Problem 14
Question
Salicylic acid pharmacokinetics In the study cited in Example \(5,\) the metabolite salicylic acid (SA) was rapidly formed and peak SA levels of about 4.2\(\mu g / m L\) were reached after an hour. The concentration of SA was modeled by the function $$C(t)=11.4 t e^{-t}$$ where \(t\) is measured in hours and \(C\) is measured in \(\mu \mathrm{g} / \mathrm{mL}\) . Use the Midpoint Rule with eight subintervals to estimate the integral \(\int_{0}^{4} C(t) d t .\) State the units.
Step-by-Step Solution
Verified Answer
The estimated integral is 12.15 \(\mu g \, \text{mL}^{-1} \, \text{hours}\).
1Step 1: Determine the Interval Length
We want to estimate the integral \( \int_{0}^{4} C(t) \, dt \) using the Midpoint Rule with 8 subintervals. First, we determine the width of each subinterval. The whole interval length is \([0, 4]\). Thus, the interval length per subinterval, \( \Delta t \), is: \[ \Delta t = \frac{b-a}{n} = \frac{4-0}{8} = 0.5. \]
2Step 2: Identify Midpoints of Each Subinterval
To apply the Midpoint Rule, we need the midpoints of each subinterval. Since \( \Delta t = 0.5 \), the subintervals are \([0, 0.5], [0.5, 1], \ldots, [3.5, 4]\). The midpoints are \(0.25, 0.75, 1.25, \ldots, 3.75\).
3Step 3: Evaluate the Function at Midpoints
Calculate the function \(C(t) = 11.4t e^{-t}\) at each midpoint. - \(C(0.25) = 11.4(0.25)e^{-0.25}\),- \(C(0.75) = 11.4(0.75)e^{-0.75}\),- \(C(1.25) = 11.4(1.25)e^{-1.25}\),- \(C(1.75) = 11.4(1.75)e^{-1.75}\),- \(C(2.25) = 11.4(2.25)e^{-2.25}\),- \(C(2.75) = 11.4(2.75)e^{-2.75}\),- \(C(3.25) = 11.4(3.25)e^{-3.25}\),- \(C(3.75) = 11.4(3.75)e^{-3.75}\).
4Step 4: Apply the Midpoint Rule Formula
The Midpoint Rule estimates the integral by calculating: \[ \int_{0}^{4} C(t) \, dt \approx \Delta t \sum_{i=1}^{n} C(\text{midpoint}_i) \]Plugging in the values:\[ \int_{0}^{4} C(t) \, dt \approx 0.5 \times (C(0.25) + C(0.75) + C(1.25) + C(1.75) + C(2.25) + C(2.75) + C(3.25) + C(3.75)) \]
5Step 5: Calculate and Sum the Function Values
Using a calculator, find the values:- \(C(0.25) \approx 2.44\),- \(C(0.75) \approx 4.48\),- \(C(1.25) \approx 4.63\),- \(C(1.75) \approx 3.83\),- \(C(2.25) \approx 3.07\),- \(C(2.75) \approx 2.44\),- \(C(3.25) \approx 1.92\),- \(C(3.75) \approx 1.49\).Sum these values: \\(2.44 + 4.48 + 4.63 + 3.83 + 3.07 + 2.44 + 1.92 + 1.49 = 24.30 \).
6Step 6: Calculate the Final Estimate
Multiply the sum by the subinterval length, \( \Delta t = 0.5 \):\[ \int_{0}^{4} C(t) \, dt \approx 0.5 \times 24.30 = 12.15 \]Thus, the estimated integral is \(12.15\), with units of \(\mu g \, \text{mL}^{-1} \, \text{hours}\).
Key Concepts
Salicylic Acid PharmacokineticsIntegral EstimationCalculus in Life Sciences
Salicylic Acid Pharmacokinetics
Pharmacokinetics is the branch of pharmacology that studies how drugs flow through the body over time. It involves understanding the processes of absorption, distribution, metabolism, and excretion of substances. Salicylic acid (SA) is a well-known compound used in many medical treatments, including skincare products for its exfoliating properties. When studying SA pharmacokinetics, it's essential to measure how concentrations change in the bloodstream after a person takes the medication.
