Problem 14
Question
In Exercises \(1-18,\) graph each ellipse and locate the foci. $$9 x^{2}+4 y^{2}=36$$
Step-by-Step Solution
Verified Answer
The graph of the ellipse is a shape centered at the origin (0,0) extending 3 units left and right along the x-axis and 2 units up and down along the y-axis. The foci of the ellipse are located at (-\(\sqrt{5}\),0) and (\(\sqrt{5}\),0).
1Step 1: Rewrite the equation in standard form
First, the given equation \(9x^2 + 4y^2 = 36\) should be rewritten in the standard form. This can be done by dividing each term by 36, resulting in the standard form equation \(\frac{x^2}{4} + \frac{y^2}{9} = 1\). From this equation, it can be determined that a^2 = 9 and b^2 = 4.
2Step 2: Determine the values of a and b
Since a^2 = 9 and b^2 = 4, the values of a and b can be found by taking the square root of these values. Therefore, a = 3 and b = 2.
3Step 3: Determine the position of the foci
The distance from the center (0,0) to each foci is given by the formula \(\sqrt{a^2 - b^2}\). In this case, \(\sqrt{9 - 4} = \sqrt{5}\). So, the positions of the foci are (-\(\sqrt{5}\),0) and (\(\sqrt{5}\),0).
4Step 4: Graph the ellipse
Begin by plotting the center of the ellipse at the origin (0,0). Then, draw the major axis from (-3,0) to (3,0) and the minor axis from (0,-2) to (0,2). Sketch the ellipse around these axes so it passes through the end points of the major and minor axes. Lastly, mark the positions of the foci (-\(\sqrt{5}\),0) and (\(\sqrt{5}\),0).
Key Concepts
Graphing EllipsesFoci of an EllipseStandard Form of an Ellipse EquationMajor and Minor Axes
Graphing Ellipses
Graphing an ellipse involves plotting an oval shape on a coordinate plane. To begin, we identify the center of the ellipse, which in this case is at the origin (0,0). We then need to determine the lengths of the major and minor axes. The major axis is the longest diameter, while the minor axis is the shortest.
To graph:
To graph:
- Locate the endpoints of the major axis based on the value of 'a' (half-length of the major axis), which is 3 in this example. Plot points at (-3, 0) and (3, 0).
- Determine the endpoints of the minor axis using 'b' (half-length of the minor axis), which is 2. Plot points at (0, -2) and (0, 2).
- Draw a smooth, oval shape that touches all four points, ensuring it is wider along the major axis and shorter across the minor axis.
Foci of an Ellipse
The foci of an ellipse are two special points located along the major axis. These points help define the shape of the ellipse. Every point on the ellipse is equidistant from the sum of the distances to the two foci.
In the equation, we find the foci using the formula \( \sqrt{a^2 - b^2} \) to calculate the distance from the center to each focus. With our values:
In the equation, we find the foci using the formula \( \sqrt{a^2 - b^2} \) to calculate the distance from the center to each focus. With our values:
- \( a^2 = 9 \) and \( b^2 = 4 \)
- The distance is \sqrt{9 - 4} = \sqrt{5} \approx 2.24
- The foci are thus located at (-\sqrt{5}, 0) and (\sqrt{5}, 0)
Standard Form of an Ellipse Equation
To properly graph an ellipse and find its foci, you'll need to convert its equation to the standard form. The standard form of an ellipse is:\(\frac{x^2}{a^2} + \frac{y^2}{b^2} = 1\)
This form clearly shows the relationship between the coefficients and the lengths of the axes. For the equation given, \( 9x^2 + 4y^2 = 36 \), we divide each term by 36 to simplify:\(\frac{x^2}{4} + \frac{y^2}{9} = 1\)
Recognizing this formula allows us to pinpoint the values of \( a^2 \) and \( b^2 \), indicating the squares of the semi-axes' lengths. This transformation is crucial for finding the geometric properties of the ellipse.
This form clearly shows the relationship between the coefficients and the lengths of the axes. For the equation given, \( 9x^2 + 4y^2 = 36 \), we divide each term by 36 to simplify:\(\frac{x^2}{4} + \frac{y^2}{9} = 1\)
Recognizing this formula allows us to pinpoint the values of \( a^2 \) and \( b^2 \), indicating the squares of the semi-axes' lengths. This transformation is crucial for finding the geometric properties of the ellipse.
Major and Minor Axes
The major and minor axes of an ellipse are fundamental for determining its shape and dimensions.
The major axis is the longest diameter running through the center and connecting two endpoints, spanning 2a. Meanwhile, the minor axis is the shortest, measuring 2b.
The major axis is the longest diameter running through the center and connecting two endpoints, spanning 2a. Meanwhile, the minor axis is the shortest, measuring 2b.
- The major axis is horizontal in this example, with endpoints at (-3, 0) and (3, 0). This reflects that \( a = 3 \).
- The minor axis is vertical, showing endpoints at (0, -2) and (0, 2), corresponding to \( b = 2 \).
Other exercises in this chapter
Problem 13
Find the focus and directrix of the parabola with the given equation. Then graph the parabola. $$ y^{2}-6 x=0 $$
View solution Problem 13
In Exercises 13-26, use vertices and asymptotes to graph each hyperbola. Locate the foci and find the equations of the asymptotes. $$\frac{x^{2}}{9}-\frac{y^{2}
View solution Problem 14
Find the focus and directrix of the parabola with the given equation. Then graph the parabola. $$ x^{2}-6 y=0 $$
View solution Problem 14
Use vertices and asymptotes to graph each hyperbola. Locate the foci and find the equations of the asymptotes. $$\frac{x^{2}}{16}-\frac{y^{2}}{25}=1$$
View solution