Problem 14
Question
Jupiter's orbital period Estimate the orbital period of Jupiter, assuming that \(a=77.8 \times 10^{10} \mathrm{m} .\)
Step-by-Step Solution
Verified Answer
Jupiter's orbital period is approximately 11.85 years.
1Step 1: Understanding Astronomical Units and Kepler's Third Law
Jupiter's orbital period can be estimated using Kepler's Third Law, which relates the orbital period and the semi-major axis of a planet's orbit. Kepler's Third Law is stated as \( T^2 = k imes a^3 \), where \( T \) is the orbital period, \( a \) is the semi-major axis, and \( k \) is a constant.
2Step 2: Using Kepler's Third Law for Planetary Orbits
For simplicity, we can use a version of Kepler's Third Law that applies to the solar system: \( T^2 = a^3 \) when \( T \) is in years and \( a \) is in astronomical units (AU). Note that \( 1 \, AU \approx 1.496 imes 10^{11} \text{ m} \).
3Step 3: Convert Jupiter's Semi-Major Axis to Astronomical Units
Jupiter's semi-major axis \( a = 77.8 imes 10^{10} \text{ m} \). Converting this to astronomical units: \( a = \frac{77.8 imes 10^{10}}{1.496 imes 10^{11}} \approx 5.2 \text{ AU} \).
4Step 4: Apply Kepler's Third Law
With \( a = 5.2 \text{ AU} \), substitute into Kepler's Third Law: \( T^2 = 5.2^3 \). Calculating, \( T^2 = 140.608 \).
5Step 5: Solve for the Orbital Period
Take the square root to find the orbital period \( T \): \( T = \sqrt{140.608} \approx 11.85 \text{ years} \).
Key Concepts
Orbital PeriodSemi-Major AxisAstronomical Units
Orbital Period
An orbital period refers to the time it takes for a celestial object, like a planet, to complete a full orbit around another object, such as the Sun. In the case of planets in our solar system, the orbital period is often measured in Earth years. Understanding the orbital period is crucial for many astronomical calculations, as it gives insight into the dynamics of celestial mechanics.
For example, to find Jupiter's orbital period, we use Kepler's Third Law, which relates the orbital period to the semi-major axis of an orbit. This allows astronomers to predict how long it takes different planets to travel around the Sun.
In the context of Jupiter, after converting its semi-major axis to astronomical units, you can calculate:
For example, to find Jupiter's orbital period, we use Kepler's Third Law, which relates the orbital period to the semi-major axis of an orbit. This allows astronomers to predict how long it takes different planets to travel around the Sun.
In the context of Jupiter, after converting its semi-major axis to astronomical units, you can calculate:
- The cube of the semi-major axis: 100.608.
- The square root to find the orbital period in years, which gives us approximately 11.85 years.
Semi-Major Axis
The semi-major axis is one of the most important parameters in an elliptical orbit, describing half of the longest diameter across the ellipse. It essentially defines the size of the orbit in which a planet travels around the Sun.
For planets, the semi-major axis is measured in astronomical units (AU), which simplifies calculations since one AU is the average distance from Earth to the Sun. In this exercise, Jupiter's semi-major axis is given, and converting it from meters to AU is a necessary step to apply Kepler's Third Law easily.
Here’s how the process works:
For planets, the semi-major axis is measured in astronomical units (AU), which simplifies calculations since one AU is the average distance from Earth to the Sun. In this exercise, Jupiter's semi-major axis is given, and converting it from meters to AU is a necessary step to apply Kepler's Third Law easily.
Here’s how the process works:
- First, convert the semi-major axis given in meters to astronomical units. For Jupiter, this involves dividing the semi-major axis in meters by the length of an AU in meters, approximately 1.496 x 10^{11} m.
- Jupiter's calculated semi-major axis of about 5.2 AU highlights the extensive distance from the Sun, compared to Earth's 1 AU, explaining why Jupiter has a longer orbital period.
Astronomical Units
An Astronomical Unit (AU) is a unit of measurement used to describe distances within our solar system. Defined as the average distance from Earth to the Sun, one AU is roughly equivalent to 149.6 million kilometers or 1.496 x 10^{11} meters.
Using AUs in calculations provides a way to express huge distances more conveniently without dealing with excessively large numbers. This unit is particularly handy when applying Kepler's Third Law, as it simplifies equations and reduces complex numbers.
Here's why AU is essential in this exercise:
Using AUs in calculations provides a way to express huge distances more conveniently without dealing with excessively large numbers. This unit is particularly handy when applying Kepler's Third Law, as it simplifies equations and reduces complex numbers.
Here's why AU is essential in this exercise:
- By converting Jupiter's semi-major axis from meters to AUs, the calculations using Kepler's Third Law become straightforward. The comparison to Earth's orbit facilitates understanding of relative distances and periods in the solar system.
- Jupiter, with a semi-major axis of about 5.2 AU, showcases its vast distance compared to Earth's 1 AU, providing insight into its longer orbital period of approximately 11.85 years.
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