Problem 14
Question
Sketch the graph of the function by first making a table of values. \(g(x)=(x-3)^{2}\)
Step-by-Step Solution
Verified Answer
The graph is a symmetric parabola with vertex at (3, 0).
1Step 1: Choose x-values
To graph the function, start by selecting a range of x-values. A good range might be from -2 to 8 to capture the behavior around the vertex.
2Step 2: Calculate Corresponding y-values
Use the function \(g(x) = (x-3)^2\) to calculate the y-values for your chosen x-values. Perform the calculations as follows:\[\begin{align*}g(-2) &= (-2-3)^2 = 25,\g(-1) &= (-1-3)^2 = 16,\g(0) &= (0-3)^2 = 9,\g(1) &= (1-3)^2 = 4,\g(2) &= (2-3)^2 = 1,\g(3) &= (3-3)^2 = 0,\g(4) &= (4-3)^2 = 1,\g(5) &= (5-3)^2 = 4,\g(6) &= (6-3)^2 = 9,\g(7) &= (7-3)^2 = 16,\g(8) &= (8-3)^2 = 25.\end{align*}\]
3Step 3: Create the Table of Values
List the x-values and their corresponding y-values in a table:\[\begin{array}{c|c}x & g(x) \\hline-2 & 25 \-1 & 16 \0 & 9 \1 & 4 \2 & 1 \3 & 0 \4 & 1 \5 & 4 \6 & 9 \7 & 16 \8 & 25 \\end{array}\]
4Step 4: Plot the Points
On a graph, plot each pair of \( (x, g(x)) \) points from the table. For example, plot the following points: \((-2, 25), (-1, 16), (0, 9), (1, 4), (2, 1), (3, 0), (4, 1), (5, 4), (6, 9), (7, 16), (8, 25)\).
5Step 5: Draw the Graph
Connect the plotted points smoothly to reveal the parabola. The vertex of the parabola is at \(x = 3\) and \(g(3) = 0\), and you'll see the graph is symmetrical around this point with arms extending upwards.
Key Concepts
Graphing ParabolasVertex of a ParabolaTable of Values
Graphing Parabolas
Graphing parabolas can be straightforward once you understand the basic structure of this type of function. A parabola is the graph of a quadratic function, which is typically in the form of - \(y = ax^2 + bx + c\), where \(a\), \(b\), and \(c\) are constants. The simplest form, like our function \(g(x) = (x-3)^2\), actually comes in the shape \(y = (x-h)^2 + k\). This is called vertex form,- where \(h\) and \(k\) dictate the parabola's vertex. To graph a parabola, you first need to create a collection of points that lie on the function. - These are determined using x-values input into the function to obtain y-values. You then- plot these coordinate points - and draw a smooth curve through them to visualize the parabola. Remember:
- Parabolas are symmetrical. Whatever you calculate on one side of the vertex mirrors on the other side.
- The direction the parabola opens (upwards or downwards) is defined by the sign of \(a\). For example, if \(a\) is positive, it opens upwards."
Vertex of a Parabola
The vertex of a parabola is a crucial point. It represents either the highest point in a parabola that opens downward or the lowest point for one that opens upward. In the vertex form of a quadratic function, which is \(y = (x-h)^2 + k\), the vertex is simply the point \((h, k)\).- For the function \(g(x) = (x-3)^2\), the parabola's vertex is at the point \((3, 0)\).To locate the vertex:
- Identify the value of \(h\) that shifts the graph left or right.
- Determine the value of \(k\) to understand how far up or down the graph is shifted.
Table of Values
Creating a table of values is a helpful step in graphing a quadratic function like a parabola. This process involves selecting a set of x-values and computing the corresponding y-values using the function equation.For instance, using the function \(g(x) = (x-3)^2\), you can select x-values such as -2, -1, 0, 1, 2, 3, etc.For each x-value chosen, substitute it into the function to find the y-value,- giving a pair \((x, g(x))\). These pairs form coordinate points to be plotted on a graph. Examples include:
- \((-2, 25)\)
- \((3, 0)\)
- \((8, 25)\)
Other exercises in this chapter
Problem 14
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