Problem 14
Question
In Exercises \(1-20\), plot the set of parametric equations by hand. Be sure to
indicate the orientation imparted on the curve by the parametrization.
$$
\left\\{\begin{array}{l}
x=2 \tan (t) \\
y=\cot (t)
\end{array} \text { for } 0
Step-by-Step Solution
Verified Answer
The curve of the parametric equations \(x = 2 \tan(t)\), \(y = \cot(t)\) for \(0
1Step 1: Understand the Parametric Equations
The given parametric equations are: \( x = 2 \tan(t) \) and \( y = \cot(t) \). These equations are functions of a parameter \( t \) where \( 0 < t < \frac{\pi}{2} \). Our task is to plot these equations on the coordinate plane and determine the orientation.
2Step 2: Determine the Range of Parameters
Since \( 0 < t < \frac{\pi}{2} \), we must determine the behavior of \( x \) and \( y \) as \( t \) approaches these limits:- As \( t \to 0^+ \), \( \tan(t) \to 0 \) and \( \cot(t) \to \infty \).- As \( t \to \frac{\pi}{2}^- \), \( \tan(t) \to \infty \) and \( \cot(t) \to 0 \).This helps to establish the direction in which the curve will be drawn. The curve starts from \((0, \infty)\) and moves towards \((\infty, 0)\).
3Step 3: Transform to Cartesian Coordinates
To better understand the relationship between \( x \) and \( y \), eliminate the parameter \( t \) by expressing \( \tan(t) \) and \( \cot(t) \) in terms of each other:\[ \tan(t) = \frac{1}{\cot(t)} \]Thus, substitute \( \tan(t) \) into the equation for \( x \):\[ x = 2 \left(\frac{1}{\cot(t)}\right) = \frac{2}{y} \]Rearrange to find the Cartesian relationship between \( x \) and \( y \):\[ xy = 2 \]
4Step 4: Sketch the Graph Based on Orientation
The Cartesian equation \( xy = 2 \) represents a rectangular hyperbola centered at the origin. To plot:1. Identify points using the parametric equations, for example: - If \( t = \frac{\pi}{4} \), then \( x = 2 \times 1 = 2 \) and \( y = 1 \), giving the point \((2,1)\).2. Use the Cartesian equation that confirms the points and direction.3. The orientation is from top-left to bottom-right and shows that the curve moves from \((0, \infty)\) to \((\infty, 0)\) in the first quadrant.
Key Concepts
Rectangular HyperbolaCartesian CoordinatesTrigonometric Functions
Rectangular Hyperbola
A rectangular hyperbola is a special type of hyperbola where the asymptotes are perpendicular to each other, intersecting at right angles. In our specific problem, the hyperbola is represented by the Cartesian equation \(xy = 2\). This form is central to the shape of a rectangular hyperbola.
- Understanding Orientation and Shape
The hyperbola has two distinct branches, which splay out towards infinity in opposite quadrants. Our rectangle is centered around the axes intersection, having symmetry about these lines.
The graph will be symmetrical in two quadrants, but in the case of our problem, it focuses on the first quadrant. - Graph Features
You'll notice that as \(x\) goes to infinity, \(y\) approaches zero and vice versa. The hyperbola does not cross its asymptotes, showing important characteristics in both Cartesian and parametric plots.
Cartesian Coordinates
Cartesian coordinates are a system that specifies each point uniquely in a plane using a pair of numerical coordinates. These are distances to two perpendicular-directed lines, which is the x-axis and the y-axis.
- Transforming Parametric Equations
Our task involves transforming parametric equations into a Cartesian form, to understand more about the curves and their interrelations. Starting with the equations \(x = 2 \tan(t)\) and \(y = \cot(t)\), we eliminated the parameter \(t\) to get \(xy = 2\).
The result is significant because it shows the relationship independent of \(t\) and places it in a framework many are familiar with, the Cartesian plane. - X and Y Axis Interactions
Understanding how \(x\) and \(y\) interact helps in predicting the values and the plot direction. In our example, the relationship dictates that an increase in \(x\) results in a proportional decrease in \(y\), and vice versa. This inverse proportionality is essential for graphing and mathematical representation.
Trigonometric Functions
Trigonometric functions are some of the most fundamental tools in mathematics, deeply connected with angles and ratios, in various applications from graphs to waves.
- Tangent and Cotangent Functions
In the given parametric equations, \(x = 2 \tan(t)\) uses the tangent function, which relates to similar triangles and circular functions. \(y = \cot(t)\) makes use of the cotangent function, which is the reciprocal of the tangent. They are thus complementary, showcasing their interplay over the interval where \(0 < t < \frac{\pi}{2}\).
These functions help translate an angle \(t\) into a meaningful curve when plotted onto the Cartesian system. Each value of \(t\) gives a point that collectively forms the curve. - Behavior within Allowed Range
As \(t\) nears the limit \(0\), \(tan(t)\rightarrow 0\) and \(cot(t)\to \infty\), indicating the curve starts at infinity on the y-axis. At approximately \(t = \frac{\pi}{2}\), \(tan(t)\rightarrow \infty\) and \(cot(t)\rightarrow 0\), reflecting the trajectory towards infinity on the x-axis.
This behavior allows us to understand the progressive motion and orientation of our curve, starting near and eventually moving apart as limits close in.
Other exercises in this chapter
Problem 13
Solve for the remaining side(s) and angle(s), if possible, using any appropriate technique. $$ a=16, \alpha=63^{\circ}, b=20 $$
View solution Problem 13
Plot the point given in polar coordinates and then give three different expressions for the point such that (a) \(r0\) and \(\theta \leq 0\) (c) \(r>0\) and \(\
View solution Problem 14
Find the component form of the vector \(\vec{v}\) using the information given about its magnitude and direction. Give exact values. \(\|\vec{v}\|=12\); when dra
View solution Problem 14
In Exercises \(1-20\), plot the graph of the polar equation by hand. Carefully label your graphs. Limaçon: \(r=1-2 \sin (\theta)\)
View solution