Problem 14
Question
Simplify the quantities using \(m(z)=z^{2}\). $$m(z+1)-m(z)$$
Step-by-Step Solution
Verified Answer
The simplified expression is \(2z + 1\).
1Step 1: Apply the function to the expression
We are given the function \(m(z) = z^2\) and asked to simplify \(m(z + 1) - m(z)\). Start by applying \(m\) to \(z+1\):\[ m(z+1) = (z+1)^2. \]
2Step 2: Expand the squared term
Expand \((z+1)^2\) using the formula \((a+b)^2 = a^2 + 2ab + b^2\). Here \(a=z\) and \(b=1\):\[ (z+1)^2 = z^2 + 2z + 1. \]
3Step 3: Substitute in Original Expression
Substitute \(m(z+1) = z^2 + 2z + 1\) and \(m(z) = z^2\) into the expression \(m(z+1) - m(z)\):\[ m(z+1) - m(z) = (z^2 + 2z + 1) - z^2. \]
4Step 4: Simplify the Expression
Simplify the expression by canceling out the \(z^2\) terms:\[ (z^2 + 2z + 1) - z^2 = 2z + 1. \]
Key Concepts
Function SimplificationAlgebraic ExpressionsBinomial Expansion
Function Simplification
Function simplification is the process of making expressions more straightforward, removing unnecessary complexity while maintaining their original value. In mathematics, especially in algebra, simplification helps us better understand the behavior of functions. It makes it easier to identify patterns and perform calculations.
- In the exercise, we started with a complex expression: \( m(z+1) - m(z) \). This expression involves applying a function to different arguments and then finding the difference between the outcomes.
- The function given, \( m(z) = z^2 \), suggests we're dealing with squares. Instead of directly substituting and calculating, simplifying reveals underlying relationships.
Algebraic Expressions
Algebraic expressions are a foundational concept in mathematics, representing quantities with variables, constants, and operations like addition and multiplication. They are essentially math phrases that can be simplified, expanded, or evaluated. Consider the expression \( z^2 + 2z + 1 \), an algebraic expression representing the square of \( (z+1) \).
- Each part of an expression, such as \( z^2 \), represents a term. Terms can be either constant, a variable raised to a power, or a product of both.
- The expression is often transformed through processes like expansion, distributive property application, or simplification to make it more manageable.
Binomial Expansion
Binomial expansion deals with expanding expressions that involve the sum of two terms raised to a power, such as \( (z+1)^2 \). The expansion uses the binomial theorem, a powerful tool in algebra, especially useful in transforming expressions into easier-to-handle forms.
- The basic binomial formula \( (a + b)^2 = a^2 + 2ab + b^2 \) allows for quick expansion of the square terms. This identity reveals the structure of multiplication in terms of addition and exponentially distributed terms.
- In the exercise, applying the formula to \( (z+1)^2 \) unfolds the original expression into \( z^2 + 2z + 1 \), which simplifies understanding and further manipulation.
Other exercises in this chapter
Problem 14
In Exercises \(10-15,\) give \(\lim _{x \rightarrow-\infty} f(x)\) and \(\lim _{x \rightarrow+\infty} f(x)\). $$f(x)=8 x^{-3}$$
View solution Problem 14
In Exercises \(11-16,\) which function dominates as \(x \rightarrow \infty ?\) $$2 x^{4} \quad \text { or } \quad 10 x^{3}+25 x^{2}+50 x+100$$
View solution Problem 14
Solve for \(x\) using logs. $$2 e^{3 x}=4 e^{5 x}$$
View solution Problem 15
In Exercises \(10-15,\) give \(\lim _{x \rightarrow-\infty} f(x)\) and \(\lim _{x \rightarrow+\infty} f(x)\). $$f(x)=25 e^{0.08 x}$$
View solution