Problem 14
Question
Simplify each expression. $$ \sqrt{28} $$
Step-by-Step Solution
Verified Answer
\( \sqrt{28} = 2 \sqrt{7} \)
1Step 1: Identify Perfect Square Factors
To simplify \( \sqrt{28} \), start by identifying the largest perfect square factor of 28. The factors of 28 are 1, 2, 4, 7, 14, and 28. Among them, 4 is the largest perfect square.
2Step 2: Rewrite the Radical Using Perfect Square Factor
Express 28 as a product of its factors, where one factor is the perfect square identified in Step 1. That is, \( 28 = 4 \times 7 \). Therefore, we can rewrite the radical as \( \sqrt{28} = \sqrt{4 \times 7} \).
3Step 3: Simplify the Radical
Use the property of square roots that states \( \sqrt{a \times b} = \sqrt{a} \times \sqrt{b} \). Apply this to \( \sqrt{4 \times 7} = \sqrt{4} \times \sqrt{7} \). Since \( \sqrt{4} = 2 \), this simplifies to \( 2 \sqrt{7} \).
4Step 4: Write the Simplified Expression
The final simplified form of \( \sqrt{28} \) is \( 2 \sqrt{7} \).
Key Concepts
Perfect SquaresSquare RootsAlgebraic Expressions
Perfect Squares
A perfect square is an integer that is the square of another integer. Think of it as a number that can be neatly arranged into a square shape. For example:
- 1 is a perfect square because it is 1 squared.
- 4 is a perfect square as it is 2 squared.
- 9 is a perfect square, being 3 squared.
Square Roots
The square root of a number is a value that, when multiplied by itself, gives the original number. For instance, the square root of 16 is 4 since 4 times 4 equals 16. Square roots are represented by the radical sign \(\sqrt{}\). In any radical expression, it’s important to identify if the number has any perfect square factors, as these simplify the expression.
In the example \(\sqrt{28}\), we break it down using its perfect square factor 4. By expressing 28 as \(4 \times 7\), we use the property \(\sqrt{a \times b} = \sqrt{a} \times \sqrt{b}\) to simplify. Thus, \(\sqrt{28} = \sqrt{4} \times \sqrt{7} = 2 \sqrt{7}\). This simplification process is essential in algebra, assisting in dealing with complex expressions more easily.
In the example \(\sqrt{28}\), we break it down using its perfect square factor 4. By expressing 28 as \(4 \times 7\), we use the property \(\sqrt{a \times b} = \sqrt{a} \times \sqrt{b}\) to simplify. Thus, \(\sqrt{28} = \sqrt{4} \times \sqrt{7} = 2 \sqrt{7}\). This simplification process is essential in algebra, assisting in dealing with complex expressions more easily.
Algebraic Expressions
Algebraic expressions can include numbers, variables, and arithmetic operations. Simplifying these expressions often involves reducing radicals, which necessitates recognizing perfect squares and computing square roots. When dealing with expressions like \(\sqrt{28}\), it’s crucial to rewrite the expression in its simplest form.
Start by identifying perfect square factors, then decompose the expression. After simplifying, you're left with an expression that maintains its original value while being easier to understand and use in further calculations.
Start by identifying perfect square factors, then decompose the expression. After simplifying, you're left with an expression that maintains its original value while being easier to understand and use in further calculations.
- Rearranging terms and breaking down the radicals is a common approach.
- This includes using properties such as \(\sqrt{a \times b} = \sqrt{a} \times \sqrt{b}\).
Other exercises in this chapter
Problem 14
Complete each solution. $$ \begin{aligned} \frac{3}{2-i} &=\frac{3}{2-i} \cdot \\ &=\frac{6+}{4-} \\ &=\frac{6+3 i}{5} i \\ &=-+\frac{3}{5} \end{aligned} $$
View solution Problem 14
Fill in the blanks. \(\sqrt[3]{x}=y \text { if } y^{3}=\)
View solution Problem 14
Solve \(8^{2}+4^{2}=c^{2}\) and assume \(c>0 .\) Approximate to two decimal places. (EQUATION CAN'T COPY)
View solution Problem 15
Multiply and simplify. All variables represent positive real numbers. $$ \sqrt{3} \sqrt{15} $$
View solution