Problem 14
Question
In Problems 13-22, use any test developed so far, including any from Section 9.2, to decide about the convergence or divergence of the series. Give a reason for your conclusion. \(\sum_{k=1}^{\infty}\left(\frac{3}{\pi}\right)^{k}\)
Step-by-Step Solution
Verified Answer
The series converges because the common ratio \( \frac{3}{\pi} < 1 \).
1Step 1: Identify the Type of Series
The given series is \( \sum_{k=1}^{\infty}\left(\frac{3}{\pi}\right)^{k} \). This is a geometric series with common ratio \( r = \frac{3}{\pi} \).
2Step 2: Determine the Common Ratio
In a geometric series \( \sum_{k=1}^{\infty} ar^{k} \), the common ratio \( r \) is crucial for convergence. Here, \( r = \frac{3}{\pi} \).
3Step 3: Check the Condition for Convergence of Geometric Series
A geometric series converges if the absolute value of the common ratio \( |r| < 1 \). Calculate \( |\frac{3}{\pi}| \).
4Step 4: Calculate the Numerical Value
Calculate \( |\frac{3}{\pi}| \approx 0.9549 \). Since \( |\frac{3}{\pi}| < 1 \), the series converges.
5Step 5: Conclusion about Convergence
Since \( |\frac{3}{\pi}| < 1 \), the geometric series \( \sum_{k=1}^{\infty}\left(\frac{3}{\pi}\right)^{k} \) converges.
Key Concepts
Convergence of SeriesGeometric Series TestCommon Ratio in Series
Convergence of Series
The concept of convergence is fundamental when dealing with infinite series. An infinite series is essentially the sum of infinitely many terms. But instead of adding them up and going on forever, we need to decide whether the series will settle to a specific number as more terms are added or not. This is what we mean by convergence. The series converges if, by adding enough terms, we can get as close as we want to a certain value, called the sum of the series.
On the other hand, if no such value exists, or the series keeps growing endlessly, we say it diverges. Understanding this distinction helps determine if an infinite series has a meaningful sum. In our exercise, we determined the convergence of a geometric series using the common ratio and its properties. This ensures that even when dealing with infinitely many terms, we have a reliable method to find convergence.
On the other hand, if no such value exists, or the series keeps growing endlessly, we say it diverges. Understanding this distinction helps determine if an infinite series has a meaningful sum. In our exercise, we determined the convergence of a geometric series using the common ratio and its properties. This ensures that even when dealing with infinitely many terms, we have a reliable method to find convergence.
Geometric Series Test
The geometric series test is a quick and reliable way to determine whether a given geometric series converges or diverges. A geometric series is a series of the form \[ S = a + ar + ar^2 + ar^3 + \ldots \] where each term after the first is the result of multiplying the previous term by a fixed number, known as the common ratio, denoted by \( r \). The geometric series test states that a geometric series converges if the absolute value of the common ratio, \( |r| \), is less than 1. If \( |r| \geq 1 \), the series diverges. This principle is straightforward but very powerful.
- Check if \( |r| < 1 \) for convergence.
- If \( |r| \geq 1 \), the series will not converge.
Common Ratio in Series
In a geometric series, the common ratio \( r \) is a key element that tells us both the nature and behavior of the series. It is the constant factor by which each term of the series is obtained from the previous one. In mathematical terms, it is calculated as the ratio of any term to its preceding term. For geometric progression, once the first term \( a \) is known, every subsequent term can be determined if you know \( r \). For the series \( \sum_{k=1}^{\infty}\left(\frac{3}{\pi}\right)^{k} \), the common ratio is \( \frac{3}{\pi} \). Knowing the common ratio is essential for conducting a convergence test.
- The common ratio determines the rate of growth or decay of the series.
- When \( r \) is less than 1, in absolute terms, terms diminish, leading to potential convergence.
Other exercises in this chapter
Problem 14
In Problems 1-20, an explicit formula for \(a_{n}\) is given. Write the first five terms of \(\left\\{a_{n}\right\\}\), determine whether the sequence converges
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In Problems 1-18, find the terms through \(x^{5}\) in the Maclaurin series for \(f(x)\). Hint: It may be easiest to use known Maclaurin series and then perform
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\(\sum_{n=1}^{\infty} \frac{\sqrt{n+1}}{n^{2}+1}\)
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In Problems 13–30, classify each series as absolutely convergent, conditionally convergent, or divergent. $$ \sum_{n=1}^{\infty}(-1)^{n+1} \frac{1}{5 n^{1.1}} $
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