In this particular case, the concentration of SA was modeled using the function \(C(t) = 11.4 t e^{-t}\), which describes how SA concentration changes over time \(t\). The peak levels of SA were measured at around 4.2 µg/mL after one hour. Such information is crucial for understanding the efficacy and duration of the drug's action. In real-life pharmaceutical applications, this understanding informs dosages and scheduling to optimize therapeutic effects while minimizing side effects.
In summary, pharmacokinetic modeling provides invaluable insights into drug behavior within the body, helping improve decision-making in medicine and therapy design.
In this particular case, the concentration of SA was modeled using the function \(C(t) = 11.4 t e^{-t}\), which describes how SA concentration changes over time \(t\). The peak levels of SA were measured at around 4.2 µg/mL after one hour. Such information is crucial for understanding the efficacy and duration of the drug's action. In real-life pharmaceutical applications, this understanding informs dosages and scheduling to optimize therapeutic effects while minimizing side effects.
In summary, pharmacokinetic modeling provides invaluable insights into drug behavior within the body, helping improve decision-making in medicine and therapy design.
Integral Estimation
Calculating integrals numerically rather than analytically can sometimes be necessary—particularly when dealing with complex functions. Estimating an integral means approximating the area under a curve for a certain range, without setting up intricate equations or transformations, making it more practical for real-world applications.
The Midpoint Rule is a method for estimating the integral of a function over an interval by dividing this interval into several subintervals. Then, it uses the value of the function at the midpoint of each subinterval to approximate the area under the curve. To do this, you calculate the area of rectangles formed by these midpoints. For the integral \(\int_{0}^{4} C(t) \, dt\), divided by 8 subintervals, this involves calculating the function \(C(t)\) at midpoints like 0.25, 0.75, etc.
This approach, though an estimation, is often sufficient for practical purposes such as calculating drug concentrations in the bloodstream where exact values aren't always necessary. It provides a neat and relatively simple method to handle real-world problems where precise calculation is either too complex or unnecessary.
The Midpoint Rule is a method for estimating the integral of a function over an interval by dividing this interval into several subintervals. Then, it uses the value of the function at the midpoint of each subinterval to approximate the area under the curve. To do this, you calculate the area of rectangles formed by these midpoints. For the integral \(\int_{0}^{4} C(t) \, dt\), divided by 8 subintervals, this involves calculating the function \(C(t)\) at midpoints like 0.25, 0.75, etc.
This approach, though an estimation, is often sufficient for practical purposes such as calculating drug concentrations in the bloodstream where exact values aren't always necessary. It provides a neat and relatively simple method to handle real-world problems where precise calculation is either too complex or unnecessary.
Calculus in Life Sciences
Calculus serves as an invaluable tool in the life sciences, ranging from modeling population dynamics to analyzing biological data and processes. One area where calculus shines is in pharmacokinetics, where it helps researchers determine drug concentration over time, as seen with salicylic acid.
Through differential equations and integral calculus, researchers can model the absorption and elimination phases of drugs, which is crucial in determining appropriate dosages for patients. Beyond pharmacokinetics, calculus helps with modeling ecosystems, calculating rates of enzyme reactions, or understanding changes in heart rates or blood flow.
By applying calculus, life scientists unpack complex phenomena, often illustrating how one variable affects another in dynamic biological systems. This rigorous approach paves the way for better predictions, improved treatments, and a deeper understanding of nature.
Through differential equations and integral calculus, researchers can model the absorption and elimination phases of drugs, which is crucial in determining appropriate dosages for patients. Beyond pharmacokinetics, calculus helps with modeling ecosystems, calculating rates of enzyme reactions, or understanding changes in heart rates or blood flow.
By applying calculus, life scientists unpack complex phenomena, often illustrating how one variable affects another in dynamic biological systems. This rigorous approach paves the way for better predictions, improved treatments, and a deeper understanding of nature.
Other exercises in this chapter
Problem 14
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Make a substitution to express the integrand as a rational function and then evaluate the integral. $$\int_{9}^{16} \frac{\sqrt{x}}{x-4} d x$$
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Determine whether each integral is convergent or divergent. Evaluate those that are convergent. \(\int_{0}^{\infty} s e^{-5 s} d s\)
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