Problem 14
Question
Solve each equation. State the number and type of roots. \(x^{4}-81=0\)
Step-by-Step Solution
Verified Answer
The equation has two real roots (3, -3) and two imaginary roots (3i, -3i).
1Step 1: Rearrange the Equation
The equation given is \(x^4 - 81 = 0\). Rearrange it to isolate \(x^4\) on one side: \(x^4 = 81\).
2Step 2: Apply the Square Root
Take the square root of both sides to simplify \(x^4 = 81\). This gives \((x^2)^2 = 81\). By taking the square root of both sides, we get \(x^2 = 9\) and \(x^2 = -9\).
3Step 3: Solve for \(x^2 = 9\)
For \(x^2 = 9\), take the square root of both sides, leading to \(x = 3\) and \(x = -3\). These are the real roots.
4Step 4: Solve for \(x^2 = -9\)
For \(x^2 = -9\), recognize that the square root of a negative number is imaginary. The solutions are \(x = 3i\) and \(x = -3i\). These are the imaginary roots.
5Step 5: Determine the Number and Type of Roots
The equation has two real roots (3 and -3) and two imaginary roots (3i and -3i). Altogether, the equation has four roots.
Key Concepts
PolynomialsComplex NumbersImaginary RootsReal Roots
Polynomials
Polynomials are expressions that consist of variables and coefficients. These variables are raised to non-negative integer powers. A polynomial equation like \(x^4 - 81 = 0\) involves terms like \(x^4\) and constants like -81.
- The degree of a polynomial is determined by the highest power of the variable in the equation. Here, \(x^4\) indicates a fourth-degree polynomial, as the highest exponent is 4.
- Polynomials can have different types of solutions depending on the degree. For a fourth-degree polynomial, there are generally four solutions — these could be real or complex.
- When solving polynomial equations, especially higher degree ones, factorization or transformations such as applying roots are often used to simplify and find solutions.
Complex Numbers
Complex numbers introduce a way to solve equations that do not have solutions within the set of real numbers. They are numbers of the form \(a + bi\), where \(a\) and \(b\) are real numbers, and \(i\) is the imaginary unit satisfying \(i^2 = -1\).
- Complex numbers extend the real number system. Real numbers are actually a subset of complex numbers where the imaginary part is zero.
- In solving equations, complex numbers allow us to handle roots of negative numbers, which aren't possible within the real number system alone.
- They are crucial in advanced mathematical concepts and in the description of phenomena in engineering and physics, where real and imaginary components are used to model real-life situations.
Imaginary Roots
Imaginary roots arise when we solve equations that require taking the square root of a negative number. In the context of the equation \(x^2 = -9\), the roots are \(x = 3i\) and \(x = -3i\). These solutions are called imaginary because they involve the imaginary unit \(i\).
- An imaginary root always comes in a pair with its conjugate because complex roots are symmetrical about the real axis. If \(3i\) is a root,\(-3i\) must also be a root.
- Imaginary roots do not correspond to a point on the real number line. Instead, they exist in a plane where the real part and the imaginary part define the position of the number.
- They are often used in mathematical calculations to ensure certain types of equations have solutions, thus broadening the applicability of algebraic methods.
Real Roots
Real roots are solutions to a polynomial equation where the roots are real numbers, meaning they do not involve imaginary numbers. For instance, in the equation \(x^2 = 9\), the solutions \(x = 3\) and \(x = -3\) are the real roots.
- Real roots are tangible and existing values on the number line that satisfy the equation.
- When plotting, real roots of an equation correspond to points where the graph intersects the x-axis.
- Real roots can be simple or repeated (multiple). In the given problem, each of the roots \(3\) and \(-3\) is simple, appearing exactly once.
Other exercises in this chapter
Problem 14
For Exercises \(11-18,\) complete each of the following. a. Graph each function by making a table of values. b. Determine the consecutive integer values of \(x\
View solution Problem 14
List all of the possible rational zeros of each function. \(p(x)=3 x^{3}-5 x^{2}-11 x+3\)
View solution Problem 14
Factor completely. If the polynomial is not factorable, write prime. $$ 2 x y^{3}-10 x $$
View solution Problem 14
Simplify. $$ \frac{5 x y^{2}-6 y^{3}+3 x^{2} y^{3}}{x y} $$
View solution