Problem 14
Question
Solve each equation. $$\left|\frac{x+2}{2}\right|=7$$
Step-by-Step Solution
Verified Answer
x = 12 or x = -16
1Step 1 - Understand absolute value
The absolute value of a number represents its distance from zero on the number line, regardless of direction. Therefore, if \(|A| = B\), it means \((A = B)\) or \((A = -B)\).
2Step 2 - Set up two equations
Given \(|\frac{x+2}{2}|=7\), this implies two conditions: \(\frac{x+2}{2}=7\) and \(\frac{x+2}{2}=-7\).
3Step 3 - Solve the first equation
Solve \(\frac{x+2}{2}=7\). Multiply both sides by 2 to get \(x + 2 = 14\). Next, subtract 2 from both sides: \((x = 12)\).
4Step 4 - Solve the second equation
Solve \(\frac{x+2}{2}=-7\). Multiply both sides by 2 to get \(x + 2 = -14\). Next, subtract 2 from both sides: \((x = -16)\).
5Step 5 - State the solutions
The solutions to the equation \(|\frac{x+2}{2}|=7\) are \(x = 12\) and \(x = -16\).
Key Concepts
Understanding Absolute ValueEquation SolvingIntroduction to Precalculus
Understanding Absolute Value
Absolute value is a key concept in mathematics that measures the distance of a number from zero on the number line, without considering direction.
The absolute value is always a non-negative number. For any real number \(x\), the absolute value is denoted as \(|x|\).
For example, \(|3| = 3\) and \(|-3| = 3\), because both 3 and -3 are three units away from zero.
It's crucial to understand that when you solve an absolute value equation like \(|A| = B\), it's equivalent to two separate equations: \A = B\ and \A = -B\. This concept is foundational for solving more complex equations and is often explored in precalculus. When solving absolute value equations, always remember:
The absolute value is always a non-negative number. For any real number \(x\), the absolute value is denoted as \(|x|\).
For example, \(|3| = 3\) and \(|-3| = 3\), because both 3 and -3 are three units away from zero.
It's crucial to understand that when you solve an absolute value equation like \(|A| = B\), it's equivalent to two separate equations: \A = B\ and \A = -B\. This concept is foundational for solving more complex equations and is often explored in precalculus. When solving absolute value equations, always remember:
- Identify the expression inside the absolute value
- Set up two separate equations
- Solve each equation independently
- Check your solutions by substituting them back into the original equation
Equation Solving
Solving equations is one of the most essential skills in mathematics. When you solve an equation, you find the value(s) of the variable that make the equation true.
To solve the given absolute value equation \(|\frac{x + 2}{2}| = 7\), you can break it down into two separate equations based on the definition of absolute value.
1. Equation 1: \frac{x + 2}{2} = 7\
2. Equation 2: \frac{x + 2}{2} = -7\
Let's solve each of these equations step by step.
Starting with Equation 1:
Always verify by substituting each solution back into the original equation to ensure they satisfy the equation.
To solve the given absolute value equation \(|\frac{x + 2}{2}| = 7\), you can break it down into two separate equations based on the definition of absolute value.
1. Equation 1: \frac{x + 2}{2} = 7\
2. Equation 2: \frac{x + 2}{2} = -7\
Let's solve each of these equations step by step.
Starting with Equation 1:
- Multiply both sides by 2: \(x + 2 = 14\)
- Subtract 2 from both sides: \(x = 12\)
- Multiply both sides by 2: \(x + 2 = -14\)
- Subtract 2 from both sides: \(x = -16\)
Always verify by substituting each solution back into the original equation to ensure they satisfy the equation.
Introduction to Precalculus
Precalculus is a course designed to prepare students for calculus and other higher-level math courses.
It combines skills and concepts from algebra and trigonometry. Being good at solving absolute value equations is one of the many essential skills you'll practice.
In precalculus, you'll often encounter equations and inequalities involving absolute values. These problems strengthen your algebraic skills and improve your problem-solving abilities.
Mastering topics in precalculus not only aids in knowing how to work with functions, polynomials, and other algebraic structures, but also equips you with the strategies to tackle complex calculus problems.
To succeed in precalculus, focus on:
It combines skills and concepts from algebra and trigonometry. Being good at solving absolute value equations is one of the many essential skills you'll practice.
In precalculus, you'll often encounter equations and inequalities involving absolute values. These problems strengthen your algebraic skills and improve your problem-solving abilities.
Mastering topics in precalculus not only aids in knowing how to work with functions, polynomials, and other algebraic structures, but also equips you with the strategies to tackle complex calculus problems.
To succeed in precalculus, focus on:
- Understanding the properties of functions
- Mastering trigonometric identities
- Practicing graphing techniques
- Solving various algebraic equations, including absolute value equations
Other exercises in this chapter
Problem 14
Identify each number as real, complex, pure imaginary, or nonreal complex. (More than one of these descriptions will apply. ) $$\sqrt{24}$$
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Use the following facts. If \(x\) represents an integer, then \(x+1\) represents the next consecutive integer. If \(x\) represents an even integer, then \(x+2\)
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Solve each inequality. Write each solution set in interval notation. $$-3 x-8 \leq 7$$
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Solve each equation. $$\frac{7}{4}+\frac{1}{5} x-\frac{3}{2}=\frac{4}{5} x$$
View solution