Problem 14
Question
In Exercises 11-18, find the standard form of the equation of the ellipse with the given characteristics and center at the origin. Vertices: \((0, \pm8); \quad\) foci: \((0, \pm4)\)
Step-by-Step Solution
Verified Answer
The standard form of the equation of the ellipse is \(\frac{y^2}{64} + \frac{x^2}{48} = 1\).
1Step 1: Identify Ellipse Orientation and Major Axis Length
Given the vertices \((0,\pm8)\), the major axis length is \(2a = 16\). This gives us \(a = 8\). Also, because the vertices are on the y-axis, we know the ellipse is vertical.
2Step 2: Identify the Distance from Center to Foci
The given foci are at \((0,\pm4)\) indicating that the distance from the center to either focus is \(c = 4\). This is half the distance between the two foci.
3Step 3: Calculate Minor Axis Length
Using the formula \(a^2 = b^2 + c^2\), we can find the length of the minor axis. Rearranging for \(b^2\) yields \(b^2 = a^2 - c^2 = 8^2 - 4^2 = 64 - 16 = 48\). Thus, the minor axis length is \(2b = 2\sqrt{48}=4\sqrt{3}\).
4Step 4: Write the Standard form of the Ellipse
Since this is a vertical ellipse, the standard equation should be written as \(\frac{y^2}{a^2} + \frac{x^2}{b^2} = 1\). Substituting the values of \(a\) and \(b\) that we found earlier, this becomes \(\frac{y^2}{64} + \frac{x^2}{48} = 1\).
Key Concepts
Standard FormMajor AxisMinor AxisFoci
Standard Form
The standard form of an ellipse is a mathematical equation that represents the shape and size of an ellipse with respect to the coordinate plane. An ellipse centered at the origin \(0,0\) can be expressed in two possible formats, depending on its orientation.
Understanding the type of ellipse can help you choose the correct standard form equation.
- If the ellipse is oriented horizontally (major axis along the x-axis), the standard form is: \(rac{x^2}{a^2} + rac{y^2}{b^2} = 1\)
- For a vertical orientation (major axis along the y-axis), the form is: \(rac{y^2}{a^2} + rac{x^2}{b^2} = 1\)
Understanding the type of ellipse can help you choose the correct standard form equation.
Major Axis
The major axis of an ellipse is the longest diameter that spans from one vertex across the ellipse to the opposite vertex. It essentially represents the 'width' or 'height' of the ellipse, depending on its orientation. Here, the major axis is always aligned with direction defined by its largest value.
In our given problem, the vertices \( (0, \pm 8)\) suggest that the ellipse is vertical with \(a = 8\), resulting in a major axis length of \(2a = 16\).
- For example, if the vertices are \( (0, \pm a)\), then the major axis is vertical.
- The length of the major axis is given by \(2a\), where \(a\) is the distance from the center to one vertex.
In our given problem, the vertices \( (0, \pm 8)\) suggest that the ellipse is vertical with \(a = 8\), resulting in a major axis length of \(2a = 16\).
Minor Axis
The minor axis of an ellipse is the shortest diameter, stretching from one side of the ellipse to the other through the center, perpendicular to the major axis. It represents the shorter side of the ellipse and is oriented across the narrowest part of the shape.
- For an ellipse with a vertical major axis, the minor axis will be horizontal.
- The length of the minor axis is denoted by \(2b\), where \(b\) is the distance from the center to the ellipse's edge along this axis.
Foci
The foci (singular: focus) of an ellipse are two special points located along the major axis and are crucial in defining the ellipse's shape. The distance between the center and each focus is represented by \(c\), and they help determine the ellipse's eccentricity, a measure of its deviation from being circular.
- The distance from the center to the foci, \(c\), is calculated using the formula \(a^2 = b^2 + c^2\).
- In this exercise, the foci are given at \( (0, \pm 4)\), indicating \(c = 4\).
Other exercises in this chapter
Problem 14
In Exercises 13-26, rotate the axes to eliminate the \(xy\)-term in the equation. Then write the equation in standard form. Sketch the graph of the resulting eq
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In Exercises 13-18, find the inclination \(\theta\) (in radians and degrees) of the line with a slope of \(m\). \(m = -2\)
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In Exercises 15-28, identify the conic and sketch its graph. \(r=\dfrac{3}{1-\cos\ \theta}\)
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