), where \( a \) and \( b \) are real numbers, and \( i \) is the imaginary unit with the property \( i^2 = -1 \).
- The real part is \( a \).
- The imaginary part is \( bi \).
Discriminant
The discriminant is a key concept in determining the nature of the roots of a quadratic equation. It is represented by the expression:
- \( b^2 - 4ac \)
- If the discriminant is positive, the equation has two distinct real roots.
- If the discriminant is zero, the equation has exactly one real root (a repeated root).
- If the discriminant is negative, the equation has two complex roots.
Standard Form of Quadratic Equation
The standard form of a quadratic equation is the basis for identifying and solving quadratics. It is written as:
- \( ax^2 + bx + c = 0 \)
- \( a \) is the coefficient of \( x^2 \).
- \( b \) is the coefficient of \( x \).
- \( c \) is the constant term.
Other exercises in this chapter
Problem 13
Add or subtract as indicated. $$(3+2 i)-(5+7 i)$$
View solution Problem 14
Solve each inequality and graph its solution set on a number line. $$\frac{x-1}{x+2}>0$$
View solution Problem 14
Use the quadratic formula to solve each of the quadratic equations. Check your solutions by using the sum and product relationships. $$n^{2}+3 n-2=0$$
View solution Problem 14
Solve each quadratic equation by using (a) the factoring method and (b) the method of completing the square. $$n(n-6)=216$$
View solution