Problem 14
Question
Let \(\left\\{x_{n}\right\\}\) be a sequence. a) Show that \(\lim x_{n}=\infty\) if and only if \(\liminf x_{n}=\infty\). b) Then show that \(\lim x_{n}=-\infty\) if and only if limsup \(x_{n}=-\infty\). c) If \(\left\\{x_{n}\right\\}\) is monotone increasing, show that either \(\lim x_{n}\) exists and is finite or \(\lim x_{n}=\infty .\) In either case, \(\lim x_{n}=\sup \left\\{x_{n}: n \in \mathbb{N}\right\\}\)
Step-by-Step Solution
Verified Answer
Prove \(\lim x_n = \infty\) if \(\liminf x_n = \infty\), \(\lim x_n = -\infty\) if \(\limsup x_n = -\infty\), and \(\lim x_n = \sup \{x_n\}\) for increasing sequences.
1Step 1: Understanding Terms
Begin by understanding the definitions of \(\lim, \limsup, \liminf, \to \infty, \to -\infty\) for sequences. The limit of a sequence \(\{x_n\}\) approaches \(\infty\) if for every constant \(M\), there is an index \(N\) such that for all \(n > N\), \(x_n > M\). \(\limsup x_n\) is the greatest limit point, and \(\liminf x_n\) is the smallest limit point of the sequence \(\{x_n\}\).
2Step 2a: Prove that \(\lim x_n = \infty \implies \liminf x_n = \infty\)
If \(\lim x_n = \infty\), then for every \(M\), there exists \(N\) such that for all \(n > N\), \(x_n > M\). This means that no terms are below any finite number for sufficiently large \(n\), hence \(\liminf x_n = \infty\).
3Step 2b: Prove that \(\liminf x_n = \infty \implies \lim x_n = \infty\)
Assume \(\liminf x_n = \infty\). For every \(M\), there exists \(N\) such that for all \(n > N\), \(x_n > M\), confirming that \(\lim x_n = \infty\). Thus, both \(\lim x_n = \infty\) and \(\liminf x_n = \infty\) are equivalent.
4Step 3a: Prove that \(\lim x_n = -\infty \implies \limsup x_n = -\infty\)
If \(\lim x_n = -\infty\), then for every constant \(M\), there exists \(N\) such that for all \(n > N\), \(x_n < M\). Therefore, \(\limsup x_n < M\) for all finite \(M\), which implies \(\limsup x_n = -\infty\).
5Step 3b: Establish \(\limsup x_n = -\infty \implies \lim x_n = -\infty\)
If \(\limsup x_n = -\infty\), for every \(M\), there exists \(N\) such that for all \(n > N\), \(x_n < M\). This implies \(\lim x_n = -\infty\). Therefore, both \(\lim x_n = -\infty\) and \(\limsup x_n = -\infty\) are equivalent.
6Step 4: Analyze Monotone Increasing Sequences
For a monotone increasing sequence \(\{x_n\}\), if the sequence is bounded above, it converges to a finite limit. Otherwise, it diverges to \(\infty\). Either case establishes \(\lim x_n = \sup \{x_n : n \in \mathbb{N}\}\). The supremum, without an upper bound, is \(\infty\).
Key Concepts
Monotone Increasing SequencesLiminf and LimsupDivergence to Infinity
Monotone Increasing Sequences
A sequence is called **monotone increasing** if each term is at least as large as the term before it. Simply put, as you move forward in the sequence, the numbers never decrease. This property helps us make conclusive statements about its limit.
There are two possible behaviors for a monotone increasing sequence:
There are two possible behaviors for a monotone increasing sequence:
- If the sequence is bounded above, meaning there's a specific number that the sequence never exceeds, it must converge. This means as you add more and more terms, they get closer to some fixed, finite number.
- If it's not bounded above, the sequence will increase without end, diverging to infinity.
Liminf and Limsup
The concepts of **liminf** and **limsup** help us capture the behavior of sequences, particularly when conveying their long-term behavior is tricky with a simple limit.
Here's a simplified explanation:
Here's a simplified explanation:
- **Liminf (Limit Inferior):** It's the greatest lower bound for the limits of subsequences. Practically, it tells us the smallest value that our sequence can "settle" around as it progresses.
- **Limsup (Limit Superior):** This is the smallest upper limit for the limits of subsequences. In essence, it pinpoints the largest value that our sequence can "approach" over time.
Divergence to Infinity
When we say a sequence **diverges to infinity**, it grows larger and larger without bound. Imagine counting numbers; they keep getting bigger without ever stopping.
This is exactly what happens when a sequence's limit is infinity. Here's how you can visualize it:
This is exactly what happens when a sequence's limit is infinity. Here's how you can visualize it:
- **Infinite Growth:** For any number you can think of, no matter how large, the sequence eventually surpasses it. So, if someone gives you a massive number \(M\), there will be a point in the sequence (let's call it \(N\)) where every term after \(N\) is larger than \(M\).
- **Consistent Increase:** No matter how big \(n\) becomes, the terms \(x_n\) grow without restriction. The sequence doesn't "settle" around any fixed number but keeps moving upward.
Other exercises in this chapter
Problem 14
Suppose \(x_{1}:=c\) and \(x_{n+1}:=x_{n}^{2}+x_{n} .\) Show that \(\left\\{x_{n}\right\\}\) converges if and only if \(-1 \leq c \leq 0,\) in which case it con
View solution Problem 14
Suppose \(\left\\{c_{n}\right\\}\) is any sequence. Prove that for any \(r \in(0,1)\) there exists a strictly increasing sequence \(\left\\{n_{k}\right\\}\) of
View solution Problem 14
Find a convergent subsequence of the sequence \(\left\\{(-1)^{n}\right\\}\).
View solution Problem 15
Prove \(\lim _{n \rightarrow \infty}\left(n^{2}+1\right)^{1 / n}=1\)
View solution