Problem 14
Question
In Exercises \(1-16,\) give a geometric description of the set of points in space whose coordinates satisfy the given pairs of equations. $$x^{2}+y^{2}+z^{2}=4, \quad y=x$$
Step-by-Step Solution
Verified Answer
The intersection is an elliptical cylinder centered on the line where \(x = y\), within the sphere of radius 2.
1Step 1: Identify the Shape Defined by the First Equation
The equation \(x^2 + y^2 + z^2 = 4\) represents a sphere centered at the origin \((0, 0, 0)\) with a radius of 2. This is because the general equation for a sphere is \((x - h)^2 + (y - k)^2 + (z - l)^2 = r^2\), where \((h, k, l)\) is the center and \(r\) is the radius.
2Step 2: Understand the Condition Given by the Second Equation
The equation \(y = x\) describes a plane in the three-dimensional space. In this plane, every point has its \(y\) coordinate equal to its \(x\) coordinate, creating a diagonal plane that passes through the origin and makes an angle of 45 degrees with both the \(x\)-axis and \(y\)-axis.
3Step 3: Combine the Equations to Find the Intersection
To find the points satisfying both conditions, we look for the intersection of the sphere and the plane. Substitute \(y = x\) into the sphere's equation: \[(x^2 + x^2 + z^2 = 4)\]which simplifies to \[(2x^2 + z^2 = 4)\].
4Step 4: Simplify and Describe the Intersection
The equation \(2x^2 + z^2 = 4\) represents an elliptical cylinder. This cylinder is centered on the \(z\)-axis with its axis along the line \(x = y\), as the section \(z = 0\) would give the ellipse \(2x^2 = 4\), or \(x^2 = 2\), showing the semi-major axis of length \(\sqrt{2}\) along the plane defined by \(x = y\).
Key Concepts
SpherePlaneElliptical Cylinder
Sphere
A sphere is one of the simplest three-dimensional shapes you can think of. It is perfectly round, like a basketball or a bubble.
In mathematical terms, a sphere is defined by the equation \((x - h)^2 + (y - k)^2 + (z - l)^2 = r^2\). This tells us everything about where the sphere is and how big it is:
In mathematical terms, a sphere is defined by the equation \((x - h)^2 + (y - k)^2 + (z - l)^2 = r^2\). This tells us everything about where the sphere is and how big it is:
- (h, k, l) is the center of the sphere. It's like the point right in the middle of the ball, or bubble.
- r is the radius, which is the distance from the center to any point on the sphere.
- The center of the sphere is at \((0, 0, 0)\), which is the origin of the coordinate system.
- The radius of the sphere is \(2\).
Plane
A plane in geometry is like a vast, flat sheet of paper that stretches endlessly in two directions. In three-dimensional space, a plane slices through the space like a knife through butter.
The equation \(y = x\) is a specific type of plane. Here's what it represents:
The equation \(y = x\) is a specific type of plane. Here's what it represents:
- Every point on this plane has its y value equal to its x value. This means if you pick any point with a certain x, it will have the same y coordinate.
- This plane forms a 45-degree angle with the x and y axes.
- It runs diagonally through the three-dimensional space.
Elliptical Cylinder
An elliptical cylinder is a type of cylinder where the base is not a circle, as in a regular cylinder, but an ellipse. You can think of it like squeezing a basketball into an oval shape and stretching it up into a cylindrical form.
In our exercise, we found an elliptical cylinder as the intersection of the sphere and plane. Here's the breakdown:
In our exercise, we found an elliptical cylinder as the intersection of the sphere and plane. Here's the breakdown:
- The cylindrical surface is defined by the equation\(2x^2 + z^2 = 4\).The meaning of this is:
- If you set \(z = 0\), then the elliptical base is structured as \(2x^2 = 4\). This simplifies to \(x^2 = 2\), giving the semi-major axis as \(\sqrt{2}\).
- The intersection creates a continuous loop, aligned with the line \(x = y\).
- This elliptical cylinder is perfectly aligned with the space where \(x = y\).
Other exercises in this chapter
Problem 14
Sketch the surfaces in Exercises \(13-44.\) CYLINDERS $$z=y^{2}-1$$
View solution Problem 14
Find the component form of the vector. The unit vector that makes an angle \(\theta=-3 \pi / 4\) with the positive \(x\)-axis
View solution Problem 15
In Exercises \(15-18\) , a. Find the area of the triangle determined by the points \(P, Q\) ,and \(R .\) b. Find a unit vector perpendicular to plane \(P Q R\)
View solution Problem 15
Direction angles and direction cosines The direction angles \(\alpha, \beta,\) and \(\gamma\) of a vector \(\mathbf{v}=a \mathbf{i}+b \mathbf{j}+c \mathbf{k}\)
View solution