Problem 14
Question
Indicate whether the given series converges or diverges. If it converges, find its sum. Hint: It may help you to write out the first few terms of the series $$ \sum_{k=6}^{\infty} \frac{2}{k-5} $$
Step-by-Step Solution
Verified Answer
The series diverges.
1Step 1: Identify Series Type
The given series is \( \sum_{k=6}^{\infty} \frac{2}{k-5} \). Notice that this looks like a harmonic series but shifted starting from \( k-6 \). To clarify, write a few initial terms: for \( k=6 \), \( \frac{2}{6-5}=2 \); for \( k=7 \), \( \frac{2}{7-5}=1 \); for \( k=8 \), \( \frac{2}{8-5}=\frac{2}{3} \). This is a divergent harmonic series with a constant multiplication of 2.
2Step 2: Comparison with Harmonic Series
The series can be rewritten as \( 2 \times \sum_{n=1}^{\infty} \frac{1}{n} \) after substituting \( n = k - 5 \). The harmonic series \( \sum_{n=1}^{\infty} \frac{1}{n} \) is known to diverge. Since we are multiplying by a constant, the divergence remains the same.
3Step 3: Apply Divergence Test
According to the divergence test, if the terms of a series do not tend to zero, the series diverges. Here, for each term \( \frac{2}{k-5} \), it approaches zero as \( k \) tends towards infinity, but since the series is effectively the harmonic series, as seen from previous reasoning, we can confirm the series diverges by comparison.
4Step 4: Conclusion
The given series \( \sum_{k=6}^{\infty} \frac{2}{k-5} \) diverges because it is equivalent to a divergent harmonic series multiplied by a constant factor.
Key Concepts
Divergence TestHarmonic SeriesInfinite SeriesComparison Test
Divergence Test
The divergence test is a simple and effective tool to determine whether a series diverges.
It comes into play with series like the one in the exercise, where we need to establish if the series diverges right at the beginning.
To apply the divergence test, you essentially look at the individual terms of the series. If the limit of the terms does not approach zero as the series progresses towards infinity, then the series must diverge.
This makes logical sense; if the terms of a series do not vanish to zero, the series cannot reasonably settle on a finite sum.
Even when terms do approach zero, this test alone isn't a guarantee of convergence; it's merely a quick way to rule out any possible convergence when they fail to vanish.
It comes into play with series like the one in the exercise, where we need to establish if the series diverges right at the beginning.
To apply the divergence test, you essentially look at the individual terms of the series. If the limit of the terms does not approach zero as the series progresses towards infinity, then the series must diverge.
This makes logical sense; if the terms of a series do not vanish to zero, the series cannot reasonably settle on a finite sum.
Even when terms do approach zero, this test alone isn't a guarantee of convergence; it's merely a quick way to rule out any possible convergence when they fail to vanish.
- Check if \(\lim_{{k \to \infty}} a_k = 0\).
- If not, series diverges.
- If yes, further tests needed.
Harmonic Series
The harmonic series is a fundamental concept when studying series convergence. It's represented by \( \sum_{n=1}^{\infty} \frac{1}{n} \).
The series is fascinating because it diverges despite the terms tending towards zero.
In easier terms, as we go further along the series, the terms get smaller—but not small enough quickly enough to sum up to a finite number.
This characteristic leads to the harmonic series being known famously for its divergence.
The series is fascinating because it diverges despite the terms tending towards zero.
In easier terms, as we go further along the series, the terms get smaller—but not small enough quickly enough to sum up to a finite number.
This characteristic leads to the harmonic series being known famously for its divergence.
- Terms: \( \frac{1}{1}, \frac{1}{2}, \frac{1}{3}, \ldots \)
- Nature: Diverges uniquely because terms shrink too slowly.
Infinite Series
An infinite series is, at its core, the sum of infinitely many terms. These series can be bewildering because they potentially carry on forever, but can still sometimes add up to a finite value.
The fundamental concern with infinite series is understanding when they converge to a sum.The most straightforward of infinite series are geometric and arithmetic series, but many other forms exist, like harmonic series as mentioned above.
The fundamental concern with infinite series is understanding when they converge to a sum.The most straightforward of infinite series are geometric and arithmetic series, but many other forms exist, like harmonic series as mentioned above.
- Composition: Involves endless terms.
- Behavior: Can converge or diverge.
- Goal: Identify overall trends, whether finite sum exists.
Comparison Test
The comparison test offers a methodical way to evaluate series by comparing it to another reference series whose behavior we understand better.
In application, you compare the series’ terms against terms of another known series—usually one with comparable growth rates or structures—and decipher its convergence or divergence accordingly.
It's an effective shortcut, bypassing longer verbal reasoning by leveraging prior established knowledge.
In application, you compare the series’ terms against terms of another known series—usually one with comparable growth rates or structures—and decipher its convergence or divergence accordingly.
- Purpose: Determines match or divergence based on familiar series.
- Usage: Find another series \( b_n \) with clear divergence/convergence.
- Comparison: Use \( 0 \leq a_n \leq b_n \) or \( a_n \geq b_n \geq 0 \) logic.
It's an effective shortcut, bypassing longer verbal reasoning by leveraging prior established knowledge.
Other exercises in this chapter
Problem 14
Find the convergence set for the given power series. Hint: First find a formula for the nth term; then use the Absolute Ratio Test. $$ x+2^{2} x^{2}+3^{2} x^{3}
View solution Problem 14
Determine convergence or divergence for each of the series. Indicate the test you use. $$ \sum_{n=1}^{\infty} \frac{\sqrt{n+1}}{n^{2}+1} $$
View solution Problem 14
Use any test developed so far, including any from Section \(9.2\), to decide about the convergence or divergence of the series. Give a reason for your conclusio
View solution Problem 14
An explicit formula for \(a_{n}\) is given. Write the first five terms of \(\left\\{a_{n}\right\\}\), determine whether the sequence converges or diverges, and,
View solution